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Topic: 🖤 (Read 194 times)

copper member
Activity: 1330
Merit: 899
🖤😏
October 26, 2023, 11:38:57 AM
#8
Why aren't you using a module like fastecdsa to perform the point subtraction, if I may ask?
I'm using this one :
Code:
import itertools
import secp256k1 as ice



with open('file1.txt', 'r') as f1, open('file2.txt', 'r') as f2:
   

    for line1, line2 in zip(f1, f2):
       
        x=  ice.pub2upub(str(line1.strip()))

        x2= ice.pub2upub(str(line2.strip()))

        res = ice.point_subtraction(x, x2).hex()
       
        result= ice.to_cpub(res)

        file3 = open('result.txt', 'a')
        file3.write(result + "\n")
        file3.close()
Posted here by mcdouglasx, it really makes things easier, however I wanted to have something that works on my phone, secp256k1_ice doesn't support mobile arch. Though I managed to go around my problem by doing the subtraction and other things in one script.

A few days ago as I was reading about P=NP, I came to a theory which states that there might be many solutions to solve an equation, and it's true, I have tried more than 10 methods to solve a key, but they all are complex, but I believe there is a fast method to solve a key. We just need to find it.
legendary
Activity: 1568
Merit: 6660
bitcoincleanup.com / bitmixlist.org
October 26, 2023, 04:36:03 AM
#6
Why aren't you using a module like fastecdsa to perform the point subtraction, if I may ask?
newbie
Activity: 17
Merit: 0
October 25, 2023, 01:06:24 AM
#5
if I want to subtract points t=j-d

------------------------------------------------------------------------------------------------------------------------
def subpoint (xj, yj, xd, yd):
   xt = (((yj*yj+2*yd*yj+yd*yd)*modinv (xd*xd-2*xd*xj+xj*xj,N2))-xd-xj)%N2
   yt = ((((yj+yd)*(xt-xd))*modinv(xd-xj,N2))+yd)%N2
   return (xt, yt)
-------------------------------------------------------------------------------------------------------------------------
modinv  modulo division
N2  = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
newbie
Activity: 1
Merit: 0
October 24, 2023, 10:53:33 PM
#4
Times are developing and technology is progressing! !
full member
Activity: 1050
Merit: 219
Shooters Shoot...
October 24, 2023, 10:45:45 PM
#3
I think I have such a script.

Did you finally get yours to work?
hero member
Activity: 667
Merit: 1529
September 22, 2023, 10:02:08 AM
#2
Then, we add these two points:
Code:
modulo=FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
px=79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798
py=483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8
qx=C6047F9441ED7D6D3045406E95C07CD85C778E4B8CEF3CA7ABAC09B95C709EE5
qy=1AE168FEA63DC339A3C58419466CEAEEF7F632653266D0E1236431A950CFE52A
c=(qy-py)/(qx-px)
c=(1AE168FEA63DC339A3C58419466CEAEEF7F632653266D0E1236431A950CFE52A-483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8)/(C6047F9441ED7D6D3045406E95C07CD85C778E4B8CEF3CA7ABAC09B95C709EE5-79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798)
c=d2a68e877f99fed44620881d385be245fade7e1c8be17cc7871c611855bf0ca1/4c4619154810c1c0daa4ddd8c73971d159db91705f2113ce51b9885e4578874d
c=d2a68e877f99fed44620881d385be245fade7e1c8be17cc7871c611855bf0ca1*ac946f7cd9ccebb8d59803e73c7d12aa395b2eb7e59a8ba119742df442fc6604
c=342119815c0f816f31f431a9fe98a6c76d11425ecaeaecf2d0ef6def197c56b0
rx=c*c-px-qx
rx=342119815c0f816f31f431a9fe98a6c76d11425ecaeaecf2d0ef6def197c56b0^2-79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798-C6047F9441ED7D6D3045406E95C07CD85C778E4B8CEF3CA7ABAC09B95C709EE5
rx=38f37014ce22fc29cf19f28a5ce4da091445536c3e2cff318ba07c2a3048f518-79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798-C6047F9441ED7D6D3045406E95C07CD85C778E4B8CEF3CA7ABAC09B95C709EE5
rx=bf350995d446407d79798ff48e5dcf0211a95691105ed65831adface1950d9af-C6047F9441ED7D6D3045406E95C07CD85C778E4B8CEF3CA7ABAC09B95C709EE5
rx=f9308a019258c31049344f85f89d5229b531c845836f99b08601f113bce036f9
ry=c*(px-rx)-py
ry=342119815c0f816f31f431a9fe98a6c76d11425ecaeaecf2d0ef6def197c56b0*(79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798-f9308a019258c31049344f85f89d5229b531c845836f99b08601f113bce036f9)-483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8
ry=342119815c0f816f31f431a9fe98a6c76d11425ecaeaecf2d0ef6def197c56b0*808ddc7d6783f89c0c6c130fd5e9b8dd4d6a3495aa5e8f28d3f090465a17dcce-483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8
ry=80ca558689d1ac796d8833e23848fbff62185de1db4777350901ce057fc9bb2a-483ADA7726A3C4655DA4FBFC0E1108A8FD17B448A68554199C47D08FFB10D4B8
ry=388f7b0f632de8140fe337e62a37f3566500a99934c2231b6cb9fd7584b8e672
As you can see, we have:
Code:
rx=f9308a019258c31049344f85f89d5229b531c845836f99b08601f113bce036f9
ry=388f7b0f632de8140fe337e62a37f3566500a99934c2231b6cb9fd7584b8e672
That matches 3*G:
Code:
04 F9308A019258C31049344F85F89D5229B531C845836F99B08601F113BCE036F9 388F7B0F632DE8140FE337E62A37F3566500A99934C2231B6CB9FD7584B8E672   3*G
copper member
Activity: 1330
Merit: 899
🖤😏
September 22, 2023, 07:40:45 AM
#1
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