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copper member
Activity: 1330
Merit: 899
🖤😏
October 10, 2023, 06:24:55 AM
#6
Do you mind sharing "your method" with the rest of us? I mean an actual algorithm like mine ( of course mine is half baked ), I'm more interested to know how you manage to halve 2**90 bits.
jr. member
Activity: 51
Merit: 107
October 10, 2023, 06:16:28 AM
#5
There is no possibility (sorry) that you can reduce for one key. if it could be possibility - then all btc has been worth nothing.


but......

as always we need math include in our conversation.


@NotATether wrote: "That's what I'd like to know as well - it does not seem feasible to condense a 129-bit range into a 90-bit range without accounting for all of the divisors and hence all the keys it will result."

and it is TRUE, or almost TRUE ->  "all of the divisors and hence all the keys it will result" we do not need "all". only part.


If you think about BSGS like normal BSGS , no -> you need modificate for BSGS inside BSGS as doubled

@NotATether wrote:
That's basically enterprise server kind of hardware, right?

Do those even support GPUs at all? I mean, maybe if it had enough PCIe lanes, you could fit a few NVIDIA gpus in there and get to work on CUDA. I guess it would have to be assembled manually and it would be very large.



Answer : Yes, enterprise server of hardware.

Do those even support GPUs at all? I mean, maybe if it had enough PCIe lanes, you could fit a few NVIDIA gpus in there and get to work on CUDA. I guess it would have to be assembled manually and it would be very large.

At the moment no: I have finished and tested for 2**90 bits , and it works.

I have no "knowledge" in GPU code. My testing was only test of my theory with succesfull.

If someone would like to work with me for it -> GPUS support , it will be nice.


the 1,5 TB ram , is calculated according my previous work

2**90 bit , has been solved in 73 hours with 128 cores.

Edit:

40 cores for main server
88 cores for workers
legendary
Activity: 1568
Merit: 6660
bitcoincleanup.com / bitmixlist.org
October 10, 2023, 05:15:49 AM
#4
for example puzzle 129 bit can be reducted to 2**90 bit -

by one key?

That's what I'd like to know as well - it does not seem feasible to condense a 129-bit range into a 90-bit range without accounting for all of the divisors and hence all the keys it will result.

you need about 1,5 TB ram.

That's basically enterprise server kind of hardware, right?

Do those even support GPUs at all? I mean, maybe if it had enough PCIe lanes, you could fit a few NVIDIA gpus in there and get to work on CUDA. I guess it would have to be assembled manually and it would be very large.
jr. member
Activity: 43
Merit: 1
October 10, 2023, 04:56:45 AM
#3


for example puzzle 129 bit can be reducted to 2**90 bit -




by one key?
jr. member
Activity: 51
Merit: 107
October 09, 2023, 08:43:01 AM
#2
about the limit - all depends of algorithm.

for example puzzle 129 bit can be reducted to 2**90 bit - then you can use modified BSGS and take sqrt(2**90) you have 2**45 bit

when I use word "modified" I mean designed special version of BSGS. with pollard rho it will not work.

you need about 1,5 TB ram.

copper member
Activity: 1330
Merit: 899
🖤😏
October 08, 2023, 08:17:02 AM
#1
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