Do you put back the each card after you draw it or not?
Nah, it won't. If you are playing poker then it will look like that, the difference is, 9 cards will draw.
I am not that good at math, but maybe you should check the numbers at http://www.durangobill.com/Poker_Probabilities_8_Cards.html (9 cards, no wildcard)
Just I can't tell how good those numbers also are.
I made a small test program calculating the odds to get the chance for (2 pairs) OR (3 of a kind) OR (Full House) OR (4 of a kind)
For hand size 5 I get the same result as the sum from http://www.durangobill.com/Poker_Probabilities_5_Cards.html, 7.03%
For hand size 9 the sum is 55.46% and my result is 67.39%
Another idea could be to try and count the number of possibilities for "worse than 2 hands" and see from there. However, I hope that its main page (http://www.durangobill.com/Poker.html) gives you some details and help you find out if your numbers are good.
Just I can't tell how good those numbers also are.
I made a small test program calculating the odds to get the chance for (2 pairs) OR (3 of a kind) OR (Full House) OR (4 of a kind)
For hand size 5 I get the same result as the sum from http://www.durangobill.com/Poker_Probabilities_5_Cards.html, 7.03%
For hand size 9 the sum is 55.46% and my result is 67.39%
Another idea could be to try and count the number of possibilities for "worse than 2 hands" and see from there. However, I hope that its main page (http://www.durangobill.com/Poker.html) gives you some details and help you find out if your numbers are good.
Thanks man! My answer is correct, it's 77%.
You should add all the probability of getting 1 pair, 2 pairs, 3 pairs until 4 pairs. Why? because the problem stated "atleast" means there are chances that 2pairs-4pairs will show when we draw 9 cards. This is my Prelims Exam so I just wanted to know if my answer is correct and yeah my solution is right!
This is a proof also that I studied and memorized it until I got home
Because some people might judge me.PS: LOCKED TOPIC
