Fair enough. The only situation where compressed keys would happen would be if they are generated by a non-Armory utility.
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###### Typing-friendly Base16 #####
# Implements "hexadecimal" encoding but using only easy-to-type
# characters in the alphabet. Hex usually includes the digits 0-9
# which can be slow to type, even for good typists. On the other
# hand, by changing the alphabet to common, easily distinguishable,
# lowercase characters, typing such strings will become dramatically
# faster. Additionally, some default encodings of QRCodes do not
# preserve the capitalization of the letters, meaning that Base58
# is not a feasible options
NORMALCHARS = '0123 4567 89ab cdef'.replace(' ','')
EASY16CHARS = 'asdf ghjk wert uion'.replace(' ','')
hex_to_base16_map = {}
base16_to_hex_map = {}
for n,b in zip(NORMALCHARS,EASY16CHARS):
hex_to_base16_map[n] = b
base16_to_hex_map[b] = n
def binary_to_easyType16(binstr):
return ''.join([hex_to_base16_map[c] for c in binary_to_hex(binstr)])
def easyType16_to_binary(b16str):
return hex_to_binary(''.join([base16_to_hex_map[c] for c in b16str]))
def makeSixteenBytesEasy(b16):
if not len(b16)==16:
raise ValueError, 'Must supply 16-byte input'
chk2 = computeChecksum(b16, nBytes=2)
et18 = binary_to_easyType16(b16 + chk2)
return ' '.join([et18[i*4:(i+1)*4] for i in range(9)])
def readSixteenEasyBytes(et18):
b18 = easyType16_to_binary(et18.strip().replace(' ',''))
b16 = b18[:16]
chk = b18[ 16:]
b16new = verifyChecksum(b16, chk)
if len(b16new)==0:
return ('','Error_2+')
elif not b16new==b16:
return (b16new,'Fixed_1')
else:
return (b16new,None)