Attempting to create a 2 of 3 multi-sig address in C++

#include
#include
#include
using namespace bc;
payment_address create_multi_signature_address(const data_chunk& calculated_script) {
// generate address from script.
short_hash sh2 = generate_ripemd_hash(calculated_script);

data_chunk raw_address;
raw_address.push_back((unsigned char)5);
for (unsigned char c : sh2)
raw_address.push_back(c);

hash_digest check_sum_digest = generate_sha256_hash(raw_address);

for (int i = sha256_digest_size-1; i >= sha256_digest_size-4; --i) {
raw_address.push_back(check_sum_digest[i]);
}

return payment_address(encode_base58(raw_address));
}

I am attempting to create a 2 of 3 multi-sig address in C++. The example I am using is from http://www.soroushjp.com/2014/12/20/bitcoin-multisig-the-hard-way-understanding-raw-multisignature-bitcoin-transactions/. I generate the script okay with the keys provided. But when I generate the address, it is wrong.

Briefly in psuedocode I am trying to do this:

We define intermediate with:
intermediate = 5 concat ( ripemd( sha256( script_bytes ) ) )

Then the address is encodeBase58( intermediate concat sha256( sha256( intermediate ) )[0..3] )

Is this psuedocode wrong? Here is the C++ code:

Code:

	hash_digest lh0 = generate_sha256_hash(calculated_script);
	
	data_chunk d1;
	for (int i = 0; i < lh0.size(); ++i)
		d1.push_back(lh0[i]);
	
	short_hash sh2 = generate_ripemd_hash(d1);
	data_chunk d3;
	data_chunk& addy= d3;
	d3.push_back((unsigned char)5);
	for (int i = 0; i < sh2.size(); ++i)
		d3.push_back(sh2[i]);
		
	hash_digest lh4 = generate_sha256_hash(d3);
	data_chunk d5;
	for (int i = 0; i < lh4.size(); ++i)
		d5.push_back(lh4[i]);
	
	hash_digest lh6 = generate_sha256_hash(d5);
	for (int i = 0; i < 4; ++i)
		d3.push_back(lh6[i]);
	
	calculated_address = encode_base58(addy);

I am looking at this page and the code I have here, they look the same. The addresses do not match in the end though.

Topic: Attempting to create a 2 of 3 multi-sig address in C++ (Read 1867 times)