Author

Topic: BSD detection (Read 9078 times)

newbie
Activity: 53
Merit: 0
August 13, 2010, 11:38:17 AM
#5
Incorporated into the CMake tree. No problems on Windows and FreeBSD.
founder
Activity: 364
Merit: 3077
August 12, 2010, 05:14:20 PM
#4
This is in SVN rev 130.  Check that it compiles right.

Code:
#if (defined(__unix__) || defined(unix)) && !defined(USG)
#include  // to get BSD define
#endif
#ifdef __WXMAC_OSX__
#ifndef BSD
#define BSD 1
#endif
#endif
newbie
Activity: 53
Merit: 0
August 12, 2010, 04:24:37 AM
#3
Quote

#if (defined(__unix__) || defined(unix)) && !defined(USG)
#include
#endif

Will that definitely cause BSD to be defined on Mac?


Don't know if Mac OS X is technically a BSD and I don't have access to a Mac, maybe someone else may test it.
If there are other Mac (and not BSD) specialties, then we'd need to check both for __WXMAC_OSX__ and BSD or detect these in some other way altogether.
founder
Activity: 364
Merit: 3077
August 11, 2010, 08:02:06 PM
#2
There is this piece of code in headers.h:

#ifdef __WXMAC_OSX__
#define __WXMAC__ 1
#define __WXOSX__ 1
#define __BSD__ 1
#endif
#endif

That code was a bad idea anyway, I'm deleting it.  Any Mac code should only use __WXMAC_OSX__, not __WXMAC__ or __WXOSX__, and we should stop using __BSD__.

Quote

#if (defined(__unix__) || defined(unix)) && !defined(USG)
#include
#endif

Will that definitely cause BSD to be defined on Mac?
newbie
Activity: 53
Merit: 0
August 11, 2010, 07:00:16 PM
#1
There is this piece of code in headers.h:

#ifdef __WXMAC_OSX__
#define __WXMAC__ 1
#define __WXOSX__ 1
#define __BSD__ 1
#endif
#endif


In my testing it's not caught on FreeBSD 8.1

I propose it be changed to:

#if (defined(__unix__) || defined(unix)) && !defined(USG)
#include
#endif


And then checks for BSD should be
#ifdef BSD
This is the recommended way of detecting BSD in the FreeBSD Porter's Handbook.

This change is already done in my CMake tree.
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