BTC Cryptography formular | Bitcointalksearch.org

BurtW

legendary

Activity: 2646

Merit: 1137

All paid signature campaigns should be banned.

Quote from: shrivelfire on December 17, 2017, 02:58:47 PM

You need to learn what are the possible addresses first. There are at least 256 types of addresses, and these are randomized.

Noob knows not what they are talking about.

There are 2¹⁶⁰ possible Bitcoin addresses.

There are 2²⁵⁶ possible public/private key pairs.

So, there are approximately 2²⁵⁶ / 2¹⁶⁰ = 2^{(256 - 160)} = 2⁹⁶ public/private key pairs per Bitcoin address.

shrivelfire

newbie

Activity: 8

Merit: 0

You need to learn what are the possible addresses first. There are at least 256 types of addresses, and these are randomized.

haltingprobability

member

Activity: 98

Merit: 26

Quote from: tromp on December 03, 2017, 10:50:07 AM

Quote from: aplistir on December 03, 2017, 05:47:40 AM

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^-70.

Assuming a lottery with 10^-8 odds of winning, the odds of winning a lottery 100 times in a row are 10^-800.

You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :-(

Last I checked, 0 = 0.

BurtW

legendary

Activity: 2646

Merit: 1137

All paid signature campaigns should be banned.

Quote from: tromp on December 03, 2017, 10:50:07 AM

Quote from: aplistir on December 03, 2017, 05:47:40 AM

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^-70.

Assuming a lottery with 10^-8 odds of winning, the odds of winning a lottery 100 times in a row are 10^-800.

You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :-(

His estimate of 100 lotteries is off by even more that that: the number of possible Bitcoin addresses is 2¹⁶⁰, not 2²⁵⁶.

Dr.Z

newbie

Activity: 16

Merit: 0

Address = RIPEMD160(SHA256(Public Key))

The public key is calculated from the private key using elliptic curve multiplication, which is irreversible: K = k * G where k is the private key, G is a constant point called the generator point and K is the resulting public key.

rddsd7

member

Activity: 224

Merit: 11

Quote from: tromp on December 03, 2017, 10:50:07 AM

Quote from: aplistir on December 03, 2017, 05:47:40 AM

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^-70.

Assuming a lottery with 10^-8 odds of winning, the odds of winning a lottery 100 times in a row are 10^-800.

You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :-(

Yeah.. I'm waaaaaaaaaaaayyyyyyyy off. but however there's a little possiblilty i guess.. so, i suggest if they would create the address by including the DATE+TIME, that would never repeat..

tromp

legendary

Activity: 990

Merit: 1108

Quote from: aplistir on December 03, 2017, 05:47:40 AM

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

Assuming 10^7 addresses in use, the odds of address collision are 10^7/2^256, or roughly 10^-70.

Assuming a lottery with 10^-8 odds of winning, the odds of winning a lottery 100 times in a row are 10^-800.

You're WAAAAAAAAAAAAYYYYYYYYYYYYYYYYYYYYYYYYYY off :-(

rddsd7

member

Activity: 224

Merit: 11

Quote from: aplistir on December 03, 2017, 05:47:40 AM

Quote from: rddsd7 on December 03, 2017, 02:10:59 AM

Hey,

Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??

Any possibility of repeating an address??

Yep. First you need to have a 256 bit random number, and then you convert it to an address.
The random number is supposed to be fully random, so it is not based on anything.

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

So you are better off playing lottery than trying to find an address collision

Thanks. That implies a lot..

aplistir

full member

Activity: 378

Merit: 197

Quote from: rddsd7 on December 03, 2017, 02:10:59 AM

Hey,

Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??

Any possibility of repeating an address??

Yep. First you need to have a 256 bit random number, and then you convert it to an address.
The random number is supposed to be fully random, so it is not based on anything.

By repeating an address, you mean address collision, where you generate an address that is already in use. That is possible, but the changes are so small that winning a lottery 100 times in a row is much more likely.

So you are better off playing lottery than trying to find an address collision

rddsd7

member

Activity: 224

Merit: 11

Hey,

Anyone knows the crypto formula for generating BTC address?? is it base on date+time...??

Any possibility of repeating an address??

Topic: BTC Cryptography formular (Read 531 times)