will try it on monday
Use this version: http://jsfiddle.net/a6a3ca0f/15/ 
Topic: Calculating amount of time to find a block (Read 1981 times)
Expected time to find a block is:
Not sure why you've done something different...
Hashrate as in gh/s? Because the number of days to mine a block seems wayyyy too big... http://jsfiddle.net/a6a3ca0f/10/Code:
Network Difficulty * 2^32 / hashrate = time in seconds to find a block
Network Difficulty = current bitcoin network difficulty target (39603666252)
2^32 = difficulty 1 share
hashrate = hashes per second (1 GH/s would be 1000000000)
Example of how long it would take to find a block for somebody with 1TH/s:
Code:
39603666252 * 2^32 / 1000000000000 = 170096451.35
You use the same formula to calculate expected earnings per day...
Code:
25 / 1968.7 = 0.01269874
My mistake was that I was calculating in gh/s, not h/s. It's now fixed: http://jsfiddle.net/a6a3ca0f/11/Expected time to find a block is:
Not sure why you've done something different...
Hashrate as in gh/s? Because the number of days to mine a block seems wayyyy too big... http://jsfiddle.net/a6a3ca0f/10/Code:
Network Difficulty * 2^32 / hashrate = time in seconds to find a block
Network Difficulty = current bitcoin network difficulty target (39603666252)
2^32 = difficulty 1 share
hashrate = hashes per second (1 GH/s would be 1000000000)
Example of how long it would take to find a block for somebody with 1TH/s:
Code:
39603666252 * 2^32 / 1000000000000 = 170096451.35
You use the same formula to calculate expected earnings per day...
Code:
25 / 1968.7 = 0.01269874
My mistake was that I was calculating in gh/s, not h/s. It's now fixed: http://jsfiddle.net/a6a3ca0f/11/
go to
https://bitcoinwisdom.com/bitcoin/difficulty
put in your hash amount it gives you what that should earn in a day. 1th should earn .0127 btc
a block is 25 btc divide it by the .0127 you get 1968.5 not quite right due to rounding but easy to do.
so a s-3 at 450gh should earn .005714 a day or 4375.218 chance for a block today.
I am running 8 s-3's and 1 asicminer prisma or 4.7th this is .05968btc in a day or a 418.9 chance at a block today
https://bitcoinwisdom.com/bitcoin/difficulty
put in your hash amount it gives you what that should earn in a day. 1th should earn .0127 btc
a block is 25 btc divide it by the .0127 you get 1968.5 not quite right due to rounding but easy to do.
so a s-3 at 450gh should earn .005714 a day or 4375.218 chance for a block today.
I am running 8 s-3's and 1 asicminer prisma or 4.7th this is .05968btc in a day or a 418.9 chance at a block today
Expected time to find a block is:
Not sure why you've done something different...
Hashrate as in gh/s? Because the number of days to mine a block seems wayyyy too big... http://jsfiddle.net/a6a3ca0f/10/Code:
Network Difficulty * 2^32 / hashrate = time in seconds to find a block
Network Difficulty = current bitcoin network difficulty target (39603666252)
2^32 = difficulty 1 share
hashrate = hashes per second (1 GH/s would be 1000000000)
Example of how long it would take to find a block for somebody with 1TH/s:
Code:
39603666252 * 2^32 / 1000000000000 = 170096451.35
You use the same formula to calculate expected earnings per day...
Code:
25 / 1968.7 = 0.01269874
Expected time to find a block is:
Not sure why you've done something different...
Hashrate as in gh/s? Because the number of days to mine a block seems wayyyy too big... http://jsfiddle.net/a6a3ca0f/10/ Code:
Network Difficulty * 2^32 / hashrate = time in seconds to find a block
Expected time to find a block is:
Not sure why you've done something different...
Code:
Network Difficulty * 2^32 / hashrate = time in seconds to find a block
What is the unit for the userHashrate supposed to be? As in, should it be defined as MH/s, GH/s, etc.
It's GH/s. I've also fixed it, I've changed it from difficulty to Blockchain.info's estimated total hashrate. I think at this point it's just a matter of whether or not the equation is correct, and I think it is. Here's an updated version: http://jsfiddle.net/a6a3ca0f/9/
What is the unit for the userHashrate supposed to be? As in, should it be defined as MH/s, GH/s, etc.
Hey everyone,
Here's an equation I developed that tells you how long it will take to find a block.
((100/((userHashrate/difficulty)*100))/144);
Explanation:
userHashrate/difficulty: chance the user finds a block
(userHashrate/difficulty)*100: converts the chance to a percentage (100>percentage>0)
100/((userHashrate/difficulty)*100): ...I forget what this does :/
((100/((userHashrate/difficulty)*100))/144): 144 blocks are found per day on average, this calculates how many days it'll take to find a block
Here's a working jsfiddle with the equation: http://jsfiddle.net/a6a3ca0f/6/. Click 'Run' in the top left to restart it.
The only possibly incorrect parts that I can think of are:
a) I forget why I divide it all by 100 in 100/((userHashrate/difficulty)*100). I'm pretty confident that it's correct to do so, but I can't remember what it does. I figured it out! It's how often you'll find a block (e.g. you will find one block every xx blocks mined).
b) Right now I divide the user's hashrate by the difficulty, not by the entire hashrate. Does this make it incorrect?
I'd appreciate feedback on these two problems and the equation in general.
Thanks,
busterroni
Here's an equation I developed that tells you how long it will take to find a block.
((100/((userHashrate/difficulty)*100))/144);
Explanation:
userHashrate/difficulty: chance the user finds a block
(userHashrate/difficulty)*100: converts the chance to a percentage (100>percentage>0)
100/((userHashrate/difficulty)*100): ...I forget what this does :/
((100/((userHashrate/difficulty)*100))/144): 144 blocks are found per day on average, this calculates how many days it'll take to find a block
Here's a working jsfiddle with the equation: http://jsfiddle.net/a6a3ca0f/6/. Click 'Run' in the top left to restart it.
The only possibly incorrect parts that I can think of are:
b) Right now I divide the user's hashrate by the difficulty, not by the entire hashrate. Does this make it incorrect?
I'd appreciate feedback on these two problems and the equation in general.
Thanks,
busterroni
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