Hi
I'm wondering how much cooling I need for my asics.
I got a little trailer 150 width x 240 length x 170 height. My plan is to but my asics into this to be able to transport it easily. I will cut a hole trough the wall for each asic so they will draw air from outside the trailer, therefore I expect it would get quite hot with 10-15 miners at 1kw each... But if I put a big exhaust at the top of the trailer wouldn't I spare quite a bit on cooling considering I'm only using power to get the hot air out and not cool it down/or suck it in...
Anyways if I'm doing my calculations with 10 miners it would be: 10000 * 3.412 =34120 BTU. So do you guys think I really need that much cooling (34120 BTU) for this or would it suffice with less considering the miners will always draw from cool air outside the trailer ? Any ideas are welcome
Sorry for my english
I'm living in norway so the outside temp is 20 +/- and -20-30 celsius at the winter.
I'm wondering how much cooling I need for my asics.
I got a little trailer 150 width x 240 length x 170 height. My plan is to but my asics into this to be able to transport it easily. I will cut a hole trough the wall for each asic so they will draw air from outside the trailer, therefore I expect it would get quite hot with 10-15 miners at 1kw each... But if I put a big exhaust at the top of the trailer wouldn't I spare quite a bit on cooling considering I'm only using power to get the hot air out and not cool it down/or suck it in...
Anyways if I'm doing my calculations with 10 miners it would be: 10000 * 3.412 =34120 BTU. So do you guys think I really need that much cooling (34120 BTU) for this or would it suffice with less considering the miners will always draw from cool air outside the trailer ? Any ideas are welcome
Sorry for my english
I'm living in norway so the outside temp is 20 +/- and -20-30 celsius at the winter.
Calculations are as follows:
Q(cfm)=(3.16 x P)/dT(f) or
Q(cfm)=(1.76 x P)/dT(c)
where Q(cfm) is the required flow in cubic feet per minute required to dissipate power P (expressed in watts) using the difference in temperature dT in either Fahrenheit (f) or Celsius (c)
for example if you wish a maximum 20 Celsius degree rise for 10kW worth of mining equipment:
Q=(1.76 x 10,000)/20
Q= 880 CFM
of course in the winter you will have a larger dT of up to 70 which means
Q=(1.76 x 10,000)/70
Q= 250 CFM
The size of your enclosure is not a consideration for this application. If you were trying to ventilate a bathroom, then you would need the dimensions in order to select an appropriate fan/blower.
These might work http://www.aeroflotech.com/ecatalog.php?fantype=residential&fid=65&s=In-Line+Duct+Fans# along the side walls of the trailer as near the top as possible.
