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Topic: Cooling solution - m³/h calculation - extractor (Read 234 times)

newbie
Activity: 31
Merit: 0
November 16, 2017, 06:04:36 AM
#1
Hey,

at the moment i'm cooling my mining farm with AC/s, but it takes a lot of electricity so i want to change it.

I want to build a wood box, as small as possible, and put all my miners in it.
On the top i want to put a strong extractor fan, and on the bottom fresh air holes with filter.

Something like this but bigger: https://www.youtube.com/watch?v=_qbLkivgxps

But now i got some questions.

1. The outside air temperature is the hole year around 90-110F (32-42C). Is it possible to cool the mining hardware dow?
I think yes, because the hardware is running hotter already, so it's just important to change the hole are in the box fast enough so it can't head up

2. The humidity is the hole year around 70-90%. Is it dangerous for the miners? i don't think so, because the air inside the box it hotter than the outside air, so no
condensation. The humidity don't get close to the hardware.

3. How can i calculate the power (m³/h) the extractor fan on the top of the box needs? I can calculate the hole volume of the wood box, but even then i have
to calculate something with the Watt and the heat to know how fast i have to take the air outside.

Thanks for every answer Smiley
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