Author

Topic: GO! (Puzzle fun :) ) (Read 1047 times)

legendary
Activity: 2212
Merit: 1199
March 21, 2014, 06:16:45 AM
#18
2014 = 0.001BTC -> 1 cheap beer
2016 = 0.001BTC -> 30 cheap beers

Yeees well Smiley but I will not hodl till 2016 Tongue I am not too good at hodling I am much better at spending Cheesy
Anyway this was very nice quiz and price doesn't really matter.

And I love the way it was solved as I love Python.
legendary
Activity: 1386
Merit: 1053
Please do not PM me loan requests!
March 20, 2014, 09:20:13 PM
#17
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley


I'd waste my time on this for BTC0.001

0.001 BTC is not a lot Smiley But I would say I undertand that it might be worth some time - but is less than a dollar Smiley how much time is worth? Smiley

Anyway did you solve it right already?

Regards and good luck
0.001 BTC is not a lot Smiley
Not in 2009, not in 2014.
But what about 2020? Wink

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this Cheesy

indeed I would like to see more too Smiley
0.001BTC is not even 1 cheap beer in my situation but quizzes like that are more interesting than 0.001BTC

2014 = 0.001BTC -> 1 cheap beer
2016 = 0.001BTC -> 30 cheap beers
legendary
Activity: 2212
Merit: 1199
March 20, 2014, 07:13:55 PM
#16
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley


I'd waste my time on this for BTC0.001

0.001 BTC is not a lot Smiley But I would say I undertand that it might be worth some time - but is less than a dollar Smiley how much time is worth? Smiley

Anyway did you solve it right already?

Regards and good luck
0.001 BTC is not a lot Smiley
Not in 2009, not in 2014.
But what about 2020? Wink

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this Cheesy

indeed I would like to see more too Smiley
0.001BTC is not even 1 cheap beer in my situation but quizzes like that are more interesting than 0.001BTC
legendary
Activity: 1386
Merit: 1053
Please do not PM me loan requests!
March 20, 2014, 04:33:55 PM
#15
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley


I'd waste my time on this for BTC0.001

0.001 BTC is not a lot Smiley But I would say I undertand that it might be worth some time - but is less than a dollar Smiley how much time is worth? Smiley

Anyway did you solve it right already?

Regards and good luck
0.001 BTC is not a lot Smiley
Not in 2009, not in 2014.
But what about 2020? Wink

Congrats to whoever decoded this. It was fun to try, I'd like to see more of this Cheesy
full member
Activity: 126
Merit: 100
March 20, 2014, 09:56:22 AM
#14
lol this was pretty cool but couldn't join in time  Huh
legendary
Activity: 3038
Merit: 1032
RIP Mommy
March 20, 2014, 05:53:13 AM
#13
Finally. Lock topic.
newbie
Activity: 2
Merit: 0
March 20, 2014, 05:48:28 AM
#12
Code:
#!/usr/bin/env python3
import fileinput

def main():
    grid = []
    for line in fileinput.input():
        line = line.rstrip()
        print('   ', end='')
        columns = []
        for char in line:
            if char == 'W':
                pair = (True, True)
            elif char == ';':
                pair = (False, True)
            elif char == '`':
                pair = (True, False)
            elif char == ' ':
                pair = (False, False)
            elif char == 'R':
                pair = (True, False)
            else:
                pair = (False, False)
            columns.append(pair)

        column = []
        for top, bottom in columns:
            column.append(top)
        grid.append(column)

        column = []
        for top, bottom in columns:
            column.append(bottom)
        grid.append(column)


    print('\x1b[0m')
    print('\x1b[47m\n')
    for column in grid:
        print('\x1b[47m    ', end='')
        for cell in column:
            print('\x1b[40m  ' if cell else '\x1b[47m  ', end='')
        print('\x1b[47m')
    print('\x1b[47m\n', end='')
    print('\x1b[0m')
    print('')


if __name__ == '__main__':
    try:
        main()
    except KeyboardInterrupt:
        print('')
        pass
legendary
Activity: 3472
Merit: 4794
March 20, 2014, 03:52:24 AM
#11
If I've got the pattern right:

  • In most cases a W represents 2 black pixels arranged vertically.
  • In most cases a ; represents 2 pixels arranged vertically where the top is white and bottom is black.
  • In most cases a ` represents 2 pixels arranged vertically where the top is black and bottom is white.
  • In most cases a blank space represents w white pixels arranged vertically.

Following those rules, I get what looks like a QR Code.  The positioning, alignment, and timing information is all properly represented. Additionally:

  • It appears to be a Version 3 (29x29) QR Code.
  • It seems to be using Level L (Low) error correction.
  • It appears to be using the (col%3=0) mask pattern.

I have not yet figured out what the bold R is meant to indicate.

As such, the resulting QR Code doesn't scan.

What I have so far looks like this:




full member
Activity: 168
Merit: 100
Lithium core developer
March 19, 2014, 12:16:35 PM
#10
It's not worth.....
legendary
Activity: 2212
Merit: 1199
March 18, 2014, 08:00:30 PM
#9
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley


I'd waste my time on this for BTC0.001

0.001 BTC is not a lot Smiley But I would say I undertand that it might be worth some time - but is less than a dollar Smiley how much time is worth? Smiley

Anyway did you solve it right already?

Regards and good luck
legendary
Activity: 1386
Merit: 1053
Please do not PM me loan requests!
March 17, 2014, 08:12:53 PM
#8
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley


I'd waste my time on this for BTC0.001
legendary
Activity: 2212
Merit: 1199
March 17, 2014, 08:10:24 PM
#7
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh

No one want to waste a time on this perhaps Smiley

legendary
Activity: 1386
Merit: 1053
Please do not PM me loan requests!
March 17, 2014, 08:09:32 PM
#6
Shocked I wonder noone has every solved it, Is it really that hard to solve Huh
This is as far as I can decode Sad
hero member
Activity: 714
Merit: 500
NEED CRYPTO CODER? COIN DEVELOPER? PM US FOR HELP!
March 17, 2014, 10:52:57 AM
#5
 Shocked I wonder noone has every solved it, Is it really that hard to solve Huh
hero member
Activity: 658
Merit: 500
March 03, 2014, 03:15:14 PM
#4
This is a bit too challenging for me, but it should not be too difficult for those who can program
legendary
Activity: 3472
Merit: 4794
March 03, 2014, 03:09:40 PM
#3

https://blockchain.info/address/12xRyf6DUkoh3e6Bd6vaXcY8JGhniGSq8w


  ;;;;;;;    ;  ; ;; ;; ;;;;;;;  
   W ;;; W `;`;W``W` W ; W ;;; W  
   W WWW W `` ``;` W`;;W W WWW W  
   W;;;;;W W W W ;`; ; W W;;;;;W  
   ;;;;; ;;;;;W`;;WW;`;;; ; ; ;  
    ```;;;W W   ;W;`W``;; `W;;`  
   ;; ;` ;`WW`;`;`;`;;;`  ;W`;;;  
      W W;``;W````WW`;``W`WW ;    
    `;;;W;;; ;;`; ; ; W```; ` WW  
   W W`;`;;`W``W`R`WW;  W ```W;`  
   W ;W `; W` `` W``; `WW;;W`    
   ;;;;;;; W`W  W WW `;W ; W ;;`  
   W ;;; W ;   `;W;W;``W;;;WW ;`  
   W WWW W W W`;;W;```;`;;W; ;;`  
   W;;;;;W W  ;W ;W;; W``;`WW;`  

For 0.01 BTC?

Not worth the effort.
legendary
Activity: 1512
Merit: 1012
March 03, 2014, 12:34:41 PM
#2











it's a trap.
full member
Activity: 181
Merit: 100
Diggit.io Admin
March 03, 2014, 09:06:46 AM
#1



   ;;;;;;;    ;  ; ;; ;; ;;;;;;;  
   W ;;; W `;`;W``W` W ; W ;;; W  
   W WWW W `` ``;` W`;;W W WWW W  
   W;;;;;W W W W ;`; ; W W;;;;;W  
   ;;;;; ;;;;;W`;;WW;`;;; ; ; ;  
    ```;;;W W   ;W;`W``;; `W;;`  
   ;; ;` ;`WW`;`;`;`;;;`  ;W`;;;  
      W W;``;W````WW`;``W`WW ;    
    `;;;W;;; ;;`; ; ; W```; ` WW  
   W W`;`;;`W``W`R`WW;  W ```W;`  
   W ;W `; W` `` W``; `WW;;W`    
   ;;;;;;; W`W  W WW `;W ; W ;;`  
   W ;;; W ;   `;W;W;``W;;;WW ;`  
   W WWW W W W`;;W;```;`;;W; ;;`  
   W;;;;;W W  ;W ;W;; W``;`WW;`  
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