Topic: higher difficulty acceptance from the node (Read 704 times)
ah. *cough* I am reading the code from my tv. bad excuse. -.-
I saw that, but then it seems that I understood it wrong. Proof of work means for me that it checks if the target is smaller than the last hash given. If I have a higher difficulty (and more leading zeroes) then it should be smaller than the last hash, or did I miss something?
Well in such case I think you probably only missed the lesson of C programming, where they were explaining the magic behind != symbol 
I saw that, but then it seems that I understood it wrong. Proof of work means for me that it checks if the target is smaller than the last hash given. If I have a higher difficulty (and more leading zeroes) then it should be smaller than the last hash, or did I miss something?
Were in AcceptBlock? It seems I can't find a check against it.
It's kind of hard to miss it, but well..
Code:
// Check proof of work
if (nBits != GetNextWorkRequired(pindexPrev, this))
return state.DoS(100, error("AcceptBlock() : incorrect proof of work"));
if (nBits != GetNextWorkRequired(pindexPrev, this))
return state.DoS(100, error("AcceptBlock() : incorrect proof of work"));
Were in AcceptBlock? It seems I can't find a check against it.
If one artificially raises the difficulty of the block and finds a valid hash for the higher difficulty, would it get accepted by the node?
No.It's in AcceptBlock function, in main.cpp
difficulty is not number of leading zeros, but a threshold number the block hash has to be less.
A block might satisfy a difficulty higher than currently required, and that would be accepted by others. The difficulty for next block does however not raise with that, its just waste of effort (or luck).
A block might satisfy a difficulty higher than currently required, and that would be accepted by others. The difficulty for next block does however not raise with that, its just waste of effort (or luck).
I searched around and found nothing in the forum, so here it is:
If one artificially raises the difficulty of the block and finds a valid hash for the higher difficulty, would it get accepted by the node?
Also, I can't wrap my head around the lesser difficulty in some mining pools. How are they accepted if they have lesser leading zeroes?
If one artificially raises the difficulty of the block and finds a valid hash for the higher difficulty, would it get accepted by the node?
Also, I can't wrap my head around the lesser difficulty in some mining pools. How are they accepted if they have lesser leading zeroes?
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