I posted that calculation a long time ago. I checked again a month ago, and it was still valid:
https://bitcointalksearch.org/topic/for-fun-the-lowest-block-hash-yet-29675Summary: Block 125,552 had a hash that would've been valid at at a difficulty of 36,000,000,000.
However, this has nothing to do with "breaking" sha256, or anything anything of the sort. It's just luck. Your statement would be like saying that "one time I rolled 10 dice and they all came up 1, so I must've come close to breaking the dice-rolling game." SHA256 is no more or less broken because of this.
cool, thanx for the info. 36,000,000,000 / today's difficulty * today's hash rate would be 274,630TH/s or 275PH/s.
Yes, I know it wouldn't even mean SHA256 was broken if the smallest hash found was actually 0 as shit happens
but it might reassure some of those less literate in mathematics that despite the effort of running a several TH/s operation for a serious amount of time, never ever there was a hash found to be smaller than
00000000000000001e8d6829a8a21adc5d38d0a473b144b6765798e61f98bd1d and not
0000000000000000000000000000000000000000000000000000000000000000
These people should just try to imagine how incredible big this number is and how far we are from 0. If the number were representing our distance to the center of the universe in nanometers, we would still be outside this universe. Far outside.
(If this smallest number found would be 0, it would be an indicator that somebody actually broke the algorithm as one might be lucky but chances this happens by pure luck are just not high enough that the algorithm could be considered save if this ever happens. The one who was lucky might know it was luck but all the cryptographers would assume it wasn't luck. It would be fun though
)
As mentioned above, even if we had touched the 0 once, this would raise concerns ans serious doubts in it being just luck