use
BN_hex2bn() and BN_nnmod() from
https://github.com/alexeyneu/BlockZero/blob/29ed505a211d14d4577012438cd8bec9d15f1272/connection/x.cpp#L287-L329
nnmod() hasn't been used there but it's straight thing to do.
Topic: how to find find % of publick key ? (Read 207 times)
it's np to do.
use
BN_hex2bn() and BN_nnmod() from (openssl's libcrypto)
https://github.com/alexeyneu/BlockZero/blob/29ed505a211d14d4577012438cd8bec9d15f1272/connection/x.cpp#L287-L329
nnmod() hasn't been used there but it's straight thing to do.
use
BN_hex2bn() and BN_nnmod() from
https://github.com/alexeyneu/BlockZero/blob/29ed505a211d14d4577012438cd8bec9d15f1272/connection/x.cpp#L287-L329
nnmod() hasn't been used there but it's straight thing to do.
Quote
but privkey has... so, pubkey has too
Not at all. I told you: the private key is the relation between the base point and your point, so "basePoint*privKey=yourPoint". Your public key does not have a remainder, because the private key exists only for a given base point, for a different point it will have completely different value. So, you can have a "remainder" only for a pair of points, like (basePoint;yourPoint), but not for a single point.What you talk abour ?
1026 MOD 64 is : 2
minus mod - 2
1024 MOD 64 is : 0 so, if you substrack 2 from pubkey you down you range fro 1:1024 to 1: 16 !!!
2 is remainder !! not base point
but no funtion for publick key !
how to find
noone has idea how to calculate mod of pubkey ?
i don't have time but play around with pycoin
Quote
ku 035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0 --json
{
"BTC_address": "12bahMGWAnSEYS3PKURvhScm8GmZhejY7t",
"BTC_address_segwit": "bc1qzxpx2mkf25ungac3yfkm9k7nfde3ympzxk6sqj",
"BTC_address_uncompressed": "16PvA358rPPhyirFyko9zRptKWL69EinoN",
"address": "12bahMGWAnSEYS3PKURvhScm8GmZhejY7t",
"address_segwit": "bc1qzxpx2mkf25ungac3yfkm9k7nfde3ympzxk6sqj",
"address_uncompressed": "16PvA358rPPhyirFyko9zRptKWL69EinoN",
"hash160": "1182656ec95539347711226db2dbd34b73126c22",
"hash160_uncompressed": "3b2e26fcd8888c57d99652937ac9e975e9f64dd7",
"input": "035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0",
"key_pair_as_sec": "035091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0",
"key_pair_as_sec_uncompressed": "045091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0ec29eeaf3d880 023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537",
"network": "Bitcoin mainnet",
"p2sh_segwit": "3EZXJeaZVsF1eFFXyLGHZ6CBn1ctwC9fHx",
"p2sh_segwit_script": "00141182656ec95539347711226db2dbd34b73126c22",
"public_pair_x": "36441801302806618484038906762766908306697395008217419414017649305421238822064",
"public_pair_x_hex": "5091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0",
"public_pair_y": "106819920335407981491505420347768958799539175113579525933191638145241450448183",
"public_pair_y_hex": "ec29eeaf3d880023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537",
"symbol": "BTC",
"y_parity": "odd"
}
{
"BTC_address": "12bahMGWAnSEYS3PKURvhScm8GmZhejY7t",
"BTC_address_segwit": "bc1qzxpx2mkf25ungac3yfkm9k7nfde3ympzxk6sqj",
"BTC_address_uncompressed": "16PvA358rPPhyirFyko9zRptKWL69EinoN",
"address": "12bahMGWAnSEYS3PKURvhScm8GmZhejY7t",
"address_segwit": "bc1qzxpx2mkf25ungac3yfkm9k7nfde3ympzxk6sqj",
"address_uncompressed": "16PvA358rPPhyirFyko9zRptKWL69EinoN",
"hash160": "1182656ec95539347711226db2dbd34b73126c22",
"hash160_uncompressed": "3b2e26fcd8888c57d99652937ac9e975e9f64dd7",
"input": "035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0",
"key_pair_as_sec": "035091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0",
"key_pair_as_sec_uncompressed": "045091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0ec29eeaf3d880 023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537",
"network": "Bitcoin mainnet",
"p2sh_segwit": "3EZXJeaZVsF1eFFXyLGHZ6CBn1ctwC9fHx",
"p2sh_segwit_script": "00141182656ec95539347711226db2dbd34b73126c22",
"public_pair_x": "36441801302806618484038906762766908306697395008217419414017649305421238822064",
"public_pair_x_hex": "5091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0",
"public_pair_y": "106819920335407981491505420347768958799539175113579525933191638145241450448183",
"public_pair_y_hex": "ec29eeaf3d880023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537",
"symbol": "BTC",
"y_parity": "odd"
}
https://pycoin.readthedocs.io/en/latest/search.html?q=modulo&check_keywords=yes&area=default
bit https://bit.dev/ is also good
btw not sure if this helps but i ust got the x value (lttle endian) as int and did
Quote
ku 36441801302806618484038906762766908306697395008217419414017649305421238822064/odd
Code:
input : 364418013028066184840389067627669083066973950082174194140176493054\
21238822064/odd
network : Bitcoin mainnet
symbol : BTC
public pair x : 36441801302806618484038906762766908306697395008217419414017649305421238822064
public pair y : 106819920335407981491505420347768958799539175113579525933191638145241450448183
x as hex : 5091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0
y as hex : ec29eeaf3d880023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537
y parity : odd
key pair as sec : 035091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0
uncompressed : 045091541f5851647a93df0c14152a4516169b5bd6acf793dee8c9dfa27710e4b0\
ec29eeaf3d880023f13d2608200ec283c971081ee88ec05247bf6d65b57e8537
hash160 : 1182656ec95539347711226db2dbd34b73126c22
uncompressed : 3b2e26fcd8888c57d99652937ac9e975e9f64dd7
Bitcoin address : 12bahMGWAnSEYS3PKURvhScm8GmZhejY7t
Bitcoin address uncompressed : 16PvA358rPPhyirFyko9zRptKWL69EinoN
Bitcoin segwit address : bc1qzxpx2mkf25ungac3yfkm9k7nfde3ympzxk6sqj
p2sh segwit : 3EZXJeaZVsF1eFFXyLGHZ6CBn1ctwC9fHx
corresponding p2sh script : 00141182656ec95539347711226db2dbd34b73126c22
it gave that
Quote
but privkey has... so, pubkey has too
Not at all. I told you: the private key is the relation between the base point and your point, so "basePoint*privKey=yourPoint". Your public key does not have a remainder, because the private key exists only for a given base point, for a different point it will have completely different value. So, you can have a "remainder" only for a pair of points, like (basePoint;yourPoint), but not for a single point.What you talk abour ?
1026 MOD 64 is : 2
minus mod - 2
1024 MOD 64 is : 0 so, if you substrack 2 from pubkey you down you range fro 1:1024 to 1: 16 !!!
2 is remainder !! not base point
but no funtion for publick key !
how to find
noone has idea how to calculate mod of pubkey ?
Quote
but privkey has... so, pubkey has too
Not at all. I told you: the private key is the relation between the base point and your point, so "basePoint*privKey=yourPoint". Your public key does not have a remainder, because the private key exists only for a given base point, for a different point it will have completely different value. So, you can have a "remainder" only for a pair of points, like (basePoint;yourPoint), but not for a single point.What you talk abour ?
1026 MOD 64 is : 2
minus mod - 2
1024 MOD 64 is : 0 so, if you substrack 2 from pubkey you down you range fro 1:1024 to 1: 16 !!!
2 is remainder !! not base point
but no funtion for publick key !
how to find
Quote
but privkey has... so, pubkey has too
Not at all. I told you: the private key is the relation between the base point and your point, so "basePoint*privKey=yourPoint". Your public key does not have a remainder, because the private key exists only for a given base point, for a different point it will have completely different value. So, you can have a "remainder" only for a pair of points, like (basePoint;yourPoint), but not for a single point.
even if it were possible, it would be indistinguishable from the partition, i.e. the private key would be out of range.
The modulo operation makes no sense here.
You can multiply a point on an elliptic curve by a number and by extension you can divide it by a number but a point (that is x and y coordinates) doesn't have a remainder!
You can multiply a point on an elliptic curve by a number and by extension you can divide it by a number but a point (that is x and y coordinates) doesn't have a remainder!
but privkey has... so, pubkey has too
The modulo operation makes no sense here.
You can multiply a point on an elliptic curve by a number and by extension you can divide it by a number but a point (that is x and y coordinates) doesn't have a remainder!
You can multiply a point on an elliptic curve by a number and by extension you can divide it by a number but a point (that is x and y coordinates) doesn't have a remainder!
Publick key - 035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0
how to find 035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0 % 7890161 ?
% - modulo
Br
how to find 035091541F5851647A93DF0C14152A4516169B5BD6ACF793DEE8C9DFA27710E4B0 % 7890161 ?
% - modulo
Br
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