I already answered this question in OP's other thread here:
https://bitcointalksearch.org/topic/m.58946721.
The string OP has given:
tb1qzqtu25qsue0a5pp3hg8lkftclf8ds
Converted to binary and grouped in to 11 digits:
01110100011 00010001100 01011100010 11110100111 00010111010 00111010100 11001000110 10101110001 01110011011 10101011001 01001100000 11000010011 01010111000 00111000000 11001101101 00001100111 00111000011 01100011010 11011001100 11101000110 00110110110 00110011000 11100001100 10001110011
Convert each grouping to decimal:
931 140 738 1959 186 468 1606 1393 923 1369 608 1555 696 448 1645 103 451 794 1740 1862 438 408 1804 1139
Map to the BIP39 wordlist:
inner bag fox visual blanket dentist silver purchase inflict private equal second finish day soap artefact debris globe sunset trip cycle credit thunder mobile
I don't see why you would do this over just memorizing a normal 12 word BIP39 seed phrase, though. If you want to use Core, then you can just use something like Ian Coleman to extract the individual private keys from your BIP39 phrase to import in to Core. Much better to do that than to come up with your own encoding system like this. And once again, relying on your memory as the only way to access your coins is an awful idea.
click "Show entropy details" checkbox, insert the seed and get the "BIP39 Mnemonic" in the field below.
Ian Coleman's tool accepts binary, base 6, decimal, hexadecimal, or a pack of cards, as entropy. It will not accept arbitrary strings as OP has suggested using.