Well, I don't know anything about LABY. Why don't you write some code from the ground up?
Here's a good project for you: Write a program that builds a 2d road network using recursion, by growing roads one branch at a time, creating a road topology that is reasonable and authentic looking, including urban areas, suburbs, and rural areas. Print the topological data out to a Renderman RIB file, and use the freely available 3Delight renderer to render the network.
Use this paper as inspiration, but do not adopt the L-system methodology: http://graphics.ethz.ch/Downloads/Publications/Papers/2001/p_Par01.pdf
Topic: Learning Python part 3 (Read 1198 times)
What error?
The solutions you offered are written correctly.
But it seems the game LABY does not have a complete python library or just cannot read them.
Gives me a track... syntax... on line depending on where I placed the code.
What error?
Are we dealing with floats?
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
Are we dealing with floats?
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
both this solutions give me an error within laby
using if and or gives me and error
The best thing was to do
if x == 1:
left()
if x == 2:
right()
main()
Are we dealing with floats?
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
In such a case, perhaps you meant something like this:
while x >= 3 and x < 4:
Good effort :-) I'm trying to learn java in my spare time. Wanna start making some apps for my phone :-P might finally be able yo get all my ahitty c# games playable on a phone :-D
You can use "while x in [3, 4]"
this probably belongs in a python developers forum? 
Disregard the previous solution and thanks for the feedback...
I will just remove x == 3 - 4 all together,
since I have the range from 1 to 4
if it does not generate 1 or 2 in the random number it will go back to function to check on other conditions and just move accordingly.
I will just remove x == 3 - 4 all together,
since I have the range from 1 to 4
if it does not generate 1 or 2 in the random number it will go back to function to check on other conditions and just move accordingly.
What I find odd is that the ant is behaving the way I want it to behave. Meaning that if random outputs 3 or 4 it moves forward.
I guess I should do x == none instead. To break the loop
Just trying to figure out why the ant behaves as intended.
Edit: figured it out
X >= 3
That way %50 it will check to move forward
And the rest of the other time it will try left or right
The behavior can be altered by increasing/decreasing the range of the random numbers
I guess I should do x == none instead. To break the loop
Just trying to figure out why the ant behaves as intended.
Edit: figured it out
X >= 3
That way %50 it will check to move forward
And the rest of the other time it will try left or right
The behavior can be altered by increasing/decreasing the range of the random numbers
Where is robot.py?
Quote
while x == 3 - 4:
Do you really mean while x==-1?Robot.py comes within LABY if you see the gist comment; the link to laby is there.
Hmm since x is a random generated number I thought I was telling pythin if x equals 3 or 4 then go back to function...
Then it should be:
while x == 3 or x == 4:
In your code, it should be obvious that 3 - 4 is an expression which subtracts 4 from 3. Furthermore, - has greater precedence than ==, thus the expression 3 - 4 evaluates before the equality operator. Finally, 3 and 4 are constants, thus the interpreter can evaluate them at compile time, if it does do a mini-compile upon running, and convert them into the value -1.
Now, let's look at some aspects of precedence and predicates.
If the == operator had greater precedence than the - operator (which it doesn't), then we would have a statement which attempts to subtract 4 from the value of True or False. If coding in C, which you are not, the equality expression would evaluate to 0 or 1. Interestingly, we could do this:
while((x == 3) - 4) {
Which would evaluate to -3 if x did indeed equal 3.
Where is robot.py?
Quote
while x == 3 - 4:
Do you really mean while x==-1?Robot.py comes within LABY if you see the gist comment; the link to laby is there.
Hmm since x is a random generated number I thought I was telling pythin if x equals 3 or 4 then go back to function...
Edit : if u run ubuntu desktop you can install it from the software center.
Where is robot.py?
Quote
while x == 3 - 4:
Do you really mean while x==-1? So are you learning to code, or playing a game? or both?
Learning to code
Solving the LABY maze challenges was to test what I have learned so far.
So are you learning to code, or playing a game? or both?
Well i'm half way through LPTHW at this point the book wants me to memorize symbols and their functions and practice.
So to take a break from the usual study drill I decided to make an automata to run on top of something called.
LABY a game it seems to solve the maze part of the problems roughly about 4 of them.
You can review my attempt at the game here:
https://gist.github.com/vitepython/6472113
Note: Op is not a programmer and is learning this as a hobby.
So to take a break from the usual study drill I decided to make an automata to run on top of something called.
LABY a game it seems to solve the maze part of the problems roughly about 4 of them.
You can review my attempt at the game here:
https://gist.github.com/vitepython/6472113
Note: Op is not a programmer and is learning this as a hobby.
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