the byte 50 + required Keys
pubkey1 count
pubkey1
(...)
byte 50 + pubkey count
byte ae
example (2 of 3)
52 33 035b641b667aded965c2f7c2be17c736e6d960e3316a5c2d46ccacf6ff9fa87edd 33 02b94370211403cac9378dfbc414df44842523e120e5301d3d593a370cf6b9fb38 33 0260b26aa4d0e921f322bcad0f04c1bcd475a70e4553f3bda007eb1534081ead46 53 ae
i made a mistake
the pubkey count is in hex
so is 21, not 33
52 21 035b641b667aded965c2f7c2be17c736e6d960e3316a5c2d46ccacf6ff9fa87edd 21 02b94370211403cac9378dfbc414df44842523e120e5301d3d593a370cf6b9fb38 21 0260b26aa4d0e921f322bcad0f04c1bcd475a70e4553f3bda007eb1534081ead46 53 ae