Author

Topic: [MERKLE BINGO] Post-Fork Satori Roll (Read 297 times)

copper member
Activity: 2562
Merit: 2510
Spear the bees
April 19, 2019, 11:39:44 PM
#4
Dropping this in lieu of a sale thread. Will attempt bingo with some Bitcoin Penny coppers soon!
copper member
Activity: 2562
Merit: 2510
Spear the bees
April 18, 2019, 12:38:40 PM
#3
Bump.

Price reduced to 0.009 BTC / card.

legendary
Activity: 2114
Merit: 1403
Disobey.
April 16, 2019, 08:22:53 AM
#2
Not interested in a full Satori roll right now, but this new format looks interesting. Bingotime. lol
If some smaller items are up for grabs with this Merkle Bingo (the name makes me chuckle everytime) method, I would try it.

Btw, chances of no winner in round 1 (based on the 21% winning chance per card) are ~2.3%
copper member
Activity: 2562
Merit: 2510
Spear the bees
April 15, 2019, 11:46:21 PM
#1

BINGO TIME: The prize is a brilliant post-fork satori roll.


I wanted to test out this new sale format. Might change numbers around later, but this allows for more versatile ticket totals in raffles!



Bingo Cards:



Available Cards: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, a, b, c, d, e, f]



Price per Card: 0.009BTC
Card Limit: None, buy them all if you'd like!
Shipping: Included Worldwide. Ships from Canada and winner is liable for any import/VAT costs.
Pay To: > 3DoHyNjRtPkB9nFihfSKwY74VfmR1qKpJ3 <



How we'll play

Don't be scared if you played Blockchain Bingo before and it took forever: this is a much quicker-paced version!

Once all tickets are selected and paid-for, I will select a block to begin our Bingo game! The selected block and all subsequent blocks will be used to determine the winner.

Rather than being based on the last character of the block hash, we will use the merkle root of (future) selected blocks.
If 6 or more of a given character are in the merkle root, then that respective character is crossed off on your bingo card.
Once your bingo card has a line of 4 crossed characters (vertical, horizontal, diagonal) then you win!
For example, if there are 6 or more c characters in the merkle root, everyone crosses off c on their bingo card.

Tiebreak Event: In the event that two or more users win on the same block, the last character of the merkle root of the block determines the winner.
The winning card closest to the character wins.* This tiebreak event repeats until a winner is decided.

* in a tiebreak event, "closest characters" wrap around, meaning that 0 is one away from f and vice versa. 1 would be two away from f, and three away from e


Good luck!


Trivia: the chance for a character to occur six or more times is roughly 21%. When we consider all the bingo cards, this is a very likely chance for a round one victory!

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