Author

Topic: Multiple transaction fees for one order? (Read 134 times)

newbie
Activity: 11
Merit: 0
December 11, 2017, 09:53:09 PM
#3
That explains it! Thank you very much.

I thought that the fee is taken from the total amount that you are paying each time with each buyer.

Thanks again!
legendary
Activity: 2772
Merit: 3282
December 11, 2017, 09:44:20 PM
#2
No, you wouldn't have to pay multiple trading fees by buying from different buyers. For your Bitstamp example, I'll use 0.25% as the fee since that's the fee for trades under $20,000. You'd pay a 0.25% fee on the 0.5 BTC you bought from buyer 1, and a 0.25% fee on the 0.5 BTC you bought from buyer 2. So you'd get 0.25% taken from 1 BTC, as that was the total. The same would occur with a single transaction. The fee is a percentage of the amount you bought from the seller, not the total amount you want to buy.
newbie
Activity: 11
Merit: 0
December 11, 2017, 09:40:29 PM
#1
First, please forgive me if this is a super basic question. I used to buy my bitcoin from a local non exchange website (like coinbase that charges a flat fee).

Now I am looking to buying a whole 1 BTC from an exchange...but I have noticed on the order book that no one sells a whole bitcoin....\


does that mean that I have to buy my bitcoin in multiple transactions from multiple sellers?

Am I paying a fee everytime I make a transaction?

Let me explain in a simplistic example:

I want to buy 1 BTC

on Bitstamp, there are 2 sellers , each selling 0.5 BTC

does that mean that when I put my order to buy 1BTC, I ill get charged 2x trading fees since I am practically buying from two sellers?

Please take easy on me Im not used to this lol

Thank you in advance!
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