The Nonce of the block is: 70755497
Converted to hex it is: 4a7a43 ---> 6 Bytes instead of 8
Converted to hex it is: 4a7a43 ---> 6 Bytes instead of 8
Something's gone wobbly here.
The nonce of 70755497 is stored in the block header as "a9a43704" (4 bytes). This is precisely the 4-byte
My quick Python 3 check:
Code:
>>> (70755497).to_bytes(4, byteorder='little')
b'\xa9\xa47\x04'
>>> ''.join(format(byte, '02x') for byte in _)
'a9a43704'
If I now try to double SHA this kind of block with only 6 Bytes for the nonce I don't get a correct result for the block hash.
If've tried to put "00" bevor and behind the digits, but that doesn't solve the problem.
If've tried to put "00" bevor and behind the digits, but that doesn't solve the problem.
In this
Code:
import hashlib
def sha256(message):
return hashlib.sha256(message).digest()
version = '03000000'
previous_hash = 'e63b16136d61d94bcda2b6609fad58c217dd9a73be7310050000000000000000'
merkle_root = '213f7741f14eb9b972b44402647b20f1e2705c73416dfb35d5f0b6fca86eb8e9'
time = '098d0656'
bits = 'ba871218'
nonce = 'a9a43704'
header = ''.join([version, previous_hash, merkle_root, time, bits, nonce])
hash_bytes = sha256(sha256(bytes.fromhex(header)))
print(''.join(format(byte, '02x') for byte in reversed(hash_bytes)))
Edit: Corrected big-endian to little-endian throughout. Cheers Danny.
