There is no big question here!
The MEMPOOL is just an explorer to view waiting transactions and confirmed ones.
MEMPOOL as in memory pool.
You place a transaction it appears there and that transaction is placed at a depth depending on your fee rate.
Blocks are mined within 8 to 14 minutes depending on the difficulty level at that particular point.
The reason 2 blocks can't be left is because you are virtually saying everyone abandoned the network. Because blocks must be mined as long as transactions are created...
Topic: Only 2 Blocks Nai been Remained In Mempool. (Read 71 times)
There can't be 2 blocks left in the memepool.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
As you can see from the image only two blocks were left that day. Don't worry when I create the thread in the main board you will see the answers other people gave me in the PM discussion. And the thing happened on Sunday. I just want to know more from here.It only means more people used smaller fees in those blocks that's why the fee rate is low.
Blocks are not found in the mempool, only transactions can be found in the mempool. What you are seeing right now is representation of transactions arrange according to their fee ranges. If someone see the mempool to be that empty and pay high fees, you will see the arrange blocks will reposition the fees again and it happens continuously when there are more transactions with high prioritize or low fees.
NB: There is difference between mempool as transaction explorer and Bitcoin node mempool.
Mempool.space is a Bitcoin explorer where you can scan and view different transaction ID while Bitcoin mempool is where transactions that are waiting for comfirmations stays before they get included in the the block and there is not such thing like general mempool, mempool.space doesn't represent the entire Bitcoin mempool, each Bitcoin node has their own respective mempool(memory pool) of transactions.
Make I do small elaboration.
Mempool.space na Bitcoin transaction explorer like them https://blockchair.com, https://blockstream.info, https://bitcoinexplorer.org and many more but what made mempool explorer unique is because of their visual representation of transactions in blocks according to their fee structure in sat/vbytes.
When you send a Bitcoin transactions, the node are the ones that pick your transaction waiting for miners to comfirm them and this transaction wait in each memory pool of the nodes, this transactions stay there until miners comfirm them which is going to be depending on the fee size sat/vbytes you pay for your transaction. Once the transaction is mined and comfirmed by the miners, the confirmed transaction is propagated back to different nodes as a copy to their memory pool.
Each node has history of transactions from the Genesis block to the current comfirm blocks of transactions but some node do prune their node to have more space in their memory because right now, blocsk of transaction from Genesis block is more than 500 gigabytes but there are some nodes that has these blocks of transactions in their memory pool. This has answered your last question.
To your first question again!
What you need to know is mempool.space(explorer) ≠ general mempool of transactions, each Bitcoin node has their own mempool(memory space for transactions for both comfirmed and unconfirmed). However, mempool.space another Bitcoin node run by someone providing the same service of explorer.
My recommendation, if you have a laptop device with atleast 700gb to a terabytes, download Bitcoin core to see how fun is running a Bitcoin node, you will understand it better in practical form.
There can't be 2 blocks left in the memepool.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
As you can see from the image only two blocks were left that day. Don't worry when I create the thread in the main board you will see the answers other people gave me in the PM discussion. And the thing happened on Sunday. I just want to know more from here.It only means more people used smaller fees in those blocks that's why the fee rate is low.
Blocks are not found in the mempool, only transactions can be found in the mempool. What you are seeing right now is representation of transactions arrange according to their fee ranges. If someone see the mempool to be that empty and pay high fees, you will see the arrange blocks will reposition the fees again and it happens continuously when there are more transactions with high prioritize or low fees.
NB: There is difference between mempool as transaction explorer and Bitcoin node mempool.
Mempool.space is a Bitcoin explorer where you can scan and view different transaction ID while Bitcoin mempool is where transactions that are waiting for comfirmations stays before they get included in the the block and there is not such thing like general mempool, mempool.space doesn't represent the entire Bitcoin mempool, each Bitcoin node has their own respective mempool(memory pool) of transactions.
There can't be 2 blocks left in the memepool.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
As you can see from the image only two blocks were left that day. Don't worry when I create the thread in the main board you will see the answers other people gave me in the PM discussion. And the thing happened on Sunday. I just want to know more from here.It only means more people used smaller fees in those blocks that's why the fee rate is low.
Blocks are not found in the mempool, only transactions can be found in the mempool. What you are seeing right now is representation of transactions arrange according to their fee ranges. If someone see the mempool to be that empty and pay high fees, you will see the arrange blocks will reposition the fees again and it happens continuously when there are more transactions with high prioritize or low fees.
NB: There is difference between mempool as transaction explorer and Bitcoin node mempool.
Mempool.space is a Bitcoin explorer where you can scan and view different transaction ID while Bitcoin mempool is where transactions that are waiting for comfirmations stays before they get included in the the block and there is not such thing like general mempool, mempool.space doesn't represent the entire Bitcoin mempool, each Bitcoin node has their own respective mempool(memory pool) of transactions.
There can't be 2 blocks left in the memepool.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
As you can see from the image only two blocks were left that day. Don't worry when I create the thread in the main board you will see the answers other people gave me in the PM discussion. And the thing happened on Sunday. I just want to know more from here. It only means more people used smaller fees in those blocks that's why the fee rate is low.
There can't be 2 blocks left in the memepool.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
It only means more people used smaller fees in those blocks that's why the fee rate is low.
I come discovered say na only 2 Blocks been dey remained in mempool.space with 1 sat/vb and transaction was very fast, so I come dey asked some experts in di forum and dem come tell me everything. And I say make I come here too. Weti you think say go happen if those remaining two blocks in the mempool.space are mined? Please what does that mean? And if those two blocks are mined, what will happen?
Dis one na opinion thread. Mega thread dey come.
Dis one na opinion thread. Mega thread dey come.
Jump to: