Author

Topic: Output heat calculator for Miners (Read 293 times)

sr. member
Activity: 448
Merit: 255
January 07, 2018, 06:34:53 PM
#10
A good option is to be living somewhere in the north and not south, and use a room in your house with multiple windows in it so you can basically just create a wind tunnel of cool fresh air. If that's not an option, then an AC is definitely for you, but don't overestimate how much these things need. I'm cooling my 20 miner farm with a 14,000 BTU AC and the temps are fine. Obviously they're going to put out more than that, you just have to exhaust their heat well.

How many cubic feet are you cooling with that 14,000 BTU A/C unit? Also what do you keep the temp of that area? I ask because that is *exactly* what I was going to use for my setup after researching Smiley I figure cooling as small an area as possible with a 70F miner inlet temp along and proper waste heat removal will do the trick.

It depends on your environment. If you use a room in your house you have excellent insulation rather than renting a warehouse unit or something. It means that if you can exhaust all of the hot air that the miners spit out so it's not recirculated into their intake using a window in the room, and you can introduce cool/room temp air to their intakes via the rest of the house/portable AC/another window, you'll be fine.
member
Activity: 504
Merit: 71
Just Getting Started...
January 07, 2018, 01:17:42 PM
#9
A good option is to be living somewhere in the north and not south, and use a room in your house with multiple windows in it so you can basically just create a wind tunnel of cool fresh air. If that's not an option, then an AC is definitely for you, but don't overestimate how much these things need. I'm cooling my 20 miner farm with a 14,000 BTU AC and the temps are fine. Obviously they're going to put out more than that, you just have to exhaust their heat well.

How many cubic feet are you cooling with that 14,000 BTU A/C unit? Also what do you keep the temp of that area? I ask because that is *exactly* what I was going to use for my setup after researching Smiley I figure cooling as small an area as possible with a 70F miner inlet temp along and proper waste heat removal will do the trick.
sr. member
Activity: 448
Merit: 255
January 07, 2018, 01:08:22 PM
#8
A good option is to be living somewhere in the north and not south, and use a room in your house with multiple windows in it so you can basically just create a wind tunnel of cool fresh air. If that's not an option, then an AC is definitely for you, but don't overestimate how much these things need. I'm cooling my 20 miner farm with a 14,000 BTU AC and the temps are fine. Obviously they're going to put out more than that, you just have to exhaust their heat well.
full member
Activity: 266
Merit: 109
Ultra Mega Giga Super Cool Flying Oposum!
January 05, 2018, 12:36:17 PM
#7
I guess that will be my most possible, easiest solution @Vrobb, electricity is pretty cheap at imagined place. So AT the current moment and numbers we will need 50k BTU AC or 5 tons. Thanks for input people!
hero member
Activity: 1610
Merit: 538
I'm in BTC XTC
January 04, 2018, 11:14:01 AM
#6
If AC is your only option, and an expensive one at that, then match the amount of heat coming from the max number of miners you'll possibly be running to the tonnage of the AC unit you buy.  1 ton AC = 12kBTU
Easy peasy, just takes money, money, money!
Mine On!  Cool
full member
Activity: 266
Merit: 109
Ultra Mega Giga Super Cool Flying Oposum!
January 04, 2018, 07:46:06 AM
#5
Well...i don't think bringing fresh air is in option, since, because air is very hot(hot country during whole year). So we should come up with some HUUGE AC, and  to do exhaust option. At the moment i would say "none" for exhausts options, since depending from number of units, we would need to make that, big fans/ACs, and number of units is fluctuating, from 40 - 200.

@Steamtyme preparing solution in advance for real world problem, trying to get a estimated numbers(helping a friend) so we know what fans/AC units we need to  buy depending of the numbers.

@VRobb uhh i don't know that currently, i guess i should ask, but i was thinking around 20C is for start(something like basic room temperature)

@lok8nusa Thanks! I will take this in a count, will later change numbers so we can get some better numbers

legendary
Activity: 1554
Merit: 2037
January 04, 2018, 02:33:08 AM
#4
You are overthinking this a little. Unless it is more of a pet project in math for you.

Essentially you want to take the miner exhaust air out of the room as fast as possible not allowing it to raise the ambient temperature. You want to exhaust this air in a way that it won't recirculate into the room your miners are set up.

So depending on what your goal is here, theoretical math problem or real world solutions, if it is the latter; What do you have for exhaust options in the room? what are your options for bringing in fresh air?

hero member
Activity: 1610
Merit: 538
I'm in BTC XTC
January 04, 2018, 12:07:32 AM
#3
You also need to know the specific heat of air at the conditions of the room.  It's then trivial to calculate temp increase for a given time period.
member
Activity: 254
Merit: 11
Call 811 before you dig
January 03, 2018, 10:59:24 PM
#2
While you need the airflow calculations (volume in CFM), the more critical data is the power dissipation (in watts) and the conversion to BTU's (1 W= 3.412142 BTU/hr).

Good luck!
full member
Activity: 266
Merit: 109
Ultra Mega Giga Super Cool Flying Oposum!
December 27, 2017, 09:56:54 PM
#1
Hey there guyz! I am trying to make Spreadsheet in excel, where i can see how much output i needed for heat for miners i am using. Link down below(there is no virus only simple excel file Cheesy )

Anyways, what numbers i have picked up from internet(please correct me if i am wrong somewhere).

1 S9 - makes around 200 CFM(cubic feet per minute) or 5.6CMM(cubic meters per minute(POWAH OF GOOGLE!).  And depending from that i will need certain amount of output as well.

Now i come to the part where i have room of certain Volume(around 1589.160003 in Cubic Feet or 45 Cubic meters). I want to find out how Volume and Total heat output are related. When i get Total heat output, and Volume, i can just divide one by another, and get time when will room heat in minutes right?

I'm really sure something is off here, so feel free to bash me as much as you want Cheesy Link is below:

 https://drive.google.com/open?id=1GcRsij5kYASmufjrMN1uIHdHc9NrgSBA
Jump to: