Author

Topic: Provably fair lottery (Read 244 times)

newbie
Activity: 2
Merit: 0
August 10, 2017, 06:28:42 AM
#1
Provably fair lottery 6 of 16

Count numbersCount winning combinationsBet
610.0005 BTC
770.0033 BTC (discount 0.0002 BTC)
8280.013 BTC (discount 0.001 BTC)
9840.041 BTC (discount 0.001 BTC)

How to participate?

BTC wallet: 1MGwp2B8SnYF7VuhptsfSc8TFMybFrhenC

Send to the given BTC wallet your bet and write in description of your payment your set of numbers from 0 to 15 separated by spaces.
For example: 7 3 8 9 11 0

12.08.2017 at 4:00 PM (GMT+0) winning combination will be chosen randomly provably fair and the winner will get 3 BTC

How the winner is chosen?

Server seed hash: 29d59be3c088af2332930456c1d04e75c483ee5c4c4f282ff190444df593a2c6

Server seed will be published with result, so given hash guarantee you that I won't change it

RESULT = SHA256([SERVERSEED]:[PAY1]:[PAY2]:....:[PAYN])
PAY1, PAY2, ... , PAYN - bitcoin addresses of bets in chronological order

The first 6 hexadecimal digits of RESULT are converted to decimals one by one and they are winning set.

For example, RESULT = 23970a3b4bc3a24f0f62c3cb5ad8f90f70ff69d8b8a1e4564ef1e93449f1873e
Then winning combination is: 2 3 9 7 0 10 (hex a = dec 10)

Problems?

If you have any problems with this lottery, you can contact my email [email protected] and I'll reply you within 12 hours

Good luck and more wins!
Thanks!
Jump to: