Thanks for participating!
#5 is up if you want to try your luck again
Topic: [Raffleception] Win tickets to "The Raffle of All Raffles"! #4 (Read 542 times)
Congratz to Zepher and notserp!
Thanks for participating!
#5 is up if you want to try your luck again
Thanks for participating!
#5 is up if you want to try your luck again
January 14, 2017, 12:01:52 PM
ill take last 2
tx/74ae19fa5eac708ee08b72b33e9ea11dff4a2fe063cd902d654b424b2de9b8a1
tx/74ae19fa5eac708ee08b72b33e9ea11dff4a2fe063cd902d654b424b2de9b8a1
Thank you!!
Winning blocks will be:
#448170
#448171
Remember you can only win one of the tickets and not both. If someone hits both blocks we'll keep on rolling them until we find a new winner
GOODLUCK!
January 14, 2017, 12:00:26 PM
ill take last 2
tx/74ae19fa5eac708ee08b72b33e9ea11dff4a2fe063cd902d654b424b2de9b8a1
tx/74ae19fa5eac708ee08b72b33e9ea11dff4a2fe063cd902d654b424b2de9b8a1
January 14, 2017, 11:52:22 AM
Zepher took 3 spots, that menas there are only 2 left before we can get this rolling!
January 14, 2017, 10:36:49 AM
1 random ticket pls.
https://blockchain.info/tx/650fbb473d8551d5ae82dc8c7533d90af2be0ceda0faf4307e838aa4ed2a1c23
https://blockchain.info/tx/650fbb473d8551d5ae82dc8c7533d90af2be0ceda0faf4307e838aa4ed2a1c23
Thank you!
5 spots left!!
January 14, 2017, 10:34:18 AM
January 14, 2017, 10:32:16 AM
can newbies join?
Everyone is able to participate as long as they can pay up
January 14, 2017, 10:05:36 AM
Reserve me a random spot please!
I want to take a part in the party.
I want to take a part in the party.
You got it! please pay as soon as possible though, we want to roll these quickly!
https://blockchain.info/tx/2bd47a157dfd07b9f54dad0f2524e86e4a4f1c14edb80584f143ae2e67806b70
Sorry about the delay, I wasn't home.
Liad.
can newbies join?
Reserve me a random spot please!
I want to take a part in the party.
I want to take a part in the party.
You got it! please pay as soon as possible though, we want to roll these quickly!
Reserve me a random spot please!
I want to take a part in the party.
I want to take a part in the party.
Please put me down for 4 ,6 & 8. Thanks!
Done and done sir! 8 tickets left!
Please put me down for 4 ,6 & 8. Thanks!
Edit: 8a0b7302eaaaf0b761de6c034357548b81d9cbf6e5e6f5941ccdc3bf129b0ca3
Edit: 8a0b7302eaaaf0b761de6c034357548b81d9cbf6e5e6f5941ccdc3bf129b0ca3
I'll try again: 5,a,f.
txid b04af549f0fe0a7c63a8c1e325b8366e78a471e11754a15b9eb8ddac985eaaf8
txid b04af549f0fe0a7c63a8c1e325b8366e78a471e11754a15b9eb8ddac985eaaf8
Added! Thanks
I'll try again: 5,a,f.
txid b04af549f0fe0a7c63a8c1e325b8366e78a471e11754a15b9eb8ddac985eaaf8
txid b04af549f0fe0a7c63a8c1e325b8366e78a471e11754a15b9eb8ddac985eaaf8
So we are currently filling the biggest raffle in btct history right now, read more about it here.
While doing this I realize that a lot of people might not want to pay 0.0391 for a ticket when there's a 1 in 256 chance to win. So I came up with the idea of doing a raffle within a raffle - Raffleception!
So here's how we'll do it:
16 spots, classic raffle. There will be 2 equal prizes. Once this is filled we will Select two blocks and whoever has the correct characters at the end of those blocks will win one of the prizes.
The prizes: Winner and runner up will get 1 ticket each to "The Raffle of All Raffles".
Price per ticket: 0.005BTC.
Pay to this address only: 1D32LQzjyjRKCFPfeUw9xDExE6YmLkdBfB
Max spots: 3 / account.
0 - notserp (Paid) - Block 448171! Congratz!
1 - anduck (Paid)
2 - ironmarvel2 (Paid)
3 - notserp (Paid)
4 - counter (Paid)
5 - pmq (Paid)
6 - counter (Paid)
7 - anduck (Paid)
8 - counter (Paid)
9 - anduck (Paid)
a - pmq (Paid)
b - zepher (Paid)
c - Liad.Services (Paid)
d - zepher (Paid)
e - zepher (Paid) - Block 448170! Congratz!
f - pmq (Paid)
You can only win one of the prizes. So if you get 1st you do not have a chance to get a 2nd.
Please pay asap so we do not wait around with this one for too long.
While doing this I realize that a lot of people might not want to pay 0.0391 for a ticket when there's a 1 in 256 chance to win. So I came up with the idea of doing a raffle within a raffle - Raffleception!
So here's how we'll do it:
16 spots, classic raffle. There will be 2 equal prizes. Once this is filled we will Select two blocks and whoever has the correct characters at the end of those blocks will win one of the prizes.
The prizes: Winner and runner up will get 1 ticket each to "The Raffle of All Raffles".
Price per ticket: 0.005BTC.
Pay to this address only: 1D32LQzjyjRKCFPfeUw9xDExE6YmLkdBfB
Max spots: 3 / account.
0 - notserp (Paid) - Block 448171! Congratz!
1 - anduck (Paid)
2 - ironmarvel2 (Paid)
3 - notserp (Paid)
4 - counter (Paid)
5 - pmq (Paid)
6 - counter (Paid)
7 - anduck (Paid)
8 - counter (Paid)
9 - anduck (Paid)
a - pmq (Paid)
b - zepher (Paid)
c - Liad.Services (Paid)
d - zepher (Paid)
e - zepher (Paid) - Block 448170! Congratz!
f - pmq (Paid)
You can only win one of the prizes. So if you get 1st you do not have a chance to get a 2nd.
Please pay asap so we do not wait around with this one for too long.
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