Yes I know, I tried dumpwallet.py and pywallet.py. This is not about reading the file but rather recognize the coin inside the wallet which I have disclosed earlier.
Download and install Berkeley DB 4.8.3 from
https://www.oracle.com/database/technologies/related/berkeleydb-release-history.htmlOpen up a command prompt in the directory containing your wallet.dat file and do
db_dump wallet.dat
You will want to copy (or redirect) that output into a text file/editor.
Search for the string
1262657374626c6f636b. Look at the next like, it should be fairly long. Starting at the 10th character, copy the next 64 characters. This is a block hash represented in hex. You will need to byte swap it because it is stored in internal byte order. This means that every two characters at the beginning are swapped with their symmetric two characters from the end. You can then search for that block hash in various block explorers until you find one for the coin that it belongs to.
For example, in my wallet, I have:
1262657374626c6f636b5f6e6f6d65726b6c65
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
Skipping the first 10 characters gives me:
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
The 64 characters at the beginning are:
398d305048481ee6b096d2a96ab996ad380c6865e5521f000000000000000000
Byte swapping that results in the hash:
0000000000000000001f52e565680c38ad96b96aa9d296b0e61e484850308d39
When looking up that hash in a block explorer, you will see that it is block 564035 in the Bitcoin blockchain.
If you don't find that particular string, try searching for
0962657374626c6f636b instead.