Author

Topic: What if the number of zeroes run out? (Read 122 times)

newbie
Activity: 2
Merit: 0
July 03, 2021, 09:59:10 AM
#4
Thanks that's all I wanted to know. I always thought it was linear.

OK, so every 8 zeros represents 4294967296 (almost 4.3 billion) times faster bitcoin hash rate.
So we got more than 5 more sets of 8 zeros, or 4.29 billion x 4.29 billion x 4.29 billion x 4.29 billion x 4.29 billion
Which is an exponential increase, not a linear increase ... it wont happen.

Edit: reminder that 2^256 is close to the number of atoms in the universe (only about 1000 times smaller)
legendary
Activity: 4592
Merit: 1851
Linux since 1997 RedHat 4
July 03, 2021, 07:32:43 AM
#3
Would it happen? Hashrate,  miners and therefore difficulty keep increasing...
OK, so every 8 zeros represents 4294967296 (almost 4.3 billion) times faster bitcoin hash rate.
So we got more than 5 more sets of 8 zeros, or 4.29 billion x 4.29 billion x 4.29 billion x 4.29 billion x 4.29 billion
Which is an exponential increase, not a linear increase ... it wont happen.

Edit: reminder that 2^256 is close to the number of atoms in the universe (only about 1000 times smaller)
legendary
Activity: 3822
Merit: 2703
Evil beware: We have waffles!
July 03, 2021, 07:27:37 AM
#2
"Number of zeros" in what? What the hell are you asking?  Huh
newbie
Activity: 2
Merit: 0
July 03, 2021, 03:12:15 AM
#1
Would it happen? Hashrate,  miners and therefore difficulty keep increasing...
Jump to: