Topic: why deepbit address sends btc to himself? (Read 575 times)
again, thank you very much for the info
This is how bitcoin works. Anytime you spend/send bitcoin you have to spend previous outputs in their entirety as inputs. If the total of the inputs ends up being more than you want to spend, then you have to send the extra back to yourself as a new output.
If at the time of that transaction deepbit happened to have an output valued at 0.01 BTC, then they could perhaps have simply spent that one output. Instead they spent an output that was valued at 3.25397458 BTC. Having used that output as the input to their transaction, they created 2 new outputs sending 0.01 BTC to an address, and the remaining change back to the original address as a new output.
If at the time of that transaction deepbit happened to have an output valued at 0.01 BTC, then they could perhaps have simply spent that one output. Instead they spent an output that was valued at 3.25397458 BTC. Having used that output as the input to their transaction, they created 2 new outputs sending 0.01 BTC to an address, and the remaining change back to the original address as a new output.
like: http://blockchain.info/tx/75a8373b98892ef09181bf66fd924bdc72348b3badf411635c7837f5f2b861b6
why not only send the 0.01 BTC to the other address?
why not only send the 0.01 BTC to the other address?
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