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Topic: 0.1 BTC for python help! - page 2. (Read 971 times)

newbie
Activity: 19
Merit: 1
April 13, 2023, 09:33:25 AM
#38
Do you just want a script that scans the public keys in "x" range and when it matches the public one that 1btc has, it saves its respective private key?
member
Activity: 122
Merit: 36
April 13, 2023, 03:40:56 AM
#37
you put them in a text file one key on each line and execute the program replacing the single key with the file
Not sure if you can do that with the python version but certainly with keyhunt.
newbie
Activity: 18
Merit: 1
April 13, 2023, 03:08:17 AM
#36

Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?


yes, the program can be modified to accept 1 billion keys and the chances do increase by the number of keys but also the speed drops proportionally with the number of keys.

it's a tradeoff speed or keys



Obviously with 1 billion key input its going to get super slow, but with manageable input it should be super fast. Can you elaborate further how can kangaroo algorithm take multiple pubkeys
newbie
Activity: 18
Merit: 1
April 13, 2023, 03:01:08 AM
#35
Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?


I am pleased it worked and you have recovered your BTC.
Can I claim the bounty?  My BTC address 1NcFJzayiHy4iPFz4QR9BqP8XHuSDCv5qx

The chances may increase exponentially with more addresses but of course it slows down with a billion keys to check.
The keyhunt program is much faster.
Plus a billion addresses may seem like a lot but it is a tiny drop in the ocean.

Well done again on recovering your btc.   

By "it worked" I meant that the script worked. It says I have to wait 1.7 million year before it actually finds the key.
member
Activity: 72
Merit: 43
April 13, 2023, 01:56:51 AM
#34

Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?


yes, the program can be modified to accept 1 billion keys and the chances do increase by the number of keys but also the speed drops proportionally with the number of keys.

it's a tradeoff speed or keys

member
Activity: 122
Merit: 36
April 13, 2023, 01:39:42 AM
#33
Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?


I am pleased it worked and you have recovered your BTC.
Can I claim the bounty?  My BTC address 1NcFJzayiHy4iPFz4QR9BqP8XHuSDCv5qx

The chances may increase exponentially with more addresses but of course it slows down with a billion keys to check.
The keyhunt program is much faster.
Plus a billion addresses may seem like a lot but it is a tiny drop in the ocean.

Well done again on recovering your btc.   
member
Activity: 110
Merit: 61
April 13, 2023, 01:14:01 AM
#32
Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?

Kangaroo algorithm is originally designed to search for a specific point (public key) and does not work with multiple keys. In the process of work, he already creates a lot of points, mathematically related with original point. Basically you need to generate a number of pubkeys equal to square root of range to solve the ECDLP. If we talking about range like 2^125 (current unsolved puzzle), you have to generate 2^63 pubkeys to solve it (no need to save them all, it is futher kangaroo optimizations called distinguished points)
newbie
Activity: 18
Merit: 1
April 12, 2023, 11:53:15 PM
#31
just download the code to a directory(folder)
change to that directory don't alter any code.  It is all run from the command line.


Open a terminal / powershell window and type in the command line

python3 kangaroo.py 00008:0000ff 02049370a4b5f43412ea25f514e8ecdad05266115e4a7ecb1387231808f8b45963
cut & paste the above to get the idea.

python 3 calls the program kangaroo.py

00008 is the start of the range in hexadecimal.
Here you put in your start range of the first key you generated yours might be much bigger 1234567abcde or whatever.

: is a separator

000ff is the end of the range (1000 decimal is a different number to 1000 hex
again put in your end range

then put in the public key of the first key you generated and wait.

If successful, a file containing the key will be generated as well as being shown on the screen

I have tested this program and it works.
good luck.



Thanks for helping, it worked.
Here comes the interesting part, that this Kangaroo algorithm takes only 1 public key. which is like finding 1 drop in an ocean as someone quoted. What about finding 1 billion drops instead of 1? Thats my point, when I say that 1 billion public keys increase the probability by 1 billion times. Hence, I am convinced if this Kangaroo algorithm takes 1 billion public keys instead of 1, the chances of finding one would increase exponentially. What do you say?
legendary
Activity: 3472
Merit: 10611
April 12, 2023, 10:52:07 PM
#30
1. Adding numbers to private keys ? Is that even possible/safe ? How would that generate a public key ? Hmm RSA, eclipctive curve ? hmmm..
It's called elliptic curve and the private keys are merely numbers so you can perform any kind of arithmetic operation on them as you like (add, subtract, multiply, divide, etc.) as long as you end up with an integer that is between 1 and curve order (N).

As for safety it comes down to how the initial key was selected, if it were random the result will also be safe. In fact this is the method that vanity address generators use.
newbie
Activity: 18
Merit: 1
April 12, 2023, 10:41:29 PM
#29
still dont know what the author wants..

@Unplugged Taste
tell us, do you know the public key of the address containing 1 BTC or not ??

from your posts i believe you dont know which public key is the correct one....

i posted on the first page a script that converts all the public keys you have into addresses and compares them to the address containing your money.
it will return only the address and it's public key

IF you already know the public key of the address why would you need to check all the public keys at once??

Perhaps you misunderstood what I said. Let me clear you that I know the public key & address carrying funds. The reason of me stressing on 1 billion public keys around it and trying to find any one private key of any of them is that it is increasing chances by 1 billion times. Why? Because they are in a sequence like 1,2,3,4,... etc. Its like there are 1 billion private keys carrying that 1 BTC because any one could easily lead to the principle private key easily.
member
Activity: 72
Merit: 43
April 12, 2023, 03:41:07 AM
#28
still dont know what the author wants..

@Unplugged Taste
tell us, do you know the public key of the address containing 1 BTC or not ??

from your posts i believe you dont know which public key is the correct one....

i posted on the first page a script that converts all the public keys you have into addresses and compares them to the address containing your money.
it will return only the address and it's public key

IF you already know the public key of the address why would you need to check all the public keys at once??
member
Activity: 122
Merit: 36
April 12, 2023, 02:05:40 AM
#27
just download the code to a directory(folder)
change to that directory don't alter any code.  It is all run from the command line.


Open a terminal / powershell window and type in the command line

python3 kangaroo.py 00008:0000ff 02049370a4b5f43412ea25f514e8ecdad05266115e4a7ecb1387231808f8b45963
cut & paste the above to get the idea.

python 3 calls the program kangaroo.py

00008 is the start of the range in hexadecimal.
Here you put in your start range of the first key you generated yours might be much bigger 1234567abcde or whatever.

: is a separator

000ff is the end of the range (1000 decimal is a different number to 1000 hex
again put in your end range

then put in the public key of the first key you generated and wait.

If successful, a file containing the key will be generated as well as being shown on the screen

I have tested this program and it works.
good luck.






newbie
Activity: 18
Merit: 1
April 12, 2023, 01:34:15 AM
#26
If you really want to use python then use this. Much easier than deciphering the robot code.

https://github.com/Telariust/pollard-kangaroo/blob/master/pollard-kangaroo.py

start it by running
python3 kangaroo.py 00008:0000ff 02049370a4b5f43412ea25f514e8ecdad05266115e4a7ecb1387231808f8b45963

replacing the range 00008 (start)  : 0000ff (end)   and public keys with your own.

It has a set of test keys too so if you just run

python3 kangaroo.py

you can see how it works with test data


Where in the above script should I insert my own start and end range? the script you suggested https://github.com/Telariust/pollard-kangaroo/blob/master/pollard-kangaroo.py
It has also inserted pubkeys in an awkward way that I don't understand
member
Activity: 122
Merit: 36
April 12, 2023, 12:24:17 AM
#25
If you really want to use python then use this. Much easier than deciphering the robot code.

https://github.com/Telariust/pollard-kangaroo/blob/master/pollard-kangaroo.py

start it by running
python3 kangaroo.py 00008:0000ff 02049370a4b5f43412ea25f514e8ecdad05266115e4a7ecb1387231808f8b45963

replacing the range 00008 (start)  : 0000ff (end)   and public keys with your own.

It has a set of test keys too so if you just run

python3 kangaroo.py

you can see how it works with test data

newbie
Activity: 18
Merit: 1
April 11, 2023, 11:43:53 PM
#24
Would someone please see the script that I think is best suited for my needs.
The script is generated by chatGPT not me. So if you suggest any changes in it please be specific like which should be replaced with which line of code. Thanks.

Code:
import multiprocessing
import hashlib
import binascii
from Crypto.Util.number import long_to_bytes, bytes_to_long

start_hex = '0000000000000000000000000000000000000000000000000000000000000000'
end_hex = '0000000000000000000000000000000000000000000000000000000000000000'
start = int(start_hex, 16)
end = int(end_hex, 16)
num_parts = 4

def kangaroo(start, end, pubkeys):
    G = 2
    hash_size = 256
    max_iters = 2**32

    def H(x):
        if isinstance(x, bytes):
            return hashlib.sha256(x).digest()
        else:
            return hashlib.sha256(x.to_bytes((x.bit_length() + 7) // 8, byteorder='big')).digest()




    def kangaroo_algorithm(x1, x2, step):
        x = x1
        xs = set()
        for i in range(max_iters):
            x = (x + step) % end
            h = bytes_to_long(H(long_to_bytes(x)))
            if h in pubkeys:
                return x, pubkeys[h]
            xs.add(x)
            if len(xs) == hash_size:
                xs.clear()
                y = x2
                for j in range(i):
                    y = (y + step) % end
                    if y in xs:
                        return x, None
        return None, None

    step = end // hash_size
    x1 = start
    x2 = start + step
    private_key, public_key = kangaroo_algorithm(x1, x2, step)
    if private_key is not None:
        private_hex = hex(private_key)[2:]
        private_hex = '0' * (64 - len(private_hex)) + private_hex
        return (private_key, private_hex, public_key)
    else:
        return None

if __name__ == '__main__':
    pubkeys_file = 'pubkeys.txt'
    foundkeys_file = 'foundkeys.txt'

    with open(pubkeys_file, 'r') as f:
        pubkeys = {int(line.strip(), 16) for line in f}

    pool = multiprocessing.Pool(processes=num_parts)

    start_ranges = [start + i * ((end - start) // num_parts) for i in range(num_parts)]
    end_ranges = [start + (i + 1) * ((end - start) // num_parts) for i in range(num_parts)]
    args = [(start_ranges[i], end_ranges[i], pubkeys) for i in range(num_parts)]

    results = pool.starmap(kangaroo, args)
    foundkeys = [result for result in results if result is not None]

    with open(foundkeys_file, 'w') as f:
        for result in foundkeys:
            f.write(f"{result[0]}\n")
            print(f"Found private key: {result[1]} for public key: {result[2]}")

    print("Done.")

I ran the script its just blinking since there are no print statements added along... I don't know whether it is working correctly or not.
sr. member
Activity: 1190
Merit: 469
April 11, 2023, 11:18:20 PM
#23
Hi everyone! I hope you are all doing great.

I am not a programmer. Just started running ready made python scripts given by Chat GPT. But now I realized robots cannot replace humans whatsoever Tech advancements may happen.
Here is my situation. I am private keys lost case. AND I just don't want to handover matters into other's hands for obvious reasons.
My case is super identical. I created a bitcoin puzzle myself with my own BTCs and in the process I lost my own private keys, very funny hah! BUT its true.
First of all I generated a random private key from within a range, like that of BITCOIN Puzzle range. I generated its public key and I than started adding 1 million in the private key and generated its public key. Again I added 1 million in the private key and generated its public key. I continued this for 1k times. So basically from first private key and last private there is 1 billion private keys.
In case you didn't get my point:
Suppose I randomly chosen private key as 980
I added 1 million in private key = 1,000,980
Again added 1 million = 2,000,980,
...
...
...
Up till I added 1 billion in my first private key.

From start to end of private keys, I generated all public keys! YES, I still have 1 billion public keys of those 1 billion private keys.
I don't understand the motivation for creating 1 billion bitcoin private keys (and public keys). And then depositing 1 BTC on to one of them. What's the purpose of the other 999,999 private keys? i mean 999,999,999.

Quote
Ironically I lost all my private keys.
You have to write them down on paper. Of course, in your case you would need to make a trip to office depot to get a couple packs of copy paper that comes in the 500 quantity stacks... Shocked you could even get that box that has like 3000 perforated sheets all connected together so you could print them out on a dot matrix printer.
newbie
Activity: 18
Merit: 1
April 11, 2023, 10:23:46 PM
#22
First of all I generated a random private key from within a range, like that of BITCOIN Puzzle range. I generated its public key and I than started adding 1 million in the private key and generated its public key. Again I added 1 million in the private key and generated its public key. I continued this for 1k times. So basically from first private key and last private there is 1 billion private keys.
In case you didn't get my point:
Suppose I randomly chosen private key as 980
I added 1 million in private key = 1,000,980
Again added 1 million = 2,000,980,
...
...
...
Up till I added 1 billion in my first private key.

From start to end of private keys, I generated all public keys! YES, I still have 1 billion public keys of those 1 billion private keys.
Ironically I lost all my private keys. Not a single public key is released since no transaction has ever happened.

What was the purpose to iterate 1k times to add 1m to the initial and then intermediate random key of this iteration? To me it makes no sense when you used also all intermediate private keys anyway (or I can't follow your procedure).

If I understand you correctly you have a starting private key from some range and you stepped over a consecutive range of 1 billion (1k times 1m) private keys. All private keys are only one unit apart from each other.
Then you generated from all those 1 billion private keys the respective public keys. It's a fair assumption that you only initially stored the starting private key and not all the intermediate ones. You did that by some script or program and kept only the output of the public keys. You had no or poor backup and somehow lost your program or script and with it your initial private key. Well, shit happens. Out of curiosity, when did you do that and how much was 1 BTC worth at that time?

I placed 1 BTC in any one of those 1 billion private keys that I am looking for.
Just to be clear: there's 1 BTC controlled by a single private key from your range of 1 billion consecutive private keys located somewhere in the private key space of Bitcoin?

Still, your 1k steps don't make any sense to me in the context of your other details. Feel free to correct me where I'm wrong.

So far you are the only one who has perfectly understood what I am saying! You are 100% correct, there's 1 BTC controlled by a single private key within the range. It was around 2 months ago.
newbie
Activity: 18
Merit: 1
April 11, 2023, 10:17:36 PM
#21
1. Adding numbers to private keys ? Is that even possible/safe ? How would that generate a public key ? Hmm RSA, eclipctive curve ? hmmm..

2. 1 BTC each in one of these billion addresses ? Euh are you aware bitcoin only has 21 million coins ?! LOL.

This smells and sounds fishy to me ! =D



Perhaps you misunderstood what I said. There is only 1 BTC in only 1 address. That 1 address that I already know & its public key has 1 billion public keys around it. you can turn any number to become your private key or any sequence of number some people are asking whether it is possible or not!
jr. member
Activity: 36
Merit: 2
April 11, 2023, 09:20:43 PM
#20
Hi everyone! I hope you are all doing great.

I am not a programmer. Just started running ready made python scripts given by Chat GPT. But now I realized robots cannot replace humans whatsoever Tech advancements may happen.
Here is my situation. I am private keys lost case. AND I just don't want to handover matters into other's hands for obvious reasons.
My case is super identical. I created a bitcoin puzzle myself with my own BTCs and in the process I lost my own private keys, very funny hah! BUT its true.
First of all I generated a random private key from within a range, like that of BITCOIN Puzzle range. I generated its public key and I than started adding 1 million in the private key and generated its public key. Again I added 1 million in the private key and generated its public key. I continued this for 1k times. So basically from first private key and last private there is 1 billion private keys.
In case you didn't get my point:
Suppose I randomly chosen private key as 980
I added 1 million in private key = 1,000,980
Again added 1 million = 2,000,980,
...
...
...
Up till I added 1 billion in my first private key.

From start to end of private keys, I generated all public keys! YES, I still have 1 billion public keys of those 1 billion private keys.
Ironically I lost all my private keys. Not a single public key is released since no transaction has ever happened. I placed 1 BTC in any one of those 1 billion private keys that I am looking for. I will be glad to share 0.1 BTC for genuine help specifically for python scripts would be great. Currently I am considering modifying Kangaroo algorithm to suit my needs, no luck so far.
Looking forward

Unfortunately, if you hide your private key in a small range, the unmanned robot will already work and have already taken your money.

full member
Activity: 385
Merit: 110
April 11, 2023, 07:47:48 PM
#19
1. Adding numbers to private keys ? Is that even possible/safe ? How would that generate a public key ? Hmm RSA, eclipctive curve ? hmmm..

2. 1 BTC each in one of these billion addresses ? Euh are you aware bitcoin only has 21 million coins ?! LOL.

This smells and sounds fishy to me ! =D

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