San Francisco 49ers
gt1991
Topic: 1 BTC Giveaway - NFL Week 12 - BitBook.biz - page 3. (Read 5776 times)
Jacksonville Jaguars
WuBitBook
WuBitBook
San Francisco 49ers
User: mirtz
User: mirtz
benjig - san francisco 49ers
Let's say two teams tie. Team "A" has 9 bets and team "B" has 1 bet. How are the winnings divided? Are they split evenly at .1 each? I think it's more fair to reward half the BTC to each winning side keeping the odds in proportion to the payout and rewarding those picking the unlikely team. The payouts would be 0.0556 for the 9 bets on team A and .5 for the bet on team B.
That's a great suggestion, but that situation actually came up in last week's contest (Seahawks and Bengals both scored 41) and we divided the winnings evenly among the winners.
Given the precedent we will keep the same rules for this week (all winners are paid equally), but in future contests we may add that rule.
Thanks for the feedback!
that would be great because i was on bengals last contest and i felt very bad when seahawks tied with them
Detroit Lions.
Bitbook Name: Steelfox7
Bitbook Name: Steelfox7
New England Patriots
[email protected]
[email protected]
Kschneezy
New England Patriots
New England Patriots
Let's say two teams tie. Team "A" has 9 bets and team "B" has 1 bet. How are the winnings divided? Are they split evenly at .1 each? I think it's more fair to reward half the BTC to each winning side keeping the odds in proportion to the payout and rewarding those picking the unlikely team. The payouts would be 0.0556 for the 9 bets on team A and .5 for the bet on team B.
Yes that would be much more fair. For example, almost everyone is choosing the broncos this week as they are probably the most likely to win this. If the broncos tie with another longshot team that only had one person choose it, it just wouldnt be fair for the person who chose the longshot against all odds team to win the same amount as the relatively safe pick of the broncos. Let's say two teams tie. Team "A" has 9 bets and team "B" has 1 bet. How are the winnings divided? Are they split evenly at .1 each? I think it's more fair to reward half the BTC to each winning side keeping the odds in proportion to the payout and rewarding those picking the unlikely team. The payouts would be 0.0556 for the 9 bets on team A and .5 for the bet on team B.
That's a great suggestion, but that situation actually came up in last week's contest (Seahawks and Bengals both scored 41) and we divided the winnings evenly among the winners.
Given the precedent we will keep the same rules for this week (all winners are paid equally), but in future contests we may add that rule.
Thanks for the feedback!
Let's say two teams tie. Team "A" has 9 bets and team "B" has 1 bet. How are the winnings divided? Are they split evenly at .1 each? I think it's more fair to reward half the BTC to each winning side keeping the odds in proportion to the payout and rewarding those picking the unlikely team. The payouts would be 0.0556 for the 9 bets on team A and .5 for the bet on team B.
eroxors
broncos
broncos
Bitice
Houston Texans
Houston Texans
xMutil4teR
Denver Broncos
Denver Broncos
Houston Texans - moreia
Thanks
Thanks
Detroit Lions
BitBook User: sergiom
BitBook User: sergiom
Kako
Dallas Cowboys
Dallas Cowboys
rapidx - Detroit lions
BitBook - SendCookies Pick - Dallas Cowboys
Username: Prime
NY Giants
NY Giants
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