A lot is not enough - page 2. | Bitcointalksearch.org

gentlemand

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Welt Am Draht

Quote from: hexafraction on July 31, 2015, 03:20:47 PM

Best of luck, and share some with me! In all seriousness (and a lot of estimation), you're more likely to lose power AND have a heart attack AND be robbed AND be hit by a falling tree during your "lottery" session.

A terrorist attack during a plane crash while lightning shoots up my chuff will tell me that chance is smiling down upon me. When I crack them keys I'll sort you out, don't worry.

erre

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How many fucking grains on sand are on earth? And how you define " sand" ?

hexafraction

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Quote from: gentlemand on July 31, 2015, 03:18:56 PM

Quote from: jonald_fyookball on July 31, 2015, 03:17:20 PM

yes someone against all odds could get lucky. but it would be , well...against all odds. Tongue

I'm gonna have a go right now. I might be some time...

Best of luck, and share some with me! In all seriousness (and a lot of estimation), you're more likely to lose power AND have a heart attack AND be robbed AND be hit by a falling tree during your "lottery" session.

gentlemand

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Welt Am Draht

Quote from: jonald_fyookball on July 31, 2015, 03:17:20 PM

yes someone against all odds could get lucky. but it would be , well...against all odds. Tongue

I'm gonna have a go right now. I might be some time...

jonald_fyookball

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Core dev leaves me neg feedback #abuse #political

yes someone against all odds could get lucky. but it would be , well...against all odds. Tongue

you may need a metaphor or comparison to understand just how against the odds it would be.

if a grain of sand is about one square millimeter, what are the odds of guessing
the exact location of a grain of sand somewhere on the earth's surface?

the surface of the earth is about 510 million square kilometers, or about half
of 10^21 square millimeters. That's much much much smaller a number than
the number of private key combinations which is about 10^77.

hexafraction

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Quote from: Bit_Happy on July 31, 2015, 03:10:44 PM

Great graphic, but can't someone (against all odds) get "lucky" and bruteforce a private key "easily" with a fast match?
Sorry about the basic question, which has probably been answered several times before...

Yes, that is in fact true. Data's just data, so it's possible to get a match by bruteforcing. One can also get lucky and find such an address by clicking "new address" in their wallet¹. In both cases, you're more likely to die while sitting in your computer chair during the time you're bruteforcing.

¹ This is actually possible, due to a buggy wallet that gave a bunch of people the same fixed private key due to an issue with generating random numbers.

Bit_Happy

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A Great Time to Start Something!

Quote from: TookDk on July 31, 2015, 03:03:04 PM

Quote from: mallard on July 31, 2015, 03:02:23 PM

If you bruteforced private keys, how long would it be until you found an address with at least 1 BTC in it?

Great graphic, but can't someone (against all odds) get "lucky" and bruteforce a private key "easily" with a fast match?
Sorry about the basic question, which has probably been answered several times before...

jonald_fyookball

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you would start seeing collisions on the order of 2^160 which is the number of Bitcoin addresses.
if you had 10,000 supercomputers all working on it, it might only take millions of years.

kevindurant

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2²⁵⁶ = 2^{(10)^(256/10)}

10³= 1000 = 2¹⁰ (yeah I know 2¹⁰ is equal to 1024 but let's assume it's like that.

Then; 2²⁵⁶ = 10^256*3/10 = 10⁷⁷

78 digit number. It's more than that of course.

"then the total number of hydrogen atoms would be roughly 10⁸²" http://www.universetoday.com/36302/atoms-in-the-universe/

There's 1 private key for each hydrogen atom in the universe.

TookDk

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One coin to rule them all

Quote from: mallard on July 31, 2015, 03:02:23 PM

If you bruteforced private keys, how long would it be until you found an address with at least 1 BTC in it?

mallard

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If you bruteforced private keys, how long would it be until you found an address with at least 1 BTC in it?

jonald_fyookball

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Core dev leaves me neg feedback #abuse #political

Quote from: BitcoinPenny on July 31, 2015, 02:48:37 PM

Quote from: jonald_fyookball on July 31, 2015, 01:22:00 PM

if you like big numbers... Ron Graham explains how big is Graham's number:

https://www.youtube.com/watch?v=GuigptwlVHo&feature=iv&src_vid=HX8bihEe3nA&annotation_id=annotation_2349383243

When he said that 3-arrow-arrow-arrow-3 was simply the number of arrows in his number, I bursted out laughing. This kind of math is for crazy people. Grin

Regards,
Me

..and that number isn't the final answer, it's just the first of a a sixty four level deep recursive stack of nested arrow notation numbers.

BitcoinPenny

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BitcoinPenny.com

Quote from: jonald_fyookball on July 31, 2015, 01:22:00 PM

if you like big numbers... Ron Graham explains how big is Graham's number:

https://www.youtube.com/watch?v=GuigptwlVHo&feature=iv&src_vid=HX8bihEe3nA&annotation_id=annotation_2349383243

When he said that 3-arrow-arrow-arrow-3 was simply the number of arrows in his number, I bursted out laughing. This kind of math is for crazy people. Grin

Regards,
Me

Amph

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Quote from: Hopalong on July 31, 2015, 02:25:59 PM

Quote from: Amph on July 31, 2015, 02:04:34 PM

Quote from: jonald_fyookball on July 31, 2015, 01:22:00 PM

if you like big numbers... Ron Graham explains how big is Graham's number:

https://www.youtube.com/watch?v=GuigptwlVHo&feature=iv&src_vid=HX8bihEe3nA&annotation_id=annotation_2349383243

in theory the biggest number should be 1Y(yotta)^1Y which is 10^24^(10^24)

1Y(yotta)^1Y+1 which is 10^24^(10^24)+1

well i was talking about defined big numbers, i know that numbers are infinite....

like the smallest is planck length or string

Hopalong

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Quote from: Amph on July 31, 2015, 02:04:34 PM

Quote from: jonald_fyookball on July 31, 2015, 01:22:00 PM

if you like big numbers... Ron Graham explains how big is Graham's number:

https://www.youtube.com/watch?v=GuigptwlVHo&feature=iv&src_vid=HX8bihEe3nA&annotation_id=annotation_2349383243

in theory the biggest number should be 1Y(yotta)^1Y which is 10^24^(10^24)

1Y(yotta)^1Y+1 which is 10^24^(10^24)+1

Aggressor66

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If you write Graham's number digits using the shortest known length (Planck length which is equal to 10^-41 or so~), the entire universe wouldn't contain it.

or

∞+1 – Infinity + 1 Wink

Amph

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Quote from: jonald_fyookball on July 31, 2015, 01:22:00 PM

if you like big numbers... Ron Graham explains how big is Graham's number:

https://www.youtube.com/watch?v=GuigptwlVHo&feature=iv&src_vid=HX8bihEe3nA&annotation_id=annotation_2349383243

in theory the biggest number should be 1Y(yotta)^1Y which is 10^24^(10^24)

gentlemand

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Welt Am Draht

The arteries in my brain are too hard to comprehend numbers beyond 51 these days. I'll have to remind myself that that's really big and be content with that.

I E

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