ARG Puzzle with 3.5 BTC Private Key Prize, Game Over - page 13.

Yemmster

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Yeah that was very anticlimactic...

xELx

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Quote from: LtPaxIV on July 06, 2014, 05:30:23 PM

Quote from: ?? on ??

lol someone got it
pls explain

it was send to a wallet that already has a huge amount of coins Shocked

Yea seems a bit odd that someone with almost a million $ worth in coin is trying to solve a puzzle for $2000~.

LtPaxIV

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Quote from: ?? on ??

lol someone got it
pls explain

it was send to a wallet that already has a huge amount of coins Shocked

Gatekeeper

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Quote from: alphabetacanary on July 06, 2014, 12:16:48 PM

Guys, I believe it's a shift of the original text.
Each character is shifted within the 62 character alphabet described by Crops clue.
The amount to shift is given by the WOW signal characters.

This program, for example transforms the "z69JZ..." string into

5KZnsvrXDcP7JFD7GCuZvifrbcBtK4kAe8nHx6ibktgvPJxs4Lp

Notice how the first two characters changed to 5K ? That's what private keys start with. However, the answer I get doesn't transform into a valid private key since the checksum doesn't match. I'm posting my program in the hopes someone else has a better variation. I just want this thing over...

Code:

#include 
#include 

char* alph = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

int idxof(char c, char* alphabet) {
    int i;
    for (i=0;i        if (alphabet[i] == c) { return i; }
    }
    return -1;
}

main()
{
    char* s = "z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P";
    char* p = "6EQUJ5";

    int i =0;
    int n;
    while (i < strlen(s)) {
        int n = idxof(s[i],alph);
        int v = idxof(p[i%strlen(p)],alph);
        v=(v+n) % 62;
        printf ("%c",alph[v]);
        i++;
    }
    printf ("\n");
}

EDIT: I believe there is either more after the 6EQUJ5 or the algorithm is slightly off. Remember, if you are trying variations of the 'p' string, you must only use characters from the alphabet. So no punctuation or spaces.

answer is in here somewhere

Gatekeeper

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Quote from: ytcoinartist on June 22, 2014, 05:25:48 PM

Portrait is a "shared start point."

Public Address: 1HXUobwcB19cGDrghuh42HDdJdJvrJUEra

the prize awaits you
the final palindrome is key
once small is now tall

#2103

arg

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Mitchell

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Verified awesomeness ✔

Quote from: Timmmaahh on July 06, 2014, 04:29:25 PM

OP is killing my sleep :'D

OP is killing everyone's sleep. I have had this puzzle in my mind for over a week now and the sad thing is that I can barely contribute since I don't get half of the stuff you guys post. I could help out a bit with the MC related stuff, but that's all.

Timmmaahh

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OP is killing my sleep :'D

Mitchell

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Verified awesomeness ✔

Quote from: ytcoinartist on June 22, 2014, 05:25:48 PM

the prize awaits you
the final palindrome is key
once small is now tall

Here is the next hint guys! We are close! I can smell the BTC and it smells like fiat free money!

Kangaderoo

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note: unrelated...!!

http://en.wikipedia.org/wiki/Kryptos

Just in case you want to crack some more puzzles in the future.... Tongue

part four is still unsolved...

mirth23

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Merit: 10

Ok, here's some collected thoughts (yet again). What have we got?

1) 0=0A=10BABYA=36 (0=0 A=10 a=36)

I am 95% certain this is the description of a mapping of [0-10A-Za-z] to numbers starting with 0. It tells you the three starting points of each substring in the list. All other interpretations that I have seen make no sense to me.

This mapping could have two uses: character shifting or transformation.

2) The hidden XMP data.

This seems to cross out all the data on the left. It also crosses out the 51 byte string. Lastly, it appears to highlight the positional codes in the RT. ASCEN section (or possibly cross them out). It even points at the 6 in '36' which seemed noteworthy since 6 shifts is what's needed to turn the z into a 5. OP went to the trouble to hide this XMP data so we should assume that it must somehow hint at the solution.

3) z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P

Most of us have shifted the hell out of this in various straightforward ways. Several of us have used the WOW signal strength as an alphabet cipher key, and at least a couple of us have used series of timecodes over on the right as a cipher key. It either doesn't want to want to turn into a private key address, or we're barking up the wrong tree.

Interestingly enough, it appears to be vigorously crossed out by the XMP. This made me wonder if there is some sort of 3733T instructional message hidden in it, but I wonder that less and less with OP's more recent hints.

4) CHANNEL NUMBER (TWO DIGITS, WRITTEN VERTICALLY)

This was recreated by OP for this image, but was text from the original document. It's possible that OP preserved it as some sort of hint. That said, most instances of "two digits, written vertically" are crossed out by the XMP.

5) Some timecode and other data on the right

This stuff is not crossed out by the XMP, some of it seems to be specifically called out by the XMP, but it's not clear what to do with it. It seems worth calling out because I think it's been largely ignored.

6) Various OP clues

"Final countdown" - Either we're near the end, or it is somehow referring to the time codes that are called out in the XMP.

wow + crops - we need to use something from the Crops puzzle. I am assuming the character map, but could there be more?

6EQUJ5 - This is the Wow signal strength. We must need to use this somehow, but it doesn't work as a key.

No sha or hash needed - any transforms we solve will be relatively straightforward

the prize awaits you
the final palindrome is key: hints at wow being a cypher key?
once small is now tall: all uppercase?

Izerian

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For c# fans

This assumes the "z69JZ..." above uses an alpha "O" instead of a numeric "0".

Converted from the posted code snippet earlier. (Thanks)

Code:

    class Program
    {
        static void Main(string[] args)
        {
            Test();
        }

        static string alph = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
        static void Test()
        {
            string s = "z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P";
            string p = "6EQUJ5";

            int i = 0;
            while (i < s.Length)
            {
                int n = idxof(s[i], alph);
                int v = idxof(p[i % p.Length], alph);
                v = (v + n) % 62;
                Console.Write(alph[v]);
                i++;
            }
            Console.WriteLine();
            Console.WriteLine("Press any key");
            Console.ReadKey();
        }

        static int idxof(char c, string alphabet){
            for (int i = 0; i < alphabet.Length; i++)
                if (alphabet[i] == c){ return i; }
            
            return -1;
        }
    }

Timmmaahh

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5UfPnqpcSeUYJFnhqCuj1KamzhQvP5KkeinHxqoDfoeaevcteLp

i get this but not working Sad

arg-sidekick

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In regards to the font, it's Lucida Sans Typewriter with a fuckton of kerning.

I think she was trying to mimic the docs font, but wasn't as anal as arg and myself.

I know, almost certainly, that the first header (RT. ACSEN.) means nothing, but it is one/two pixels higher than OG. I'm really, really plucking ideas out my rectum because I have a possible solution but I'm definitely missing something small.

Also, don't think we're closer than anyone else in this thread, we're really not.

http://i.imgur.com/0WG1oyu.gif

shorena

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No I dont escrow anymore.

updated pdf: https://mega.co.nz/#!UhhWHIwB!1nQUPq2gKqCC61xySHS37soRnzaFS0Ov1zSpKpllFZc

thanks to mirth23 it now has a short version.

It has all the hints AFAIK. Enjoy

Gatekeeper

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Merit: 250

once small is now tall

is the annoying part, you can't use 6equj5 as the key because the 5th char would become a capital i , which isnt valid
you cant really change all lower case to upper case because i doubt a priv key will have no lower at all

so i guess this part is the key to solving it
we know 6EQUJ5 gives invalid code

Huh

arg

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I test both, but O looks to be valid.

http://i.imgur.com/wykAupC.gif

Quote from: Gatekeeper on July 06, 2014, 03:17:19 PM

If the font is the same as the word TWO above it then it's a 0

It's a different font.

http://i.imgur.com/qB5JDAG.jpg

http://i.imgur.com/VVlx0vR.jpg

Same as Mirth23, I've tried hundreds of mutations of the strings with no result.

Gatekeeper

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If the font is the same as the word TWO above it then it's a zero

alphabetacanary

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Quote from: ooxtcoo on July 06, 2014, 03:13:00 PM

but it looks like a zero in the picture... mhh...

Yes, I agree. It looks more like a zero in the picture. But I'm pretty sure the OP had posted the 1, 2, 3 clue listing with a capital O. But it's gone now.

ooxtcoo

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Quote from: alphabetacanary on July 06, 2014, 03:14:22 PM

6EQUJ5WOW as the shifter produces 5KZnsvHhJEKShKs9LduZvifr1mHVFP8FJAsix6ibkt65VvsDSQU but still not correct.

yes i also treyed that all, but with my wrong code Sad

Topic: ARG Puzzle with 3.5 BTC Private Key Prize, Game Over - page 13. (Read 99503 times)