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Topic: ARG Puzzle with 3.5 BTC Private Key Prize, Game Over - page 20. (Read 99514 times)

arg
newbie
Activity: 14
Merit: 0
Er, maybe I'm on the wrong track.

All of this seems too.. complex.

The solution probably needs to involve a dual sha256 too. That hint is still on the front post.

My pet theory is that the line on the right hand side of Wow.jpeg is somehow the answer, and the 51 character is just a red herring somehow. If it was just a transformation on the "private key" what was the point of the hidden swirls and lines on the image?
sr. member
Activity: 274
Merit: 250
@ pongo

The Doge pic was a joke m8. Smiley
newbie
Activity: 5
Merit: 0
Er, maybe I'm on the wrong track.  In that format, what I got is this:

0x3067c24761f46c1f411ee50a802f9451d04ce566e6c6bca2d0c0d42ba448e5969ca5c2298fc8a 4

which is 312 bits, a bit overqualified to be a private key.
arg
newbie
Activity: 14
Merit: 0
The code from Wow.jpg (z69JZqlJn862D1ndx7oLVEMmVolP1zewEeUCrsI7Roahzpeny7P) maps to the following numbers using the above character mapping:

Code:
61 6 9 19 35 52 47 19 49 8 6 2 13 1 49 39 59 7 50 21 31 14 22 48 31 50 47 25 1 61 40 58 14 40 30 12 53 54 18 7 27 50 36 43 61 51 40 49 60 7 25

Maybe to shift this by 64 to get ASCII characters?

No, that gives you a newline char which I don't think the OP would have used.
legendary
Activity: 1974
Merit: 1077
^ Will code for Bitcoins
The code from Wow.jpg (z69JZqlJn862D1ndx7oLVEMmVolP1zewEeUCrsI7Roahzpeny7P) maps to the following numbers using the above character mapping:

Code:
61 6 9 19 35 52 47 19 49 8 6 2 13 1 49 39 59 7 50 21 31 14 22 48 31 50 47 25 1 61 40 58 14 40 30 12 53 54 18 7 27 50 36 43 61 51 40 49 60 7 25

Maybe to shift this by 64 to get ASCII characters?
newbie
Activity: 5
Merit: 0
Heh, not OP.

Yeah, though isn't it suspicious that the dogecoin symbol is there?  Maybe we're not at the last step and there's something to do with dogecoin?

Here's some quick code I was trying out:



import hashlib, binascii
import sys

__b62chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'
__b62base = len(__b62chars)



def b62decode(v, length):
  """ decode v into a string of len bytes
  """
  long_value = 0
  for (i, c) in enumerate(v[::-1]):
    long_value += __b62chars.find(c) * (__b62base**i)

  result = bytes()
  while long_value >= 256:
    div, mod = divmod(long_value, 256)
    result = chr(mod) + result
    long_value = div
  result = chr(long_value) + result

  nPad = 0
  for c in v:
    if c == __b62chars[0]: nPad += 1
    else: break

  result = chr(0)*nPad + result
  if length is not None and len(result) != length:
    return None

  return result


bytes = b62decode('z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7PA', None)

for byte in bytes:
   # sys.stdout.write("{:02x} ".format(ord(byte)))
   sys.stdout.write("{:08b} ".format(ord(byte)))

arg
newbie
Activity: 14
Merit: 0
That's just using each character as a number.  Did you try converting it to the binary representation?  for example, 11 in base-62 equals the number 63

Tried something like that too.


you'd get a dogecoin private key.

What? We are looking for a Bitcoin key, not dogecoin.
sr. member
Activity: 274
Merit: 250
That's just using each character as a number.  Did you try converting it to the binary representation?  for example, 11 in base-62 equals the number 63

I unfortunately have to leave right now, but my prediction is that if you took z69JZqlJn862D1ndx7oLVEMmV0lP1zewEeUCrsI7Roahzpeny7P and converted it to the binary representation, assuming that's base62, you'd get a dogecoin private key.

Thanks but we are not looking for a Doge priv key.
We have an existing Bitcoin address which is funded so that does not make much sense.
newbie
Activity: 5
Merit: 0
That's just using each character as a number.  Did you try converting it to the binary representation?  for example, 11 in base-62 equals the number 63

I unfortunately have to leave right now, but my prediction is that if you took z69JZqlJn862D1ndx7oLVEMmV0lP1zewEeUCrsI7Roahzpeny7P and converted it to the binary representation, assuming that's base62, you'd get a dogecoin private key.
arg
newbie
Activity: 14
Merit: 0
Maybe it's a form of base-62 encoding like this:

new encoding: 0  1  2  3  4  5  6  7  8  9  A  B  C  D  E  F  G  H  I  J  K  L  M  N  O  P  Q  R  S  T  U  V  W  X  Y  Z  a  b  c  d  e  f  g  h  i  j  k  l  m  n  o  p  q  r  s  t  u  v  w  x  y  z
decimal:      0  1  2  3  4  5  6  7  8  9  10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61


Tried that a day ago.

61 6 9 19 35 52 47 19 49 8 6 2 13 1 49 39 59 7 50 21 31 14 22 48 31 24 47 25 1 61 40 58 14 40 30 12 53 54 18 7 27 50 36 43 61 51 40 49 60 7 25
newbie
Activity: 5
Merit: 0
Maybe it's a form of base-62 encoding like this:

new encoding: 0  1  2  3  4  5  6  7  8  9  A  B  C  D  E  F  G  H  I  J  K  L  M  N  O  P  Q  R  S  T  U  V  W  X  Y  Z  a  b  c  d  e  f  g  h  i  j  k  l  m  n  o  p  q  r  s  t  u  v  w  x  y  z
decimal:      0  1  2  3  4  5  6  7  8  9  10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61
arg
newbie
Activity: 14
Merit: 0
There's an l in the given string so that can't be used to mutate the header key.
member
Activity: 112
Merit: 10
=10BABYA=: Huh? I have been puzzling over this for a while. It might be an end point to stop reading.
tl;dr: I think the real key is to correctly interpret 0=0A=10BABYA=36WOWÐS and z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P .

I'm still not quite sure what to use it on, but I'm pretty sure the 0=0A=10BABYA=36 is a character mapping.
0=0
A=10
BabyA=36. Morse code has no lowercase, so she called the lowercase 'a' BabyA.

OH. It's a description of a base58 character mapping. These are the valid base58 characters. 0 isn't in it, 10 is 10, and a is 36:

edit: Upon closer inspection, I made a transcription error and base62 is far more likely. I agree with pongo below: 0=0, A=10, a=36
full member
Activity: 183
Merit: 100
=10BABYA=: Huh? I have been puzzling over this for a while. It might be an end point to stop reading.

tl;dr: I think the real key is to correctly interpret 0=0A=10BABYA=36WOWÐS and z69JZqlJn862D1ndx7oLVEMmVOlP1zewEeUCrsI7Roahzpeny7P .

I'm still not quite sure what to use it on, but I'm pretty sure the 0=0A=10BABYA=36 is a character mapping.
0=0
A=10
BabyA=36. Morse code has no lowercase, so she called the lowercase 'a' BabyA.

This also jives with the background story for Wow!.jpg. The numbers/letters are intensities:

Quote from: from Wikipedia
The circled alphanumeric code 6EQUJ5 describes the intensity variation of the signal. A space denotes an intensity between 0 and 1, the numbers 1 to 9 denote the correspondingly numbered intensities (from 1.0 to 10.0), and intensities of 10.0 and above are denoted by a letter ('A' corresponds to intensities between 10.0 and 11.0, 'B' to 11.0 to 12.0, etc.). The value 'U' (an intensity between 30.0 and 31.0) was the highest detected by the radio telescope; on a linear scale it was over 30 times louder than normal deep space.

Edit:

The code from Wow.jpg (z69JZqlJn862D1ndx7oLVEMmVolP1zewEeUCrsI7Roahzpeny7P) maps to the following numbers using the above character mapping:

Code:
61 6 9 19 35 52 47 19 49 8 6 2 13 1 49 39 59 7 50 21 31 14 22 48 31 50 47 25 1 61 40 58 14 40 30 12 53 54 18 7 27 50 36 43 61 51 40 49 60 7 25
hero member
Activity: 1582
Merit: 502
Guys does anybody have an image of the crop with the new morse code?



-snip-

Thank you Smiley



How did you guys convert this to morse from binary?

They didnt. It was decoded as binary IIRC

Please explain, because I saw a couple of versions of the code translations and I will like to try myself.

Thank you Smiley
copper member
Activity: 1498
Merit: 1528
No I dont escrow anymore.
Guys does anybody have an image of the crop with the new morse code?



-snip-

Thank you Smiley



How did you guys convert this to morse from binary?

They didnt. It was decoded as binary IIRC

here is the post you are looking for: https://bitcointalksearch.org/topic/m.7662736
hero member
Activity: 1582
Merit: 502
Guys does anybody have an image of the crop with the new morse code?



-snip-

Thank you Smiley



How did you guys convert this to morse from binary?
hero member
Activity: 1582
Merit: 502
Guys does anybody have an image of the crop with the new morse code?



-snip-

Thank you Smiley

arg
newbie
Activity: 14
Merit: 0
Guys does anybody have an image of the crop with the new morse code?



http://i.imgur.com/9fvOEZq.jpg
hero member
Activity: 1582
Merit: 502
Guys does anybody have an image of the crop with the new morse code?

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