Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 322.

racminer

member

Activity: 245

Merit: 17

Quote from: zielar on December 20, 2018, 07:10:34 PM

Quote

174176B015F4D
22BD43C2E9354
75070A1A009D4
EFAE164CB9E3C
180788E47E326C
236FB6D5AD1F44
6ABE1F9B67E114
9D18B63AC4FFDF
1EB25C90795D61C
2C675B852189A21
9?...................... <=== next key trophy

but not good

I have not studied the address space you are talking about because I daresay that even more people are doing it now than I can imagine, so I walked to the indicated threshold. I do not see the point that 100 people would check the same range. I think that as someone wrote earlier here - we could open up a little with each other and somehow cooperate.

Sorry but you are not on the right path; look at the binary pattern:

0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 1BgGZ9tcN4rm9KBzDn7KprQz87SZ26SAMH
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0011 1CUNEBjYrCn2y1SdiUMohaKUi4wpP326Lb
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0111 19ZewH8Kk1PDbSNdJ97FP4EiCjTRaZMZQA
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1000 1EhqbyUMvvs7BfL8goY6qcPbD6YKfPqb7e
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 0101 1E6NuFjCi27W5zoXg8TRdcSRq84zJeBW3k
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0011 0001 1PitScNLyp2HCygzadCh7FveTnfmpPbfp8
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0100 1100 1McVt1vMtCC7yn5b9wgX1833yCcLXzueeC
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1110 0000 1M92tSqNmQLYw33fuBvjmeadirh1ysMBxK
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 1101 0011 1CQFwcjw1dwhtkVWBttNLDtqL7ivBonGPV
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0010 0000 0010 1LeBZP5QCwwgXRtmVUvTVrraqPUokyLHqe
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0100 1000 0011 1PgQVLmst3Z314JrQn5TNiys8Hc38TcXJu
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1010 0111 1011 1DBaumZxUkM4qMQRt2LVWyFJq5kDtSZQot
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 0100 0110 0000 1Pie8JkxBT6MGPz9Nvi3fsPkr2D8q3GBc1
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0010 1001 0011 0000 1ErZWg5cFCe4Vw5BzgfzB74VNLaXEiEkhk
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0110 1000 1111 0011 1QCbW9HWnwQWiQqVo5exhAnmfqKRrCRsvW
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1100 1001 0011 0110 1BDyrQ6WoF8VN3g9SAS1iKZcPzFfnDVieY
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 0111 0110 0100 1111 1HduPEXZRdG26SUT5Yk83mLkPyjnZuJ7Bm
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0011 0000 1000 0000 1101 1GnNTmTVLZiqQfLbAdp9DVdicEnB5GoERE
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0101 0111 0100 1001 1111 1NWmZRpHH4XSPwsW6dsS3nrNWfL1yrJj4w
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1101 0010 1100 0101 0101 1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 1011 1010 0101 0011 0100 14oFNXucftsHiUMY8uctg6N487riuyXs4h
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0010 1101 1110 0100 0000 1111 1CfZWK1QTQE3eS9qn61dQjV89KDjZzfNcv
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0101 0101 0110 1110 0101 0010 1L2GM8eE7mJWLdo3HZS6su1832NX2txaac
0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 1101 1100 0010 1010 0000 0100 1rSnXMr63jdCuegJFuidJqWxUPV7AtUf7
0000 0000 0000 0000 0000 0000 0000 0000 0000 0001 1111 1010 0101 1110 1110 0101 15JhYXn6Mx3oF4Y7PcTAv2wVVAuCFFQNiP
0000 0000 0000 0000 0000 0000 0000 0000 0000 0011 0100 0000 0011 0010 0110 1110 1JVnST957hGztonaWK6FougdtjxzHzRMMg
0000 0000 0000 0000 0000 0000 0000 0000 0000 0110 1010 1100 0011 1000 0111 0101 128z5d7nN7PkCuX5qoA4Ys6pmxUYnEy86k
0000 0000 0000 0000 0000 0000 0000 0000 0000 1101 1001 0001 0110 1100 1110 1000 12jbtzBb54r97TCwW3G1gCFoumpckRAPdY
0000 0000 0000 0000 0000 0000 0000 0000 0001 0111 1110 0010 0101 0101 0001 1110 19EEC52krRUK1RkUAEZmQdjTyHT7Gp1TYT
0000 0000 0000 0000 0000 0000 0000 0000 0011 1101 1001 0100 1100 1101 0110 0100 1LHtnpd8nU5VHEMkG2TMYYNUjjLc992bps
0000 0000 0000 0000 0000 0000 0000 0000 0111 1101 0100 1111 1110 0111 0100 0111 1LhE6sCTuGae42Axu1L1ZB7L96yi9irEBE
0000 0000 0000 0000 0000 0000 0000 0000 1011 1000 0110 0010 1010 0110 0010 1110 1FRoHA9xewq7DjrZ1psWJVeTer8gHRqEvR
0000 0000 0000 0000 0000 0000 0000 0001 1010 1001 0110 1100 1010 1000 1101 1000 187swFMjz1G54ycVU56B7jZFHFTNVQFDiu
0000 0000 0000 0000 0000 0000 0000 0011 0100 1010 0110 0101 1001 0001 0001 1101 1PWABE7oUahG2AFFQhhvViQovnCr4rEv7Q
0000 0000 0000 0000 0000 0000 0000 0100 1010 1110 1101 0010 0001 0001 0111 0000 1PWCx5fovoEaoBowAvF5k91m2Xat9bMgwb
0000 0000 0000 0000 0000 0000 0000 1001 1101 1110 1000 0010 0000 1010 0111 1100 1Be2UF9NLfyLFbtm3TCbmuocc9N1Kduci1
0000 0000 0000 0000 0000 0000 0001 0111 0101 0111 0111 0101 0110 1010 1001 0011 14iXhn8bGajVWegZHJ18vJLHhntcpL4dex
0000 0000 0000 0000 0000 0000 0010 0010 0011 1000 0010 1111 1010 1100 1101 0000 1HBtApAFA9B2YZw3G2YKSMCtb3dVnjuNe2
0000 0000 0000 0000 0000 0000 0100 1011 0101 1111 1000 0011 0000 0011 1110 1001 122AJhKLEfkFBaGAd84pLp1kfE7xK3GdT8
0000 0000 0000 0000 0000 0000 1110 1001 1010 1110 0100 1001 0011 0011 1101 0110 1EeAxcprB2PpCnr34VfZdFrkUWuxyiNEFv
0000 0000 0000 0000 0000 0001 0101 0011 1000 0110 1001 1010 1100 1100 0101 1011 1L5sU9qvJeuwQUdt4y1eiLmquFxKjtHr3E
0000 0000 0000 0000 0000 0010 1010 0010 0010 0001 1100 0101 1000 1101 1000 1111 1E32GPWgDyeyQac4aJxm9HVoLrrEYPnM4N
0000 0000 0000 0000 0000 0110 1011 1101 0011 1011 0010 0111 1100 0101 1001 0001 1PiFuqGpG8yGM5v6rNHWS3TjsG6awgEGA1
0000 0000 0000 0000 0000 1110 0000 0010 1011 0011 0101 1010 0011 0101 1000 1111 1CkR2uS7LmFwc3T2jV8C1BhWb5mQaoxedF
0000 0000 0000 0000 0001 0010 0010 1111 1100 1010 0001 0100 0011 1100 0000 0101 1NtiLNGegHWE3Mp9g2JPkgx6wUg4TW7bbk
0000 0000 0000 0000 0010 1110 1100 0001 1000 0011 1000 1000 1101 0101 0100 0100 1F3JRMWudBaj48EhwcHDdpeuy2jwACNxjP
0000 0000 0000 0000 0110 1100 1101 0110 0001 0000 1011 0101 0011 1100 1011 1010 1Pd8VvT49sHKsmqrQiP61RsVwmXCZ6ay7Z
0000 0000 0000 0000 1010 1101 1110 0110 1101 0111 1100 1110 0011 1011 1001 1011 1DFYhaB2J9q1LLZJWKTnscPWos9VBqDHzv
0000 0000 0000 0001 0111 0100 0001 0111 0110 1011 0000 0001 0101 1111 0100 1101 12CiUhYVTTH33w3SPUBqcpMoqnApAV4WCF
0000 0000 0000 0010 0010 1011 1101 0100 0011 1100 0010 1110 1001 0011 0101 0100 1MEzite4ReNuWaL5Ds17ePKt2dCxWEofwk
0000 0000 0000 0111 0101 0000 0111 0000 1010 0001 1010 0000 0000 1001 1101 0100 1NpnQyZ7x24ud82b7WiRNvPm6N8bqGQnaS
0000 0000 0000 1110 1111 1010 1110 0001 0110 0100 1100 1011 1001 1110 0011 1100 15z9c9sVpu6fwNiK7dMAFgMYSK4GqsGZim
0000 0000 0001 1000 0000 0111 1000 1000 1110 0100 0111 1110 0011 0010 0110 1100 15K1YKJMiJ4fpesTVUcByoz334rHmknxmT
0000 0000 0010 0011 0110 1111 1011 0110 1101 0101 1010 1101 0001 1111 0100 0110 19LeLQDmSR8nxFa4v7UdX9SC41mdxP6Rx9
0000 0000 0110 1010 1011 1110 0001 1111 1001 1011 0110 0111 1110 0001 0001 0100 1LzhS3k3e9Ub8i2W1V8xQFdB8n2MYCHPCa
0000 0000 1001 1101 0001 1000 1011 0110 0011 1010 1100 0100 1111 1111 1101 1111 17aPYR1m6pVAacXg1PTDDU7XafvK1dxvhi
0000 0001 1110 1011 0010 0101 1100 1001 0000 0111 1001 0101 1101 0110 0001 1100 15c9mPGLku1HuW9LRtBf4jcHVpBUt8txKz
0000 0010 1100 0110 0111 0101 1011 1000 0101 0010 0001 1000 1001 1010 0010 0001 1Dn8NF8qDyyfHMktmuoQLGyjWmZXgvosXf
0000 01xx 1HAX2n9Uruu9YDt4cqRgYcvtGvZj1rbUyt
0000 1xxx 1Kn5h2qpgw9mWE5jKpk8PP4qvvJ1QVy8su

Each key has one higher bit (equal to 1) than the previous key. You cannot have a key starting with 9 for case #59.
case #59 starts with either a 4,5,6 or 7
case #60 starts with either 8,9,A,B,C,D,E or F

So if you are right, you scanned 1/8th the range of case #60 ... how long did it take you and how many and what kind of GPU's do you run?

zielar

full member

Activity: 282

Merit: 114

Quote

174176B015F4D
22BD43C2E9354
75070A1A009D4
EFAE164CB9E3C
180788E47E326C
236FB6D5AD1F44
6ABE1F9B67E114
9D18B63AC4FFDF
1EB25C90795D61C
2C675B852189A21
9?...................... <=== next key trophy

but not good

I have not studied the address space you are talking about because I daresay that even more people are doing it now than I can imagine, so I walked to the indicated threshold. I do not see the point that 100 people would check the same range. I think that as someone wrote earlier here - we could open up a little with each other and somehow cooperate.

racminer

member

Activity: 245

Merit: 17

Quote from: zielar on December 20, 2018, 11:30:08 AM

After full scan keyspace 0000000000000000000000000000000000000000000000000900000000000000 - 00000000000000000000000000000000000000000000000009FFFFFFFFFFFFFF
I can share with you the knowledge of the fact that the private key to the next address (and to others also) is NOT in it. Maybe someone will say that I should not give such knowledge, but I say that I do not lose any benefit by sharing this knowledge, because I have not invested in it to be able to participate in it, and it makes no sense that someone would waste time on something that has already been tested . If someone has a type for the next scan, I would like to take care of it because I missed ideas ... poki what I'm starting on the continuation of the end of the previous scope and I'm going to space

Thank you, but why did you scan the range
900000000000000-9FFFFFFFFFFFFFFFF
instead of
400000000000000-7FFFFFFFFFFFFFFFF
where private key of puzzle #59 is expected???

zielar

full member

Activity: 282

Merit: 114

After full scan keyspace 0000000000000000000000000000000000000000000000000900000000000000 - 00000000000000000000000000000000000000000000000009FFFFFFFFFFFFFF
I can share with you the knowledge of the fact that the private key to the next address (and to others also) is NOT in it. Maybe someone will say that I should not give such knowledge, but I say that I do not lose any benefit by sharing this knowledge, because I have not invested in it to be able to participate in it, and it makes no sense that someone would waste time on something that has already been tested . If someone has a type for the next scan, I would like to take care of it because I missed ideas ... poki what I'm starting on the continuation of the end of the previous scope and I'm going to space

Elliptic23

newbie

Activity: 22

Merit: 3

Quote from: KingZee on December 19, 2018, 10:30:17 PM

I tried to read as much as I can from this thread. I understood how each subsequent key has a bigger interval than the one before it, but I don't understand how the highest keys were also spent?

If this was the hex for the 57th key :
0x00000000000000000000000000000000000000000000000001eb25c90795d61c

which I assume is a random between (57bits)1FFFFFFFFFFFFFF and 100000000000000.

How were the highest outputs spent? Wouldn't they be extremely hard to find because of the massive 256-bit max range? I don't get it..

The creator still knows the private keys. Theres a post around here with him explaining what he did.

He realized that the 161 to 256 bit puzzles are pointless since they will never be more difficult than 160 bits as there are only 2^160 possible addresses. So he moved the funds from those puzzles into the lower puzzles.

KingZee

sr. member

Activity: 938

Merit: 452

Check your coin privilege

I tried to read as much as I can from this thread. I understood how each subsequent key has a bigger interval than the one before it, but I don't understand how the highest keys were also spent?

If this was the hex for the 57th key :
0x00000000000000000000000000000000000000000000000001eb25c90795d61c

which I assume is a random between (57bits)1FFFFFFFFFFFFFF and 100000000000000.

How were the highest outputs spent? Wouldn't they be extremely hard to find because of the massive 256-bit max range? I don't get it..

itod

legendary

Activity: 1974

Merit: 1077

Honey badger just does not care

Quote from: zielar on December 17, 2018, 12:09:39 PM

I would like to know someone who is sitting longer in the subject - does the correct correct private key exist in equal intervals in the HEX format? What I mean here is whether, for example, if we set a certain value "- stride" on the command line, would it not affect the advantage of searching?

Random. No patterns, no intervals, that's what random means.

zielar

full member

Activity: 282

Merit: 114

I would like to know someone who is sitting longer in the subject - does the correct correct private key exist in equal intervals in the HEX format? What I mean here is whether, for example, if we set a certain value "- stride" on the command line, would it not affect the advantage of searching?

itod

legendary

Activity: 1974

Merit: 1077

Honey badger just does not care

Quote from: racminer on December 14, 2018, 12:59:18 AM

Quote from: itod on December 13, 2018, 05:58:37 PM

Quote from: racminer on December 13, 2018, 04:17:25 PM

Quote from: itod on December 13, 2018, 02:07:35 PM

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

hi

Why on earth people have sent BTC here: https://www.blockchain.com/btc/address/1BitcoinEaterAddressDontSendf59kuE from 2011-06-21 up to 2018-11-02

13.22016611 BTC

Huh

Amazing ignorance.

Because they can, and it says "Do not send". What is confusing you here?

You realize these 13.22016611 BTC are lost forever?

What is confusing me is that's your own wallet !
it seems that you have lost 13.22 BTC forever ... too bad.

(Well, maybe not 13.22 since your profile here was created on may 2013)

ROFL

racminer

member

Activity: 245

Merit: 17

Quote from: itod on December 13, 2018, 05:58:37 PM

Quote from: racminer on December 13, 2018, 04:17:25 PM

Quote from: itod on December 13, 2018, 02:07:35 PM

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

hi

Why on earth people have sent BTC here: https://www.blockchain.com/btc/address/1BitcoinEaterAddressDontSendf59kuE from 2011-06-21 up to 2018-11-02

13.22016611 BTC

Huh

Amazing ignorance.

Because they can, and it says "Do not send". What is confusing you here?

You realize these 13.22016611 BTC are lost forever?

What is confusing me is that's your own wallet !
it seems that you have lost 13.22 BTC forever ... too bad.

(Well, maybe not 13.22 since your profile here was created on may 2013)

itod

legendary

Activity: 1974

Merit: 1077

Honey badger just does not care

Quote from: racminer on December 13, 2018, 04:17:25 PM

Quote from: itod on December 13, 2018, 02:07:35 PM

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

hi

Why on earth people have sent BTC here: https://www.blockchain.com/btc/address/1BitcoinEaterAddressDontSendf59kuE from 2011-06-21 up to 2018-11-02

13.22016611 BTC

Huh

Amazing ignorance.

Because they can, and it says "Do not send". What is confusing you here?

You realize these 13.22016611 BTC are lost forever?

racminer

member

Activity: 245

Merit: 17

Quote from: racminer on December 12, 2018, 08:09:22 AM

Hi

I have a suggestion to everyone here interested in solving case #59
We know for sure that the private key looks like:

04XX PPPP PPPP PPPP or
05XX PPPP PPPP PPPP or
06XX PPPP PPPP PPPP or
07XX PPPP PPPP PPPP

the range PPPP PPPP PPPP can be scanned with a single RX480 using bitcrack in about ten days

from 400 to 7FF we have 1023 possibles cases

we could split the workload and create a peer to peer method (via private messages here + trust + honesty Roll Eyes

) and exchange ruled out scanned ranges.
the lucky one will get the prize

anyone interested?

the range PPPP PPPP PPPP can be scanned with a single 2080 using bitcrack in about one day Wink

https://bitcointalksearch.org/topic/m.48444413

PietCoin97

jr. member

Activity: 91

Merit: 3

Quote from: itod on December 13, 2018, 02:07:35 PM

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

hahaha yes i know what random means but i like the thoughts of Andzhig

racminer

member

Activity: 245

Merit: 17

Quote from: itod on December 13, 2018, 02:07:35 PM

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

hi

Why on earth people have sent BTC here: https://www.blockchain.com/btc/address/1BitcoinEaterAddressDontSendf59kuE from 2011-06-21 up to 2018-11-02

13.22016611 BTC

Huh

Amazing ignorance.

Andzhig

jr. member

Activity: 184

Merit: 3

Quote

When you find the puzzel 59 with your success Formular it will be easy for you to find the other ones?

do not know, it is necessary to find first)).

Quote

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

This we know. But at the time of the puzzle, in early 2015, there were still no powerful graphics cards and programs for finding Bitcoin addresses on them. The speed of 1 2080 is impressive https://bitcointalksearch.org/topic/m.48444413

itod

legendary

Activity: 1974

Merit: 1077

Honey badger just does not care

Do you newbies know what "random" means?

Although the private keys you are talking about are generated with pseudorandom algorithm, it's obvious creator of this puzzle knew what he was doing, and this means he used enough entropy that these laughable experiments with walls of numbers where you try to find some pattern makes as much sense as trying to get in earths orbit by jumping up as hard as you can.

Amazing ignorance.

PietCoin97

jr. member

Activity: 91

Merit: 3

When you find the puzzel 59 with your success Formular it will be easy for you to find the other ones?

Andzhig

jr. member

Activity: 184

Merit: 3

Quote

do you still have doubts ?

clearly, understood, thx.

***

Another option to try your luck.

288230376151711744-576460752303423488 our range.

success formula.

144115188075855872 - ((((((((((1,9850114 * 128) * 128) * 128) * 128) * 128) * 128) * 128) * 128) - 142989288169013248) * 128) = ~138245434111601493 - 138245758910846492 = 324799244999 < scan residue
288230376151711744 - ((((((((((3,9783185 * 128) * 128) * 128) * 128) * 128) * 128) * 128) * 128) - 285978576338026496) * 128) = ~199976540817066822 - 199976667976342049 = 127159275227 < scan residue
576460752303423488 - ((((((((((7,9456789 * 128) * 128) * 128) * 128) * 128) * 128) * 128) * 128) - 571957152676052992) * 128) =

   63

101 3,9783185 2
111 1,9850114 4

   56 sec 49 sec 42 sec
100 127,38634167733380354869954231845 1 101 127,27325883491753266696377977496 2 101 127,34166804622168456262443214655 1
110 63,583036446150909604124734642028 3 101 63,660348182749885381781496107578 1 101 63,668431836413219571113586425781 1
100 31,861576626618332619411688710898 0 110 31,787429311634468831471167504787 3 111 31,771796089393319562077522277832 4
110 15,90613502904471082688431238239 2 101 15,908679856821891007712110877037 2 100 15,926393464003922417759895324707 0
111 7,941484368221046585833988729064 4 100 7,9644791460323176579549908638 0 100 7,966582541557727381587028503418 0
111 3,97142883352349745       4 111 3,9726356460934955094899123650976 4 101 3,9699310258729383349418640136719 2
100 1,9915187218734213270288080366299 0 110 1,9868375314665325248597582685761 3 100 1,990362136945805104915052652359 1

   35 28 21
100 127,41463838936761021614074707031 0 110 127,1519957482814788818359375 3 110 127,1361083984375
110 63,588673464953899383544921875 3 110 63,58295440673828125 3 110 63,58837890625
110 31,7922732196748256683349609375 3 110 31,7968273162841796875 3 101 31,82952880859375
101 15,90996809303760528564453125 2 111 15,876374721527099609375 5 110 15,9052734375
111 7,938812442123889923095703125 4 110 7,9462490081787109375 3 101 7,954345703125
111   3,979142837226390838623046875 4 101 3,97543811798095703125 110 3,97543811798095703125
101 1,9883378362865187227725982666016 2 101 1,9887961782515048980712890625 110 1,987188816070556640625

binary representations of the first 7 digits, after the comma. 1,9...3,9...7,9...15,9... (15.blabla - 127.blabla We are not taking yet.) And we look at coincidences.

          63

10010101 01000111 10010001 (3,9783185 > 9783185 > 100101010100011110010001)
10010110 01001101 00000010 (1,9850114 > 9850114 > 100101100100110100000010)

          56

10001010 01000011 11100110 10001010 10100111 01001110 10001101 01011011 00111110
10001111 10101000 10111011 10010011 00101010 11110111 10010011 01111101 00100001
10010100 00111010 01110000 10010100 01101001 10010100 10010011 11111111 11101110
10010111 01001011 00110011 10010110 10010100 01010111 10010111 00011110 00000101

10001010 11011001 10100000 10000101 10111001 01100011 10001010 00100010 00111110
10001111 01000000 01011100 10010000 01100010 11011010 10010001 10011111 00100001
10010101 01100111 11000100 10010100 11010111 00001101 10010100 11010111 00001101
10010110 11001110 11110010 10010110 11100000 11011001 10010110 10100010 00010000

Let's say we have a repeat 10001111 we get an approximate range 510000000000000000-550000000000000000. At 10010011 290000000000000000-340000000000000000.

with clarification, on all possible ranges.

10001111 553000000000000000-580000000000000000 if after 9 comes 3 > 7,93... too high
10001111 519000000000000000-554000000000000000 if after 9 comes 4 > 7,94...
10010000 460000000000000001-520000000000000000 if after 9 comes 4 > 7,94...
10010000 458000000000000000-462000000000000000 if after 9 comes 5 > 7,95...
10010001 390000000000000000-460000000000000000 if after 9 comes 5 > 7,95...
10010010 369000000000000000-400000000000000000 if after 9 comes 5 > 7,95... did not appear yet
10010010 337000000000000000-369000000000000000 if after 9 comes 6 > 7,96... did not appear yet
10010011 270000000000000000-338000000000000000 if after 9 comes 6 > 7,96... too low

if after 9 comes 7,9 012...789 fall out of range, 012 > 576460752303423488,789 < 288230376151711744. As we see 10010010 have not participated anywhere yet (unless on initial puzzles).

Most likely range from 10010001 390000000000000000 to 10001111 554000000000000000. 390000000000000000-554000000000000000.

***

python 3 script

Quote

from bitcoin import *
import random
import subprocess
import time
from decimal import *
#from PyRandLib import *
#rand = FastRand63()
#random.seed(rand())

l1= [("10001111"),("10010000"),("10010001")]

l2= [("10000000"),("10000001"),("10000010"),("10000011"),("10000100"),("10000101"),("10000110"),("10000111"),
   ("10001000"),("10001001"),("10001010"),("10001011"),("10001100"),("10001101"),("10001110"),("10001111"),
   ("10010000"),("10010001"),("10010010"),("10010011"),("10010100"),("10010101"),("10010110"),("10010111"),
   ("10011000"),("10011001"),("10011010"),("10011011"),("10011100"),("10011101"),("10011110"),("10011111"),
   ("10100000"),("10100001"),("10100010"),("10100011"),("10100100"),("10100101"),("10100110"),("10100111"),
   ("10101000"),("10101001"),("10101010"),("10101011"),("10101100"),("10101101"),("10101110"),("10101111"),
   ("10110000"),("10110001"),("10110010"),("10110011"),("10110100"),("10110101"),("10110110"),("10110111"),
   ("10111000"),("10111001"),("10111010"),("10111011"),("10111100"),("10111101"),("10111110"),("10111111"),
   ("11000000"),("11000001"),("11000010"),("11000011"),("11000100"),("11000101"),("11000110"),("11000111"),
   ("11001000"),("11001001"),("11001010"),("11001011"),("11001100"),("11001101"),("11001110"),("11001111"),
   ("11010000"),("11010001"),("11010010"),("11010011"),("11010100"),("11010101"),("11010110"),("11010111"),
   ("11011000"),("11011001"),("11011010"),("11011011"),("11011100"),("11011101"),("11011110"),("11011111"),
   ("11100000"),("11100001"),("11100010"),("11100011"),("11100100"),("11100101"),("11100110"),("11100111"),
   ("11101000"),("11101001"),("11101010"),("11101011"),("11101100"),("11101101"),("11101110"),("11101111"),
   ("11110000"),("11110001"),("11110010"),("11110011"),("11110100"),("11110101"),("11110110"),("11110111"),
   ("11111000"),("11111001"),("11111010"),("11111011"),("11111100"),("11111101"),("11111110"),("11111111"),
   ("00000000"),("00000001"),("00000010"),("00000011"),("00000100"),("00000101"),("00000110"),("00000111"),
   ("00001000"),("00001001"),("00001010"),("00001011"),("00001100"),("00001101"),("00001110"),("00001111"),
   ("00010000"),("00010001"),("00010010"),("00010011"),("00010100"),("00010101"),("00010110"),("00010111"),
   ("00011000"),("00011001"),("00011010"),("00011011"),("00011100"),("00011101"),("00011110"),("00011111"),
   ("00100000"),("00100001"),("00100010"),("00100011"),("00100100"),("00100101"),("00100110"),("00100111"),
   ("00101000"),("00101001"),("00101010"),("00101011"),("00101100"),("00101101"),("00101110"),("00101111"),
   ("00110000"),("00110001"),("00110010"),("00110011"),("00110100"),("00110101"),("00110110"),("00110111"),
   ("00111000"),("00111001"),("00111010"),("00111011"),("00111100"),("00111101"),("00111110"),("00111111"),
   ("01000000"),("01000001"),("01000010"),("01000011"),("01000100"),("01000101"),("01000110"),("01000111"),
   ("01001000"),("01001001"),("01001010"),("01001011"),("01001100"),("01001101"),("01001110"),("01001111"),
   ("01010000"),("01010001"),("01010010"),("01010011"),("01010100"),("01010101"),("01010110"),("01010111"),
   ("01011000"),("01011001"),("01011010"),("01011011"),("01011100"),("01011101"),("01011110"),("01011111"),
   ("01100000"),("01100001"),("01100010"),("01100011"),("01100100"),("01100101"),("01100110"),("01100111"),
   ("01101000"),("01101001"),("01101010"),("01101011"),("01101100"),("01101101"),("01101110"),("01101111"),
   ("01110000"),("01110001"),("01110010"),("01110011"),("01110100"),("01110101"),("01110110"),("01110111"),
   ("01111000"),("01111001"),("01111010"),("01111011"),("01111100"),("01111101"),("01111110"),("01111111")]

def ran1():
   nnn1 = str(random.choice(l1))
   return nnn1

def ran2():
   nnn2 = str(random.choice(l2))
   return nnn2

while 1 == 1:
   i = 1
   while i <= 100000:
   a = str("7.")
   bina = (ran1()+ran2()+ran2())
   nuli = bina.count("0")
   if nuli != 100:
   comb1 = int(bina,2)
   if comb1 >= 9400000:
   if comb1 <= 9680000:
   deccomb1 = str(comb1)
   comb2 = Decimal(a+deccomb1)
   deccomb2 = int(576460752303423488 - ((((((((((comb2 * 128) * 128) * 128) * 128) * 128) * 128) * 128) * 128) - 571957152676052992) * 128))
   if deccomb2 >= 390000000000000000:
   if deccomb2 <= 554000000000000000:
   ran = deccomb2
   myhex = "%064x" % ran
   myhex = myhex[:64]
   priv = myhex
   pub = privtopub(priv)
   pubkey1 = encode_pubkey(privtopub(priv), "bin_compressed")
   addr = pubtoaddr(pubkey1)

   oy = """cd "C:\crackbit" """
   ey = "\nstart /min cuBitCrack.exe -d 0 -i addr.txt -o find.txt -c -b 32 -t 256 -p 512 -s " # bitcrack settings
   f=open("C:/testpy.cmd","w")
   f.write (oy)
   f.write (ey)
   f.write (priv)
   f.close()

   subprocess.Popen([r"C:/testpy.cmd"])

   print(bina,nuli,comb1,deccomb1,comb2,deccomb2,bin(deccomb2)[2:])

   time.sleep(0.1)



   time.sleep(1200.0) # break between restarts, scan time, in sec, 1200 sec > 20 min.
   subprocess.call("taskkill /IM cuBitCrack.exe")
   i = i+1

   pass

[/size]

racminer

member

Activity: 245

Merit: 17

Quote from: Andzhig on December 12, 2018, 11:33:02 AM

Quote from: racminer on December 12, 2018, 08:09:22 AM

Hi

I have a suggestion to everyone here interested in solving case #59
We know for sure that the private key looks like:

04XX PPPP PPPP PPPP or
05XX PPPP PPPP PPPP or
06XX PPPP PPPP PPPP or
07XX PPPP PPPP PPPP

the range PPPP PPPP PPPP can be scanned with a single RX480 using bitcrack in about ten days

from 400 to 7FF we have 1023 possibles cases

we could split the workload and create a peer to peer method (via private messages here + trust + honesty Roll Eyes

) and exchange ruled out scanned ranges.
the lucky one will get the prize

anyone interested?

It is unlikely, here, to find a sufficient number of people willing, so that from this idea it would turn out to be something worthwhile. Moreover, no need to reinvent the wheel, LBC already exists. And I am tormented by vague doubts that there is such a number (I think it's a "little" more.). "from 400 to 7FF we have 1023 possibles cases"

Of course I am aware of LBC

but what I suggest is not the same spirit. About the 1023 cases, it is oubious

no need to get "tormented by vague doubts", it's just simple arithmetic.
( 07FF FFFF FFFF FFFF - 0400 0000 0000 0000 ) = 288230376151711743 keys
FFFF FFFF FFFF = 281474976710655

288230376151711743/(281474976710655+1) = 1023

do you still have doubts ?

Andzhig

jr. member

Activity: 184

Merit: 3

Quote from: racminer on December 12, 2018, 08:09:22 AM

Hi

I have a suggestion to everyone here interested in solving case #59
We know for sure that the private key looks like:

04XX PPPP PPPP PPPP or
05XX PPPP PPPP PPPP or
06XX PPPP PPPP PPPP or
07XX PPPP PPPP PPPP

the range PPPP PPPP PPPP can be scanned with a single RX480 using bitcrack in about ten days

from 400 to 7FF we have 1023 possibles cases

we could split the workload and create a peer to peer method (via private messages here + trust + honesty Roll Eyes

) and exchange ruled out scanned ranges.
the lucky one will get the prize

anyone interested?

It is unlikely, here, to find a sufficient number of people willing, so that from this idea it would turn out to be something worthwhile. Moreover, no need to reinvent the wheel, LBC already exists. And I am tormented by vague doubts that there is such a number (I think it's a "little" more.). "from 400 to 7FF we have 1023 possibles cases"

Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 322. (Read 240068 times)