Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it - page 367. (Read 253308 times)

are you serious it may take decades?  seriously  and the way technology is improving you think that in decades from now we will be relaying on tech from 2009.  wise up if the 20 years the tech to break bitcoin has improved so will the tech to have improved bitcoin security.

Like antonantonopolus says the inventioin is out of the box, it cant be put back in. "worst case senario bitcoin breaks and tomorrow we start a new crypto with all the failures of bitcoiin sorted"..... YES  and yes those who new about crypto get in at the bottom.........

Probably only two guys know that (who cracked and who owns), and they are probably not among us in this forum.

Let us assume that there is some sort of mathematical formula to solve this puzzle.

That's the only way we will ever be able to solve this puzzle during our lifetime.

I strongly recommend to all the mathematical experts out there to have a look at this sequence, maybe they are able to find something.

All of this story tell us something.

We now know that someone out there is able to crack aprox. 2^50 private keys in about 1 year.

(in a worst case scenario, also assuming that the one who cracked the 50 addresses brute forced all the possible addresses sequential)

As time goes by this capability will increase, it may take decades and decades or centuries but eventually it will be possible to crack 2^256 pvks.

The transaction referenced in this thread is a good reference to test how far the mankind cracking capabilities are.

As of now, we can enjoy the safety of bitcoin for a long long time

2^1   2   
2^2   4   
2^3   8   
2^4   16   
2^5   32   
2^6   64   
2^7   128   
2^8   256   
2^9   512   
2^10   1024   
2^11   2048   
2^12   4096   
2^13   8192   
2^14   16384   
2^15   32768   
2^16   65536   
2^17   131072   
2^18   262144   
2^19   524288   
2^20   1048576   
2^21   2097152   
2^22   4194304   
2^23   8388608   
2^24   16777216   
2^25   33554432   
2^26   67108864   
2^27   134217728   
2^28   268435456   
2^29   536870912   
2^30   1073741824   
2^31   2147483648   
2^32   4294967296   
2^33   8589934592   
2^34   17179869184   
2^35   34359738368   
2^36   68719476736   
2^37   137438953472   
2^38   274877906944   
2^39   549755813888   
2^40   1099511627776   
2^41   2199023255552   
2^42   4398046511104   
2^43   8796093022208   
2^44   17592186044416   
2^45   35184372088832   
2^46   70368744177664   
2^47   140737488355328   
2^48   281474976710656   
2^49   562949953421312   
2^50   1125899906842620   <- This is aprox. the number of bitcoins private keys someone is able to crack in about 1 year
2^51   2251799813685250   
2^52   4503599627370500   
2^53   9007199254740990   
2^54   18014398509482000   
2^55   36028797018964000   
2^56   72057594037927900   
2^57   144115188075856000   
2^58   288230376151712000   
2^59   576460752303423000   
2^60   1152921504606850000   
2^61   2305843009213690000   
2^62   4611686018427390000   
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2^73   9444732965739290000000   
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2^141   2787593149816330000000000000000000000000000   
2^142   5575186299632660000000000000000000000000000   
2^143   11150372599265300000000000000000000000000000   
2^144   22300745198530600000000000000000000000000000   
2^145   44601490397061200000000000000000000000000000   
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2^168   374144419156711000000000000000000000000000000000000   
2^169   748288838313422000000000000000000000000000000000000   
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2^171   2993155353253690000000000000000000000000000000000000   
2^172   5986310706507380000000000000000000000000000000000000   
2^173   11972621413014800000000000000000000000000000000000000   
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2^188   392318858461668000000000000000000000000000000000000000000   
2^189   784637716923335000000000000000000000000000000000000000000   
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2^241   3533694129556770000000000000000000000000000000000000000000000000000000000   
2^242   7067388259113540000000000000000000000000000000000000000000000000000000000   
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2^244   28269553036454100000000000000000000000000000000000000000000000000000000000   
2^245   56539106072908300000000000000000000000000000000000000000000000000000000000   
2^246   113078212145817000000000000000000000000000000000000000000000000000000000000   
2^247   226156424291633000000000000000000000000000000000000000000000000000000000000   
2^248   452312848583266000000000000000000000000000000000000000000000000000000000000   
2^249   904625697166533000000000000000000000000000000000000000000000000000000000000   
2^250   1809251394333070000000000000000000000000000000000000000000000000000000000000   
2^251   3618502788666130000000000000000000000000000000000000000000000000000000000000   
2^252   7237005577332260000000000000000000000000000000000000000000000000000000000000   
2^253   14474011154664500000000000000000000000000000000000000000000000000000000000000   
2^254   28948022309329000000000000000000000000000000000000000000000000000000000000000   
2^255   57896044618658100000000000000000000000000000000000000000000000000000000000000   
2^256   115792089237316000000000000000000000000000000000000000000000000000000000000000   <- And this is how safe bitcoin is.

thats why i still like this forum. topics like this are a pleasure to follow.

keep going and solve this.

50 addresses have been cleaned out so far. The integers for the first 24 private keys have been posted.
Could anyone post the pvks for 25 to 50?

My guess is that the same person conducting the above is the same person who started this thread and requesting tips. Then again, it's probably just me seeing things that aren't there. HAHAHA

Given how long it is going on and first 50 rewards claimed already, it becomes economically unjustificable to keep brute forcing giving the number of tries you need to do going up almost exponencionally. But maybe someone still bruteforcing the 51st reward with modified oclvanityminer...

There may, or may not be an actual pattern to the values, but that "close to the double of the previous value" would occur if you simply chose a completely random number from a set with 1 additional binary digit at each level.

Effectively each new private key would be a number of binary digits equivalent to the number of milibitcoins stored at the address with the first digit being a 1.

The answer to life, the universe and everything in it......

Watching this interesting thread, good luck !

This drama cannot be created with fiat money. Huge kudos to the person who provided the challenges.

The Russians always get it first


You got all the work done right there until the #24, nicely done

Exactly.

I think the best is if we find a mathematical formula for the sequence (if it really exists).

For example, if you look at the decimal values, they seem to be always close to the double of the previous value, excluding the first few values.


Exactly.

By the way, address 20:

KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rHfuE2Tg4nJW
1HsMJxNiV7TLxmoF6uJNkydxPFDog4NQum
pvk decimal value: 863317
pvk hex value: D2C55

So these are the decimal values we have:

Address 2: 3
Address 3: 7
Address 4: 8
Address 5: 21
Address 6: 49
Address 7: 76
Address 8: 224
Address 9: 467
Address 10: 514
Address 11: 1155
Address 12: 2683
Address 13: 5216
Address 14: 10544
Address 15: 26867
Address 16: 51510
Address 17: 95823
Address 18: 198669
Address 19: 357535
Address 20: 863317
Address 21: ?


Yes, that's a lot of brute force right there  

no ones offering it, its just there

I posted this puzzle transaction in January'15
https://bitcointalksearch.org/topic/--932434

(This tx was not sent by me)

Let me translate from Russian into English the main point in my prevoius post:

First output: take random number from 2⁰ upto 2¹-1, use it as private key
Second output: take random number from 2¹ upto 2²-1, use it as private key
Third output: take random number from 2² upto 2³-1, use it as private key
And so on...

Only 50 of the 256 addresses are claimed 31 BTC remain.

so does that mean someone has cracked the puzzle? and claimed all (or most) of the 32 BTC?

The interesting thing is that addresses #1 - #46 were cleaned out in January 2015. Then nothing for many months. Then on Sep 1 2015 #47, #48, #49 and #50 were almost simultaneously cleaned out.

Now I understand, thank you for your informative posts DannyHamilton, I think most of my doubts are no more. I guess this "puzzle" was meant to be unbroken after a certain point

At least we can now see that there are better ways to work for those 32 BTC instead of attempting to break this