We just bounced back below $60k after insufficient reasons to make the next challenge on SEC issues regarding bitcoin ETF correction and noa does not include bitcoin weakening factors now. I still believe the tunnel is getting wider to $79k right in November when the taproot will start. Obviously when the bitcoin price is at $60k, it can't be guaranteed that traders can easily find deep profits, it will trigger a larger accumulation of holdings. Proof that the transaction volume of bitcoin will decrease. It is a normal element
right, bitcoin has always done something like that several times, when it has increased there will be a correction to then bounce back. it seems that this has become a habit that is done by bitcoin and of course if those who do not see the nature of bitcoin have experienced excessive fear. even though there should be no need to be nervous and afraid in dealing with bitcoin and we are based on the habits that have been done.
Before entering the month of November to increase according to what you said, at least come back from the predicted increase that occurred in 2013 and 2017 where are the details;
Year | Month | Percentage | Remarks |
2021 | October | 44.11% | update |
2017 | October | 47.81% | Real |
2013 | October | 60.9% | Real |
44.11%, Update Time: 2021-10-29 22:07 so the possibility of reaching 47.81% could happen, if it could happen then the price achieved by bitcoin could be above $70K.
So we are waiting for what will happen at the end of October, will it increase according to predictions in 2017 or will it decrease again? there are still 2 days and bitcoin is able to make that change.
The cryptocurrency market is unpredictable because anything can happen from now to Christmas. Although, bitcoin is experiencing a price correction at the moment but it may eventually recover and reach a new all-time high. There are almost three weeks to Christmas now a lot of things can happen, the price of bitcoin may even reach $100,000 when the market is fully recovered and reach new all-time highs.