syntax should be: bitcoin_hash.py wallet.dat > wallet.hash
then post here the content of the wallet.hash file, it should be a string like this: $bitcoin$96$d011a1b6a8d675b7a36d0cd2efaca32a9f8dc1d57d6d01a58399ea04e703e8bbb44899039326f7a00f171a7bbc854a54$16$1563277210780230$158555$96$628835426818227243334570448571536352510740823233055715845322741625407685873076027233865346542174$66$625882875480513751851333441623702852811440775888122046360561760525
It's useful to pass the info to hashcat in the correct syntax.
However, cracking speed seem very slow with this algorithm, so brute force is impossible (except for very short passwords). The only realistic possibility is try possible variations of the list of password you posted in the first post.
bump, can you do this Butense? I know it would be difficoult to find the password, but I want to try.
I see the 0.155 haven't moved, so nobody found the password until now