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Topic: Dice Stettings at 92% Chance - page 4. (Read 1751 times)

legendary
Activity: 1946
Merit: 1137
April 10, 2017, 02:40:54 AM
#4
So I tried this strategy at a dice site and I'm thinking of the odds of winning
So I set the chance of winning to 92% and start with minimum bet of 1000 Satoshis with profit of 76 Satoshis
Now, I could win like 9-11 times in a row, sometimes higher and lose
After losing, what would be the chance that I could lose again twice in a row?
I'm thinking of if I lose with that settings, I could go all-in with higher bet since my chance winning is higher.
What do you guys think?


i think this is a very common mistake that people make (me included) Smiley

bets that we make are completely independent on each other. your second bet has nothing to do with first and third has nothing to do with second and first and so on to the end of infinity bet.

this means with each bet you have the same chance of win or lose. you can roll the dice on 92% win chance and lose. then roll again and lose and again and again until the end of time because you simply have 8% to lose each time and it is there each time you roll the dice, it doesn't go away just because you lost once or twice or 10 times.

with that said, your strategy is what i am doing sometimes and it works sometimes and it doesn't some other times. but mostly works since the 92% win chance is big on its own.
legendary
Activity: 3108
Merit: 1290
Leading Crypto Sports Betting & Casino Platform
April 10, 2017, 01:47:48 AM
#3
So I tried this strategy at a dice site and I'm thinking of the odds of winning
So I set the chance of winning to 92% and start with minimum bet of 1000 Satoshis with profit of 76 Satoshis
Now, I could win like 9-11 times in a row, sometimes higher and lose
After losing, what would be the chance that I could lose again twice in a row?
I'm thinking of if I lose with that settings, I could go all-in with higher bet since my chance winning is higher.
What do you guys think?


The chance of losing in the next roll is 8% and stays the same for each successive roll. Just to let you know this is not a winning strategy so don't risk your money like that. As a matter of fact you can easily get 5 more losing rolls after this.
Do not complicate things so much, maybe we are just over analyze it, the real deal is you will not gonna win whatever winning percentage you will set if you want a long term goal. Simply the house edge will just ruin everything you started and will surely give you a zero in th end.
My advise is, just bet what you like and enjoy what you got for the moment as that would not last for sure.
legendary
Activity: 1372
Merit: 1000
April 10, 2017, 01:26:44 AM
#2
So I tried this strategy at a dice site and I'm thinking of the odds of winning
So I set the chance of winning to 92% and start with minimum bet of 1000 Satoshis with profit of 76 Satoshis
Now, I could win like 9-11 times in a row, sometimes higher and lose
After losing, what would be the chance that I could lose again twice in a row?
I'm thinking of if I lose with that settings, I could go all-in with higher bet since my chance winning is higher.
What do you guys think?


The chance of losing in the next roll is 8% and stays the same for each successive roll. Just to let you know this is not a winning strategy so don't risk your money like that. As a matter of fact you can easily get 5 more losing rolls after this.
legendary
Activity: 1834
Merit: 1036
April 10, 2017, 12:00:08 AM
#1
So I tried this strategy at a dice site and I'm thinking of the odds of winning
So I set the chance of winning to 92% and start with minimum bet of 1000 Satoshis with profit of 76 Satoshis
Now, I could win like 9-11 times in a row, sometimes higher and lose
After losing, what would be the chance that I could lose again twice in a row?
I'm thinking of if I lose with that settings, I could go all-in with higher bet since my chance winning is higher.
What do you guys think?
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