Topic: ENDED: FREE RAFFLE -1oz Silver XMR + CS Lichtenstein + CS1 Austria - Happy 2022! (Read 958 times)
January 15, 2022, 02:59:54 PM
Hey Kryptowerk ! I received the stamps today ! Thanks for this
January 03, 2022, 12:29:49 PM
Very cool and congrats to groswesh as well!
Thanks Kryptowerk!
Thanks Kryptowerk!
Ty !
May this entire year go on this way 
Thanks to Kryptowerk !
January 03, 2022, 02:20:43 AM
Very cool and congrats to groswesh as well!
Thanks Kryptowerk!
Thanks Kryptowerk!
January 02, 2022, 11:32:43 PM
congrats @digicoinuser and @groswesh!
and thanks @kryptowerk for the raffle!
and thanks @kryptowerk for the raffle!
January 02, 2022, 05:59:30 PM
Ok, Raffle entries are closed.
We will run the dice, starting with block 716925
https://blockstream.info/
1st win is for the stamps.
First digits were out of range (86) so we take the next block.
https://blockstream.info/block/000000000000000000011f98c21093a3a83e1ff871e2be90799c69c1ef601312
12 is winner for the stamps!
Congrats GrosWesh!
2nd win is for the coin.
We will run the dice, starting with block 716933
https://blockstream.info/First digits of this and next block were out of range (73, 70) so we take the next next block
https://blockstream.info/block/00000000000000000008ab3b842a2e2e8e430a790d0cd4cf18a2d0e365540658
58 is winner of the silver coin
Congrats Digicoinuser!
Hope I didn't make any mistake, it's quite late here and I tend to mess things up in raffles sometimes.
Winners, please send me your shipping info via DM (use privnote if possible).
We will run the dice, starting with block 716925
https://blockstream.info/
1st win is for the stamps.
First digits were out of range (86) so we take the next block.
https://blockstream.info/block/000000000000000000011f98c21093a3a83e1ff871e2be90799c69c1ef601312
12 is winner for the stamps!
Congrats GrosWesh!
2nd win is for the coin.
We will run the dice, starting with block 716933
https://blockstream.info/First digits of this and next block were out of range (73, 70) so we take the next next block
https://blockstream.info/block/00000000000000000008ab3b842a2e2e8e430a790d0cd4cf18a2d0e365540658
58 is winner of the silver coin
Congrats Digicoinuser!
Hope I didn't make any mistake, it's quite late here and I tend to mess things up in raffles sometimes.
Winners, please send me your shipping info via DM (use privnote if possible).
January 02, 2022, 02:34:33 PM
Thank you for this chance to win
60 - Buchi-88
60 - Buchi-88
January 02, 2022, 11:32:06 AM
Want to get this rolling this evening, so this is a last call!
Probably closing around 4 pm (EST) NY time / 22:00 Berlin time.
Probably closing around 4 pm (EST) NY time / 22:00 Berlin time.
Thank you for the raffle and i will take the free spot
#8 - Kaol-84
regards
January 02, 2022, 07:09:32 AM
Want to get this rolling this evening, so this is a last call!
Probably closing around 4 pm (EST) NY time / 22:00 Berlin time.
Probably closing around 4 pm (EST) NY time / 22:00 Berlin time.
January 01, 2022, 07:35:31 PM
I don't know how raffles with more than 16 but less than 256 slots are usually handled
Hi there,
usually people just take the last 2 digits of the hash of a predefined block.
That way you can easily do 100 slots.
If we look at block 716741 for example:
Hash: 00000000000000000003d05de9d3d807bf2434f88a8102a3e7283b9be2d523e9
The winner would be #39 in this case.
Interesting way of converting a number into hex first and then looking for a decimal number again nonetheless
Haha thanks. That sounds easy enough and doable.
We may still have to skip some blocks, as there are only 1 - 64 instead of 0 - 99 but I guess that shouldn't be a problem.
With this 100 Slot raffle can you also easy adjust to 20, 25 or 50 User with 5, 4 or 2 Slots for every Player without reRoll / Block skipping.
January 01, 2022, 05:13:56 PM
OP updated.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
Hi there,
usually people just take the last 2 digits of the hash of a predefined block.
That way you can easily do 100 slots.
If we look at block 716741 for example:
Hash: 00000000000000000003d05de9d3d807bf2434f88a8102a3e7283b9be2d523e9
The winner would be #39 in this case.
Interesting way of converting a number into hex first and then looking for a decimal number again nonetheless
Haha thanks. That sounds easy enough and doable.
We may still have to skip some blocks, as there are only 1 - 64 instead of 0 - 99 but I guess that shouldn't be a problem.
2 sats:
100 spots with reroll on blocks that don't hit is pretty simple.
If you want a guarantee hit on the first block with 64 you can create 4 groups of 16. Then the 2nd to last digit of the hash determines the group and the last digit determines the winner.
For example: group 1 = [0, 1, 2, 3] group 2 = [4, 5, 6, 7] group 3 = [8, 9, a, b] and group 4 = [c, d, e, f]
16 spots per group x 4 groups is 64 spots.
If we look at block 716741 for example:
Hash: 00000000000000000003d05de9d3d807bf2434f88a8102a3e7283b9be2d523e9
The winner would be group 4(e) and spot 9.
Helps to set it up this way ahead of time rather than set it up after the fact, so probably easier to just do the 100 spots with reroll, but there are other options. This format can be used for raffles with multiples of 8/16 fairly easily, just need to determine groups and spots.
geo
January 01, 2022, 04:34:09 PM
OP updated.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
Hi there,
usually people just take the last 2 digits of the hash of a predefined block.
That way you can easily do 100 slots.
If we look at block 716741 for example:
Hash: 00000000000000000003d05de9d3d807bf2434f88a8102a3e7283b9be2d523e9
The winner would be #39 in this case.
Interesting way of converting a number into hex first and then looking for a decimal number again nonetheless
Haha thanks. That sounds easy enough and doable.
We may still have to skip some blocks, as there are only 1 - 64 instead of 0 - 99 but I guess that shouldn't be a problem.
January 01, 2022, 02:17:13 PM
OP updated.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
Hi there,
usually people just take the last 2 digits of the hash of a predefined block.
That way you can easily do 100 slots.
If we look at block 716741 for example:
Hash: 00000000000000000003d05de9d3d807bf2434f88a8102a3e7283b9be2d523e9
The winner would be #39 in this case.
Interesting way of converting a number into hex first and then looking for a decimal number again nonetheless
January 01, 2022, 12:51:22 PM
Jcga - 3
Thank you Kryptowerk,
Beautifull coins you have made, do you plan to release a 2022 version of them.
Best wishes for this new year.
Thank you Kryptowerk,
Beautifull coins you have made, do you plan to release a 2022 version of them.
Best wishes for this new year.
January 01, 2022, 09:24:46 AM
OP updated.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
If you don't see yourself in the list, your slot was already taken or you didn't fulfil the requirements regarding your account (or I missed your entry - rechecking now).
Still some slots open!
Edit: I adjusted the way the slots will be drawn.. There are 64 slots. Your number will be converted to HEX. If the last 2 digits of the block are your number, you win. However there are 256-64 = 192 unused slots, so we will just use the next block and next block until a number from "01" to "40" (1 to 64 in HEX) comes up in the last two digits of the block hash.
I don't know how raffles with more than 16 but less than 256 slots are usually handled - if there is a better idea, I am willing to change it again unless all slots are already full.
January 01, 2022, 07:32:52 AM
63 debutant
HNY !
HNY !
January 01, 2022, 06:56:37 AM
16 - NeuroticFish
Happy New Year and thanks for the raffle.
Happy New Year and thanks for the raffle.
January 01, 2022, 05:46:37 AM
55 bitbollo
Thank you and HAPPY NEW YEAR!
Thank you and HAPPY NEW YEAR!
January 01, 2022, 05:10:38 AM
05 - 5tift
Happy New Year!
Happy New Year!
January 01, 2022, 04:48:11 AM
58 - digicoinuser
Happy New Year!
Happy New Year!
January 01, 2022, 02:50:27 AM
45 - Danydee
Thank you and happy new year !
Thank you and happy new year !
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