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Topic: [FREE RAFFLE][ENDED]MX12 BITCOIN ART - ERROR PIECE 715155 <-- Bitcoin Block (Read 707 times)

sr. member
Activity: 771
Merit: 283
Wow, this is reay cool. Thank you very much!
legendary
Activity: 2254
Merit: 2419
EIN: 82-3893490
congrats to Mortare! and thank you for the raffle mx12!
copper member
Activity: 1099
Merit: 452
Thanks to MX for the raffle and heisty for the surrender. Class act, both of you.
legendary
Activity: 1456
Merit: 5874
light_warrior ... 🕯️
47 - Mortare
thnx
Congratulations! / https://blockchair.com/bitcoin/block/715156

Code:
0000000000000000000922d4a49229937d096d49bfe39cd9d22bd567e7a8ac47
copper member
Activity: 731
Merit: 309
Got it thanks! Please let me know if you are okey Heisty with re-roll
Noorman0 forgot to mention that if the winning number does not match any number that was chosen by one of the participants, then the winner is determined by the means of the next block, (and so on until a winner is found). Anyway, you should probably wait for heisty's answer, (wouldn't he mind) since this is a free giveaway and only you have the right to decide how the winner is selected, unless of course you are talking about another prize drawing  Wink

Yep, cool with me!

Bitcoin Block 715155



 Bitcoin Block 715,155
00000000000000000005361522a4ae9050cfda787f635c12f26be14d5ba73288
 No winner
Next Bitcoin Block ...
copper member
Activity: 386
Merit: 8
Got it thanks! Please let me know if you are okey Heisty with re-roll
Noorman0 forgot to mention that if the winning number does not match any number that was chosen by one of the participants, then the winner is determined by the means of the next block, (and so on until a winner is found). Anyway, you should probably wait for heisty's answer, (wouldn't he mind) since this is a free giveaway and only you have the right to decide how the winner is selected, unless of course you are talking about another prize drawing  Wink

Yep, cool with me!
legendary
Activity: 1456
Merit: 5874
light_warrior ... 🕯️
Got it thanks! Please let me know if you are okey Heisty with re-roll
Noorman0 forgot to mention that if the winning number does not match any number that was chosen by one of the participants, then the winner is determined by the means of the next block, (and so on until a winner is found). Anyway, you should probably wait for heisty's answer, (wouldn't he mind) since this is a free giveaway and only you have the right to decide how the winner is selected, unless of course you are talking about another prize drawing  Wink
copper member
Activity: 731
Merit: 309
Let's say it was Bitcoin Block 715,145 00000000000000000008cfd241b914ea2e441a0529dd47c549a33220ec852a82

That means 82 is the winner.
What is taken is the last 2 digits of the hash number (letters excluded).

Got it thanks! Please let me know if you are okey Heisty with re-roll
hero member
Activity: 1778
Merit: 709
[Nope]No hype delivers more than hope
Let's say it was Bitcoin Block 715,145 00000000000000000008cfd241b914ea2e441a0529dd47c549a33220ec852a82

That means 82 is the winner.
What is taken is the last 2 digits of the hash number (letters excluded).

Another example, in case block number 715144 has hash 00000000000000000008a226f5aa338d009b2decd1e6094cc6645bfc0f9bb4fa

Then, 94 is the winner
copper member
Activity: 731
Merit: 309
Just eyeballing the script it might be the case that only numbers 1-10 were considered...  If this is what happened I'd be fine with picking a future block to ensure a fair re-roll.

If you are okey with it, we can re-roll picking up one of the next blocks, your choice BTC
copper member
Activity: 731
Merit: 309
Congratulations number 08 - heisty Smiley BTCBTCBTC You are the winner!!!

For information I used Python to find the winner:

In general, the rule of good form in such raffles is to determine the winner using a blockchain or a hash, with a predetermined condition, and not with the help of an incomprehensible screenshot, the reliability of which no one can verify.

Not that I was upset about the loss, since I always lost in such lotteries, but this technique, to put it mildly, raises doubts.

Oh,
I will create another raffle as well and use blockchain this time. I never had exp with using hash/blockchain for raffles. Can you tell me how the raffle like this work? We have 50 or 100 numbers how you will pick up the winner? Let's say it was Bitcoin Block 715,145 00000000000000000008cfd241b914ea2e441a0529dd47c549a33220ec852a82



worth noting is that the spot "00" was also included so a range of 1-51 would exclude that individual as well.  This was really 51 participants and only 9 were actually in the drawing.

I have recorded video as well, the screenshot is only example.

import random
print(random.randrange(0,50))
legendary
Activity: 2254
Merit: 2419
EIN: 82-3893490
worth noting is that the spot "00" was also included so a range of 1-51 would exclude that individual as well.  This was really 51 participants and only 9 were actually in the drawing.
legendary
Activity: 1092
Merit: 1125
If you put the following Code into a Python interpreter

import random
print(random.randrange(1,10))

then you will print a random integer (a full number) from 1 to 9.
The 1 is included and the 10 isn't.
I also think that's a bit "unconventional" for a raffle with 50 people Cheesy

You could go ahead and use the following code:

import random
print(random.randrange(1,51)

This will include 1-50.
As others have mentioned before. You could also pick a bitcoin block in the future and let the last 2 digits of the hash of the block decide the winner. If its above 50, just go with the next block.
Just make sure to announce the block you chose before it is mined Wink
copper member
Activity: 386
Merit: 8
Just eyeballing the script it might be the case that only numbers 1-10 were considered...  If this is what happened I'd be fine with picking a future block to ensure a fair re-roll.
copper member
Activity: 1099
Merit: 452
Is it just me or does the random number generator only pick a number between 1 and 10.. not trying to be a bitter loser but 40 people were excluded?
copper member
Activity: 386
Merit: 8
I'll gladly accept the win but agree that the random number generator is a bit unconventional.  Thank you for hosting this raffle, I've replied to your PM.   

Happy holidays all. Grin
copper member
Activity: 731
Merit: 309
Congratulations number 08 - heisty Smiley BTCBTCBTC You are the winner!!!

For information I used Python to find the winner:

copper member
Activity: 731
Merit: 309
"IN 10 MINUTES WILL ANNOUNCE WINNER"
full member
Activity: 626
Merit: 200
Gula membunuhmu.
28-Yabes, Last spot?

Thank you
hero member
Activity: 573
Merit: 543
26 - Frank AlpenCoin
thank you
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