Suppose that we playing roulette. We put 20$ on the red and we lose. We should put 40$ at this turn. We lose again and put 80$. İf we lose this again we should put 160$.
Last turn we won and now we have 160$ profit. let's calculate;
first turn: -20 $
second turn: -40$
third turn: -80$
total = -140$.
fourth turn: +160$.
160$ - 140$ = 20$ net profit.
looks like a nice method, doesn't it?
Assume that we have lost 8 consecutive times. every lost will double the bet amount that we will put. calculate;
1. -20$
2. -40$
3. -80$
4. -160$
5. -320$
6. -640$
7. -1280$
8. -2560$
Total = -5100$
Now we have to 5120$ to make a profit at the ninth turn.
9. +5120$
5120$ - 5100$ = 20$ net profit.
We started with a small amount as 20 dollars, but if we lose 8 times, the amount will be really high to put on the bet.
It's not hard to lose eight consecutive times. I have experienced and seen many times
but if you have a lot of money and trust yourself is a very profitable and beautiful method, I've made a lot of profits with martingale and I'm still doing this method sometimes at gambling.