thanks for the clarifications...
I dont think your method is correct. This is the method I used to satisfy myself that a oplatinum ring was truly pure.
a) Weigh Ring.
b) Weigh ring under water.
This can be done by suspending the ring on a frame such that it hangs from a thread, and is imersed.
c) As an alternative to b), weigh the difference in weight between b) and a) , many scales can do this automatically.
Either way, you have the in air weight , and the loss of weight from imersion in water, c.
Hmm. I think this is what I did, no? What's the difference?
His test relies on more implied concepts of physics. Mainly Archimedes's bouyancy principles. This helps to get rid of errors in weighing or measuring the volume of the displaced water.
My method also used the bouyancy principle and find the volume of the coin by "weighing" the displaced water. I also suspend the coin from a thread. I don't see how his method differs at all from what I did, practically. Am I overlooking something?
Well, for a start at no point does the weight of the beaker of water go on the scales. Your photograph seems to show the beaker of water on the scales. The point about these small scales is they are very accurate for small masses, less so for larger masses. Especially so as regards repeat readings which of course is what counts. Partly its a percentage thing. So its much better to not weigh large weights as far as you can. My method does involve weighing a wire frame so that you can weigh under the scales (and submerse the dangling object in water, which of itself is never weighed. You could use a 100 ton bucket of watter when weighing a 10g coin, and it would make no difference.
Sounds great, I'd love to be able to do that. I understand your point about the accuracy deteriorating with higher weight and I'd like to avoid that.
Can you maybe find or produce a drawing of that frame and the other stuff? I'm still having problems. The setup I come up with in my mind has other problems... I'm probably thinking too complicatedly.
I think you are displacing the water out of the contain. There is an acuracy problem with this, and that is that surface tension may result in inconsistent results. Its inherrently sticky, and a few drips more or less may splut out as you do it. Any amount of grease or detergent on the object may also change the surface tension and that is worse. You may say its a trivial amount, but the point is, its multiplied by the comparatively large area of the top of the beaker. So it ends up as quite a bit.
I'm not sure what you mean by "you're displacing water out of the cointainer". No water leaves the container (except after the measurement is complete and I remove the coin some drops stick to the coin of course). I'm weighing the container with the water first (resetting scale to 0), then I'm submersing the coin hanging it from the string (so it doesn't touch either the floor of the container of the top of the water). The scale then shows the weight of the displaced water. (Actually I did it a little differently: For resetting the scale I put the coin (attached to the string but not hanging from it) into the container (so it's laying on the ground of the container). Scale shows zero at that point. Then I lift it up while keeping it submerged to it doesn't touch the ground or surface. That's why the scale show a negative value in my shot (the weight of the displaced water minus the weight of the coin)).