Topic: I need a maths genius - page 2. (Read 847 times)
I believe the answer is -72.You multiply the numbers in bracket first and you get -6.Taking its square would cancel minus and we get -6 x -6= 36.Multiply it with -2 and you have answer.
This requires no genius..
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
3rd and 4th are from left to right.
I thought it didn't matter, *shrugs*
18 * 3 / 3 * 2 = 36 ; going left to right.
18 * 3 / 3 * 2 = 9 ; (18 * 3) then dividing it by the (3 * 2).
This requires no genius..
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
3rd and 4th are from left to right.
I thought it didn't matter, *shrugs*
This requires no genius..
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
3rd and 4th are from left to right.
This requires no genius..
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
2(2x-3)^2
2(4*x*x-9)
8x*x-18
Bedmas..
1s) Brackets
2d) Exponents
3rd order doesn't matter( Division/Multiplication
4th, order doesn't matter) addition/Subtraction.
2(2x-3)^2
2(4*x*x-9)
8x*x-18
What do I do first here,
-2(2x-3)^2
Do I distribute or do I square the bracket first.
-2(2x-3)^2
Do I distribute or do I square the bracket first.
Well -- .... this is something BASIC for anyone who is doing math ...
1st - brackets " ( ) "
2nd - of roots and exponentiation
3rd - * and /
4rd - + and - ...
So... in this case
1st : 2x-3
2nd : (2x-3)^2
3rd : -2 * (2x-3)^2 ...
What do I do first here,
-2(2x-3)^2
Do I distribute or do I square the bracket first.
-2(2x-3)^2
Do I distribute or do I square the bracket first.
Too early on a Sunday morning for this, so I placed it into Wolfram Alpha.
Check here for the results: http://www.wolframalpha.com/input/?i=-2%282x-3%29%5E2
Look at the step-by-step solution under the expanded form section.
Hope that helps!
this helped a lot, thanks
What do I do first here,
-2(2x-3)^2
Do I distribute or do I square the bracket first.
-2(2x-3)^2
Do I distribute or do I square the bracket first.
Too early on a Sunday morning for this, so I placed it into Wolfram Alpha.
Check here for the results: http://www.wolframalpha.com/input/?i=-2%282x-3%29%5E2
Look at the step-by-step solution under the expanded form section.
Hope that helps!
What do I do first here,
-2(2x-3)^2
Do I distribute or do I square the bracket first.
-2(2x-3)^2
Do I distribute or do I square the bracket first.
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