Maybe not all users are familiar with your terms so I will quote them here.
It looks like stealing from players.
At the top on house edge of
9.22% they will take additional 30% from your win.
Q.: How much do you pay out of 100%?
A.: We pay out approximate ~ 75 % (most lotteries are paying 40-60%)
For example winorgohome won 5.25
BTC and he was paid only 4
BTC and 0.5 was split among users so they put 0.75
BTC into their pockets.
Well, this should be easy to figure out. He wagered 0.0000005
BTC and won 4
BTC. He had to hit a perfect 6/6 which should be [6/49 x 5/48 x 4/47 x 3/46 x 2/45 x 1/44] = 1/13983816. So he will lose, on average, .0000005
BTC 13983815 times and win 4
BTC 1 time. So he will lose 6.9919075
BTC to win 4
BTC. So, if he wagers 6.991908
BTC, he will walk away with 4
BTC (on average). So the house edge appears to be ~42.79%. Please let me know if I screwed up any of the math and I'll of course correct it.
EDIT: Sorry, I neglected to factor in the 4/6 and 5/6 payouts.
4/6 on a 50sat bet pays out x125 = .0000625
BTC5/6 on a 50sat bet pays out x1500 = .00075
BTCYou'll hit 4/6 in ~.096862% of your games.
You'll hit 5/6 in ~.001845% of your games.
So, in the 13983816 games you'll play, you will hit 4/6 ~13545 times. Each time you'll get .0000625
BTC, so that's .84656274087
BTC.
In the 13983816 games you'll play, you will hit 5/6 ~258 times. Each time you'll get .00075
BTC, so that's .1935010539
BTC.
So 4
BTC + .84656274087
BTC + .1935010539
BTC = ~5.04
BTC. So you will wager 6.99
BTC and get 5.04
BTC returned, for a house edge of ~27.89%.