However, I would like to add that if you make this bet, your pot-odds are 1:5 or what is the same for every 100 times you bet, you will have losses of $ 4* it if you are lucky enough to win 1 time. (Prize $16)
Yeap, this is what EV shows by itself. The problem of any lottery is always the fact that it has negative EV, without it any lottery would disappear very fast
Difference is -0.4 USD per very your bet
*Difference is -0.04 USD per very your bet
Just add that it is 0.04, anyway thanks for the calculation.
Yeah, i just forgot about one zero, my bad. sometimes happens
Instead of betting in this kind of lottery in which i don't know what this call,I rather bet in Real lottery in which i can bet for 40 cents per number combination.
In this case at least i know that i have waiting for huge winning because it seems that the chance to win on them both are the same.
and besides in gambling like this in which Luck is the best weapon?i will choose the bigger winning .
Real lottery very close EV. I don't remember correct rules, but as i understand there 6 digits to imagine. This is 10^6 combinations (first digit this is from 0-9, second also can be any 0-9 and up to 6), and you need to guess
at least 3 numbers. This will be C(6, 3) = 20 (this is in case if order of numbers doesn't matter) and also we have 3 slots which can be any numbers (this is 10^3).
So the result = ( 20 * 10^3) / 10 ^ 6 =
0.02Yep, a little better (in 2 times) but with the reward for 3 numbers i doubt that EV will be positive.