Topic: [LUCKY HEX] - Bet 0.1 for a 1/8 chance to win 770%!!! (Read 2898 times)
Grats to 1Az5sgYz! I am delighted to say that it's not me this time... But I have already made a few more bets
1Az5sgYz... wins with 3a6cebd165...
Wouldn't P be 2 since either place can win. Even if they are the same we still look at them and each one can win even though we aren't increasing the payout.
Nah. I hear ya, but that is why there is an "n" in the top right too. "n" places to win on, but only "P" gets paid... so if all "n" places turns out to be the identical number, only "P" times will the jackpot be paid. In this case, it's 2 minus 1. Out of the 2 spots, only 1 gets paid at any given time, even if both spots have the same winning hex.
I spent over 35 minutes figuring out a formula that is scalable. Feel free to play with the numbers, you'll see it works for all base numbers and paid places!! (I'm pretty proud of that)
Try these numbers:
base 10 [0 - 9], 2 spots, 1 paid = 19:100 (1 in 5.26)
base 8, 2 spots, 1 paid = 15:64 (1 in 4.27)
base 16, 3 spots, 1 paid = 46:4096 (1 in 89)
base 2 [binary], 3 spots, 1 paid = 4:8 (1 in 2)
base 16, 2, 2 = 32:256 (1 in 8 for single payout, 1 in 256 for double payout)
It works. The formula. I do think it's easier to just pay out for any one instance.
No, just acknowledging it is fine. The odds are still pretty good.. 1 in 8.26, just be exact. :p
Sorry, right now I have a headache so bad my vision is going blurry...so excuse the present dumbness but:Wouldn't P be 2 since either place can win. Even if they are the same we still look at them and each one can win even though we aren't increasing the payout.
No, just acknowledging it is fine. The odds are still pretty good.. 1 in 8.26, just be exact. :p
bitlotto, are you going to answer my previous post? What happens, in the rare case that, both numbers match the TX first digit? There's only 1 in 256 chance of that happening.
Right now, its still .77 even if both "rolls" are what you need. I could change that I guess but the .77 would have to go down... Do you think it's worth changing?
bitlotto, are you going to answer my previous post? What happens, in the rare case that, both numbers match the TX first digit? There's only 1 in 256 chance of that happening.
19h6Y2... wins .77 with tx of efa19645de... because next block has 1, e at the end.
I feel slightly guilty here
. I had put in a couple of more bets and have won again! Are you doing that all by hand or do you have it automated? Seems like a lot of work. Can't you integrate it into your bitlotto website?
19h6Y2... wins .77 with tx of efa19645de... because next block has 1, e at the end.
I feel slightly guilty here
. I had put in a couple of more bets and have won again! Are you doing that all by hand or do you have it automated? Seems like a lot of work. Can't you integrate it into your bitlotto website?
What happens if BOTH hexes match the tx (transaction) number? Is there a double payout? Hmm? 
You have two chances to match your hex.
I think your math is off, but it might be in error of the player, so I won't press the matter.
EDIT:
Your math is in error of the house... when both hex digits match! (because I assume there is no double payout)
The real formula is therefore:
(n * ß) - (n - P)
----------------------
ßn
ß = base number system (# digits in system),
n = number of "places" player can win in,
P = number of paid matches. [say if all "places" match, how many times do you get paid?]
So, if we plug in the numbers, and then simplify, we get....
(2 * 16) - (2 - 1) 31 1
------------------- = ----- = -----
162 256 8.26
Just curious, how is this a 1/8 odds?
2 * 1/16 = 1/8You have two chances to match your hex.
I think your math is off, but it might be in error of the player, so I won't press the matter.
EDIT:
Your math is in error of the house... when both hex digits match! (because I assume there is no double payout)
The real formula is therefore:
(n * ß) - (n - P)
----------------------
ßn
ß = base number system (# digits in system),
n = number of "places" player can win in,
P = number of paid matches. [say if all "places" match, how many times do you get paid?]
So, if we plug in the numbers, and then simplify, we get....
(2 * 16) - (2 - 1) 31 1
------------------- = ----- = -----
162 256 8.26
19h6Y2... wins .77 with tx of efa19645de... because next block has 1, e at the end.
And now trying two more times, someone has to bankrupt bitlotto
LOL. Done. I'm pretty much broke. My % for all my stuff is pretty much so low right now I just have enough to pay hosting/domain etc. If my games get big one day hopefully I have a tiny bit to spare.
And now trying two more times, someone has to bankrupt bitlotto
14HHEY... wins with tx b40bfae0df... because next block ended in 0, b
Oh nice!! I just won 0.77 BTC!!! Thanks bitlotto!
14HHEY... wins with tx b40bfae0df... because next block ended in 0, b
Put in 3 too. Hopefully i'll go 3/3 ? (: hahah, ridiculously lucky there
Just curious, how is this a 1/8 odds?
Just curious, how is this a 1/8 odds?
I'm guessing your bets were in Block 135727. They lost!
Next block was Block 135763 and it ended in 0,1
None of the inputs had a 0 or 1 as the first digit.
O duh. THanks for the clarification, don't know how I managed to overlook that fact
Why is it 1/16? Sorry if I'm missing something obvious
Hex has 16 characters and it's pretty much random.
Why is it 1/16? Sorry if I'm missing something obvious
Put in 3 too. Hopefully i'll go 3/3 ? (: hahah, ridiculously lucky there
Just curious, how is this a 1/8 odds?
Just curious, how is this a 1/8 odds?
2 * 1/16 = 1/8
You have two chances to match your hex.
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