The last 7 characters of a private key are a checksum.
Apart from the fact that that particular key was missing 7 characters do you have any other reason for saying this?
The reason I am asking this is because I can't think of any reason why checksum would be 7 characters! Maybe I am missing some mathematical facts but AFAIK checksum is 4 bytes and 4 bytes encoded with base58encoding will give you between 4 chars to 6 chars. 4 chars being {0, 0, 0, 0} which is equal to 1111 and 6 chars being {255, 255, 255, 255} which is equal to 7YXq9G.
I also ran some random tests
for fun and I didn't get a single 7 char!
Random rnd = new Random();
byte[] bytes = new byte[4];
for (int i = 0; i < 100000000; i++)
{
rnd.NextBytes(bytes);
var b58enc = BtcB58Encoder.Encode(bytes, true);
if (b58enc.Length == 7)
{
string result = b58enc;
}
}
Also do you have any idea how such keys missing last characters are
technically being recovered, apart from the obvious "import it in bc.i"?