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Topic: Primedice Strategy A.K.A Ultimate Puzzle (Read 18154 times)

sr. member
Activity: 462
Merit: 250
September 11, 2015, 06:25:19 AM
#54
Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.


i was trying this strategie in a long time but it lead me to a lose :/ it have a nice chance to win but it's not a safe one Wink

Hint: What are the odds off flipping heads on a coin 20 times in a row? If you can use those odds to your advantage you cannot lose
trust me you can lose with any strategie Wink if there is a safe strategie all dice site will close :p after losing all the bankroll Wink
  Or ban you  Wink
you said that from your experience because there is the third option the site turn to scam and run with all balance :p
member
Activity: 111
Merit: 100
September 11, 2015, 06:14:35 AM
#53
Here.... 95.3*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2= about one Bitcoin.
You guys can figure out the rest
member
Activity: 111
Merit: 100
September 11, 2015, 05:57:19 AM
#52
Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.


i was trying this strategie in a long time but it lead me to a lose :/ it have a nice chance to win but it's not a safe one Wink

Hint: What are the odds off flipping heads on a coin 20 times in a row? If you can use those odds to your advantage you cannot lose
trust me you can lose with any strategie Wink if there is a safe strategie all dice site will close :p after losing all the bankroll Wink
  Or ban you  Wink
sr. member
Activity: 462
Merit: 250
September 11, 2015, 05:52:37 AM
#51
Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.


i was trying this strategie in a long time but it lead me to a lose :/ it have a nice chance to win but it's not a safe one Wink

Hint: What are the odds off flipping heads on a coin 20 times in a row? If you can use those odds to your advantage you cannot lose
trust me you can lose with any strategie Wink if there is a safe strategie all dice site will close :p after losing all the bankroll Wink
member
Activity: 111
Merit: 100
September 11, 2015, 05:46:41 AM
#50
Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.


i was trying this strategie in a long time but it lead me to a lose :/ it have a nice chance to win but it's not a safe one Wink

Hint: What are the odds off flipping heads on a coin 20 times in a row? If you can use those odds to your advantage you cannot lose
sr. member
Activity: 462
Merit: 250
September 11, 2015, 05:29:53 AM
#49
Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.


i was trying this strategie in a long time but it lead me to a lose :/ it have a nice chance to win but it's not a safe one Wink
member
Activity: 111
Merit: 100
September 11, 2015, 05:24:27 AM
#48
I can win every time. If anyone is willing to pay me for the secret we can set up escrow
legendary
Activity: 1232
Merit: 1014
FPV Drone Pilot
There's no strategy in Gambling. Hope you know Cheesy  Kiss   Grin

There is major strategy in some parts of gambling.  Not in 99% payout games with posted 1% holds.


Dude, get serious. Any martingale variation is a sure loser in the long run, the house always wins

Martingale is a long-term losing strategy for those that can't wrap their heads around independent probabilities.  It's amazing how many times it's been explained yet almost daily it's presented as a possible winning strategy vs. unbeatable (unless you cheat) dice.
sr. member
Activity: 319
Merit: 250
Do a modified martingale.

Instead of betting 100, 200, 400, 800, .... until you win @ 2x.

bet 10, 10, 10, 10, 10, 20 ,20, 20, 20, 20, 40, 40, 40, 40, 40, .... until you win @ 10x.

You could guess a max lose streak of 100 before you win. So that makes 100 / 5 = 20, then (2^20)*5 = 5242880 which equals the minimum amount of Satoshi you need to bet using this technique with a starting bet of 1.
Any martingale is the same as the original x2 martingale. This method isn't 100% safe as the varience is bound to get you after playing for sometime I tried various kinds of martingale but I still ended up losing BTC. No method is safe to be honest, its a matter of time before you lose if you are lucky due to the house edge.

Its not the same as a standard martingale. In my example;

1st 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+40) = 210 win
2nd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*2)) = 170 win
3rd 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*3)) = 130 win
4th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*4)) = 90 win
5th 40 satoshi bet wins the (40*10) - ((10*5)+(20*5)+(40*5)) = 50 win

I'm basically dividing the original martingale bet by 5 giving me 5 times a chance to win instead of 1. Now the chance of winning a 10x bet is much harder then a 2x times, but you only have 1 chance to win on 2x. By splitting the bet you have a range of potential gains as compared to fixed gain.

1st 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+80) = 370 win
2nd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*2)) = 290 win
3rd 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*3)) = 210 win
4th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*4)) = 130 win
5th 80 satoshi bet wins the (80*10) - ((10*5)+(20*5)+(40*5)+(80*5)) = 50 win

As you can see as the lose streak increases the win range increases also.

legendary
Activity: 3038
Merit: 4418
Crypto Swap Exchange
Do a modified martingale.

Instead of betting 100, 200, 400, 800, .... until you win @ 2x.

bet 10, 10, 10, 10, 10, 20 ,20, 20, 20, 20, 40, 40, 40, 40, 40, .... until you win @ 10x.

You could guess a max lose streak of 100 before you win. So that makes 100 / 5 = 20, then (2^20)*5 = 5242880 which equals the minimum amount of Satoshi you need to bet using this technique with a starting bet of 1.
Any martingale is the same as the original x2 martingale. This method isn't 100% safe as the varience is bound to get you after playing for sometime I tried various kinds of martingale but I still ended up losing BTC. No method is safe to be honest, its a matter of time before you lose if you are lucky due to the house edge.
legendary
Activity: 1344
Merit: 1000
Losing streaks will destroy your bankroll.
It is not uncommon to face losing streaks of more than 10 times in dice.
sr. member
Activity: 319
Merit: 250
Do a modified martingale.

Instead of betting 100, 200, 400, 800, .... until you win @ 2x.

bet 10, 10, 10, 10, 10, 20 ,20, 20, 20, 20, 40, 40, 40, 40, 40, .... until you win @ 10x.

You could guess a max lose streak of 100 before you win. So that makes 100 / 5 = 20, then (2^20)*5 = 5242880 which equals the minimum amount of Satoshi you need to bet using this technique with a starting bet of 1.
hero member
Activity: 546
Merit: 500
Trying to revive this thread rather than start a new one.

Anyone care to share their "winning" dice formulas?

there is no winning formula on dices.

Maybe leave while in profit?

Exactly that.. It's just a matter of luck. Sure you can try to 'minimize' your risk but the longer you play the bigger the risk. So be lucky and quit while ahead.
sr. member
Activity: 379
Merit: 251
Like what others have said, there is no strategy.  Tongue
newbie
Activity: 56
Merit: 0
Since its all from the faucet, i propose you put it on 50% chance and roll twice and then withdraw
remember......... you only live once
legendary
Activity: 1876
Merit: 1005
February 22, 2015, 03:45:56 AM
#39
Just another useless thread.

There is no strategy that works, period
It is your luck or just good day you win from betting sites. I do agree with you strategy or bot such thing doesn't work 100%.
hero member
Activity: 490
Merit: 500
February 22, 2015, 02:59:01 AM
#38
Dude, get serious. Any martingale variation is a sure loser in the long run, the house always wins
sr. member
Activity: 266
Merit: 250
February 22, 2015, 02:43:18 AM
#37
Here's the only strategy guaranteed to win.....

Ready for it?

Here it is....


...don't play.
member
Activity: 98
Merit: 10
Mine hard!
February 21, 2015, 04:21:44 PM
#36
Its even more stupid than trying to find a "strategy" for dice. Might as well try looking into "beating roulette" while you are at it.

I like a challenge: http://www.wikihow.com/Practice-Roulette-Strategy

Not so surprisingly, Martingale shows up first in the list, with a disclaimer, of course.

Tips:
This strategy is a short-term winning strategy only. It is like all systems still an act of gambling - you are gambling that you will win a small amount before you lose a huge amount. Get out with your winnings (or losses) before you regret it.

Warnings:
Like all betting strategies, in the long run the math is against you. This way of playing (aka "Martingale") will be successful only in the short term. Yes, you will see it work say, 9 times out of 10, but the winnings from your 9 successful session will not cover your losings from the 1 losing session you are bound to come across sooner or later. Casinos always have the edge on your money rather than the other way around. Statistically, this is like selling a lottery ticket. You have a large chance of a small win (the selling price of a losing ticket), but a small chance of a big loss (owing the holder of a winning ticket).

The Martingale System only works if there is no upper table limit. An upper table limit means that, in the long run, you WILL end up with less money than you started.

Even if there isn't a betting limit, and if you have an infinite credit limit, it still doesn't really work, it just doesn't really fail either. If the martingale strategy is continued indefinitely and without regard to betting limits, your bankroll will hit arbitrarily high positive and negative values. The expected value is still negative, but the variation is so high that it your bankroll won't stay either negative or positive.
sr. member
Activity: 385
Merit: 250
February 21, 2015, 04:09:36 AM
#35
The strategy to play dice games are feeling that ur luck is on 99% rather than skill
This a provably games so its hard to predict
Just be patient and use ur luck
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