By dividing, you can increase the number of public keys in comparison to other methods. I don’t think anyone would ever give you the whole formula to do it correctly.
Definitely Yes ! No on not know exact.
This is some my trying's:
https://bitcointalksearch.org/topic/m.57386530Just FYI, for my 2 cents, if you know the range a key lies in, or want to gamble and take a chance where you think the key may lie, then I think subtraction is better.
Like I said a few posts back; we will take #120 puzzle for example. The private key can only start with 1 of 8 possibilities: 8, 9, A, B, C, D, E, F
Let's say you think it starts with C. You can then take the pubkey and subtract by C00000000000000000000000000000. Let us now say for example purposes the private key is:
C23BD97E765A75F0D6D4A6C6B67221.
So for your search range, after subtracting the C000....would be 0:FFFFFFFFFFFFFFFFFFFFFFFFFFFFF
By subtracting, you went from a search range of 2^120 to 2^116; 16 times smaller the original search range. BUT if you guessed wrong and the key does not start with C, then you will not find the key.
Staying with the same example, if you thought it started with C, D, E, or F and you subtracted by C000....then you could search the range of:
0:3FFFFFFFFFFFFFFFFFFFFFFFFFFFFF, and now you've went from 2^120 down to 2^117, 8 times smaller. BUT again, if the key does not start with C, D, E, or F, you won't find the key.
Dividing is fascinating because in your mind you see a much smaller search range, BUT the amount of pubkeys you have to search GROWS the smaller you cut the search range.
So I understand you subtract C00000000000000000000000000000 from 02CEB6CBBCDBDF5EF7150682150F4CE2C6F4807B349827DCDBDD1F2EFA885A2630 the public key for 120 and for example if you wanted to search F then you would subtract F00000000000000000000000000000 from 120 public key? and then search the same range 0:FFFFFFFFFFFFFFFFFFFFFFFFFFFFF
Correct.
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i was thinking last night that we treat each keyspace as if they were separated by a wall but they are not so i measured the distance between 115 and the center of 60 then reduced the public key of 115 by that amount. i hit the 115 public key ( i scanned a thru f on 60 and about one hour later I got a hit. Key found privkey fc07a1825367bbc
Publickey 0242257a130fe109c25c2ca6c60af60e5849305f77370401299b63da2094ec0297 and the addition + 31464123230573851029232324144930570 . Trying it on 120 but so far no luck. i wish I had this kind of luck on 120 or the powerball lol. I have a image of the hit but don't think I can post it. The addition goes to the private key found
Awesome!
i was thinking last night that we treat each keyspace as if they were separated by a wall but they are not so i measured the distance between 115 and the center of 60 then reduced the public key of 115 by that amount. i hit the 115 public key ( i scanned a thru f on 60 and about one hour later I got a hit. Key found privkey fc07a1825367bbc
Publickey 0242257a130fe109c25c2ca6c60af60e5849305f77370401299b63da2094ec0297 and the addition + 31464123230573851029232324144930570 .
...
So the center of 60, which was what, in your calculation? so you took 115 - minus middle of 60 = x and subtracted x from original 115 pubkey, right?
And then you did a search in the 2^60 range?
I cant copy what he was do it. I was try and unsuccessful ((((((((9999. Not known start range he was reduced or end of 115 range....
Another look to dived pubkey to 2:
https://ask.sagemath.org/question/50288/multiply-the-point-by-2-1-mod-n/?answer=50743#post-id-50743https://ask.sagemath.org/answers/50743/revisions/Any worked I ideas ?