I'll take 4,7 & b
Added, thanks for participating
. You can just edit your post later with txid. 
Topic: [Raffleception] Win tickets to "The Raffle of All Raffles"! Blocks 448023&448024 - page 2. (Read 652 times)
January 13, 2017, 01:48:02 PM
Added, thanks for participating
. You can just edit your post later with txid. 
January 13, 2017, 01:47:53 PM
Sure 2 and 3 pay now?
txid: 1321fdf07f6c8cc816b3d3141ac729d8e863388299af8a9b74911a9d2909eb83
txid: 1321fdf07f6c8cc816b3d3141ac729d8e863388299af8a9b74911a9d2909eb83
January 13, 2017, 01:44:24 PM
I'll take 4,7 & b
January 13, 2017, 01:43:49 PM
I'd like two spots please. That should give me a 1/4 chance.
Great, any preference or is random fine?
January 13, 2017, 01:41:29 PM
I'd like two spots please. That should give me a 1/4 chance.
January 13, 2017, 01:35:06 PM
Winning block #:448023 - "4" counter!
Winning block #:448024 - "4" rollover to next block
Winning block #:448025 - "e" hybridsole!
Good luck!
Winning block #:448024 - "4" rollover to next block
Winning block #:448025 - "e" hybridsole!
Good luck!
January 13, 2017, 01:32:27 PM
So we are currently filling the biggest raffle in btct history right now, read more about it here.
While doing this I realize that a lot of people might not want to pay 0.0391 for a ticket when there's a 1 in 256 chance to win. So I came up with the idea of doing a raffle within a raffle - Raffleception!
So here's how we'll do it:
16 spots, classic raffle. There will be 2 equal prizes. Once this is filled we will Select two blocks and whoever has the correct characters at the end of those blocks will win one of the prizes.
The prizes: Winner and runner up will get 1 ticket each to "The Raffle of All Raffles".
Price per ticket: 0.005BTC.
Pay to this address only: 1D32LQzjyjRKCFPfeUw9xDExE6YmLkdBfB
Max spots: 3 / account.
0 - Raimonn (Paid)
1 - hybridsole (Paid)
2 - wheelz1200 (Paid)
3 - wheelz1200 (Paid)
4 - counter
5 - pmq (Paid)
6 - tman (Paid)
7 - counter
8 - Raimonn (Paid)
9 - tman (Paid)
a - pmq (Paid)
b - counter
c - Raimonn (Paid)
d - tman (Paid)
e - hybridsole (Paid)
f - pmq (Paid)
You can only win one of the prizes. So if you get 1st you do not have a chance to get a 2nd.
Please pay asap so we do not wait around with this one for too long.
While doing this I realize that a lot of people might not want to pay 0.0391 for a ticket when there's a 1 in 256 chance to win. So I came up with the idea of doing a raffle within a raffle - Raffleception!
So here's how we'll do it:
16 spots, classic raffle. There will be 2 equal prizes. Once this is filled we will Select two blocks and whoever has the correct characters at the end of those blocks will win one of the prizes.
The prizes: Winner and runner up will get 1 ticket each to "The Raffle of All Raffles".
Price per ticket: 0.005BTC.
Pay to this address only: 1D32LQzjyjRKCFPfeUw9xDExE6YmLkdBfB
Max spots: 3 / account.
0 - Raimonn (Paid)
1 - hybridsole (Paid)
2 - wheelz1200 (Paid)
3 - wheelz1200 (Paid)
4 - counter
5 - pmq (Paid)
6 - tman (Paid)
7 - counter
8 - Raimonn (Paid)
9 - tman (Paid)
a - pmq (Paid)
b - counter
c - Raimonn (Paid)
d - tman (Paid)
e - hybridsole (Paid)
f - pmq (Paid)
You can only win one of the prizes. So if you get 1st you do not have a chance to get a 2nd.
Please pay asap so we do not wait around with this one for too long.
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