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Topic: [RAFFLE][LOTTERY] MX12 BITCOIN ART - SPECIAL (Read 574 times)

hero member
Activity: 687
Merit: 562
Nobody dies a virgin… Life fucks us all.
November 16, 2022, 10:29:23 PM
#34
Thanks for the entry Geo… very kind of you!

And congrats to the winner ✌🏼
legendary
Activity: 2436
Merit: 1362
November 16, 2022, 02:21:36 AM
#33
@geophphreigh - thanks for including me in your bulk ticket but, very generous of you.

@sunnybwoy - congratulations! you got a really nice prize.

@mx12.levins - thank you for hosting this.
legendary
Activity: 1244
Merit: 1075
November 15, 2022, 07:10:20 PM
#32
Glad you are excited to get this art sunnybwoy. Will DM for more details regarding shipping.
thanks for playing everyone.

Geo
copper member
Activity: 575
Merit: 34
November 15, 2022, 10:34:43 AM
#31
Big thank you to Mopar for pointing this out & to geo for giving me this opportunity, thank you mx12 for this amazing art work that will be displayed for all to see LFG!
copper member
Activity: 731
Merit: 309
November 15, 2022, 07:09:42 AM
#30
Another way would be keep going 1 digit down the hash number until you get a 2 digit number below 50. If you use the first block the numbers would be 61, 56, 35. Winning number would be 35... whoaaaaaa must be a sign

This is also kind a interesting, going 1 digit down. I want to stick to the usual way and it's also more fun because you need to wait another block. But looks like we have winner who already won once the raffle?
copper member
Activity: 731
Merit: 309
November 15, 2022, 07:05:38 AM
#29
I would have to agree with Mopar. Single digit is good for a 16 spot raffle (0-9, a-f), but with 50 spots, you would have to take the last two digits and exclude any blocks where the last two are over 51.

Here are the blocks since the original selected block:
763,196 - 00000000000000000000758c9dc8a0e18c260d25b75ecc93035afaafa6bfdbb1 = 61
763,197 - 000000000000000000009bc854d34bff776dc53c0b587da5765ac49e69aab4eb = 94
763,198 - 00000000000000000005207ce70062b25e4d654c22cf65a1b642dbc920e7a7f0 = 70
763,199 - 000000000000000000064ebfc84a95e3fe2446e7abf6112cae5cf8ca95f53575 = 75
763,200 - 000000000000000000078efb893c59c5a381ce7bbf65c01bedc6f9524e51855a = 55
763,201 - 000000000000000000048232fcca7d559a194431c8bd8e2e3d79b73dca5dcdff = 35

Based on this 35 would be winner at block 763,201
...
35. sunnybwoy
...
Of course this is your raffle, so up to you mx12.levins.

Let us know what you decide and I will get shipping payment sent to you.
Geo

This is the way to go.
copper member
Activity: 1075
Merit: 442
November 14, 2022, 10:39:33 PM
#28
Another way would be keep going 1 digit down the hash number until you get a 2 digit number below 50. If you use the first block the numbers would be 61, 56, 35. Winning number would be 35... whoaaaaaa must be a sign
copper member
Activity: 575
Merit: 34
November 14, 2022, 09:41:44 PM
#27
 Shocked
legendary
Activity: 1244
Merit: 1075
November 14, 2022, 08:52:40 PM
#26
I would have to agree with Mopar. Single digit is good for a 16 spot raffle (0-9, a-f), but with 50 spots, you would have to take the last two digits and exclude any blocks where the last two are over 51.

Here are the blocks since the original selected block:
763,196 - 00000000000000000000758c9dc8a0e18c260d25b75ecc93035afaafa6bfdbb1 = 61
763,197 - 000000000000000000009bc854d34bff776dc53c0b587da5765ac49e69aab4eb = 94
763,198 - 00000000000000000005207ce70062b25e4d654c22cf65a1b642dbc920e7a7f0 = 70
763,199 - 000000000000000000064ebfc84a95e3fe2446e7abf6112cae5cf8ca95f53575 = 75
763,200 - 000000000000000000078efb893c59c5a381ce7bbf65c01bedc6f9524e51855a = 55
763,201 - 000000000000000000048232fcca7d559a194431c8bd8e2e3d79b73dca5dcdff = 35

Based on this 35 would be winner at block 763,201
...
35. sunnybwoy
...
Of course this is your raffle, so up to you mx12.levins.

Let us know what you decide and I will get shipping payment sent to you.
Geo
legendary
Activity: 2254
Merit: 2419
EIN: 82-3893490
November 14, 2022, 07:18:56 PM
#25
not to question your decision but usually it is the last 2 numbers in the hash - that determine the winner.

for this block, the last 2 are:

00000000000000000000758c9dc8a0e18c260d25b75ecc93035afaafa6bfdbb1

61

as you did only 50 spots is that why you used just the 1?

but then what if it had been a "4" instead of a "6"?

would "41" have been the winner or would have "1" still have been the winner?
copper member
Activity: 731
Merit: 309
November 14, 2022, 07:16:18 PM
#24
winner @2stout  00000000000000000000758c9dc8a0e18c260d25b75ecc93035afaafa6bfdbb1 yeah, makes sense.

copper member
Activity: 731
Merit: 309
November 14, 2022, 06:08:23 PM
#23
Wow.. i guess were just waiting on me now. Ill get my 10 spots paid as soon as i get home. Thanks for getting in done geo

Don’t rush. Be careful 👍 I trust you🙏 6 bitcoin blocks to go 🧡⛏
hero member
Activity: 573
Merit: 543
November 14, 2022, 04:32:48 PM
#22
Thank you geo... so generous.
Thank you mx12.
love art and this bitcointalk community.
copper member
Activity: 1075
Merit: 442
November 14, 2022, 04:20:15 PM
#21
Wow.. i guess were just waiting on me now. Ill get my 10 spots paid as soon as i get home. Thanks for getting in done geo
legendary
Activity: 2086
Merit: 1321
Bitcoin needs you!
November 14, 2022, 11:52:46 AM
#20
WOW - Thanks geo - this is an awesome gesture.
Gotta love the collectibles section of the forum  Smiley
Good luck all and thanks again geo Smiley
copper member
Activity: 202
Merit: 17
November 14, 2022, 11:24:39 AM
#19
Thank you geo for the generous offer and mx12 for the lovely artwork. Good luck to everyone!
legendary
Activity: 3570
Merit: 1959
November 14, 2022, 11:12:45 AM
#18
Love the art and would like to see this run. It has been a while since I bought out a raffle, this one seems great!  Grin

I looked through the collectibles posts over the past few days and picked out 39 members in good standing who have been active (and who don't already have a spot, or have already purchased this art). Please give all of these members one spot, and the last 40th, to me. 

I will cover shipping for the winner as well.
If the winner wishes decline the art, then we can keep rolling blocks until a winner does want to participate.

Enjoy, and let's roll this.
Geophphreigh

Geo! Thanks a million, so generous of you, appreciate it! Cool
legendary
Activity: 3276
Merit: 3537
Nec Recisa Recedit
November 14, 2022, 10:54:34 AM
#17
@geophphreigh
thank you for this generous gesture!
full member
Activity: 792
Merit: 142
November 14, 2022, 10:01:24 AM
#16
@geophphreigh you are ever thoughtful, thank you!
legendary
Activity: 3304
Merit: 8633
Crypto Swap Exchange
November 14, 2022, 09:29:59 AM
#15
@geophphreigh a very big gesture that is not self-evident
thank you!
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